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AD 20161027 期中考 6
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目前的所得稅累進稅率為：
0-520000 5%
520001-1170000 12%
1170001-2350000 20%
2350001-4400000 30%
4400001-10000000 40%
10000001- 45%
請撰寫一程式，由使用者輸入所得後計算出所得稅輸出。
sample input:
1000000
sample output:
83600
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
points)
ID: 15427 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
reshown
Oct 27, 2016
by
Shun-Po
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41
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* ** * * * * * * x=0,i=0;
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* * ** ** *** * ** * **** * * * * 0;
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}
answered
Oct 27, 2016
by
410523005
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122
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i,j,a,b,c,d,e;
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return 0;
}
answered
Oct 27, 2016
by
楊傑宇
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Hidden content!#include ** * ** * * *
#include * * *
int main()
{
** * * * ** ** * * * ***** num;
* * * * * * * * * * * ** &num);
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}
answered
Oct 27, 2016
by
610537002
(
-110
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
** * * *** * * * * * * i=0,
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* * ***** * ***** * * * if(i>=10000001)
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* * * * * *** * 0;
}
answered
Oct 27, 2016
by
410423016
(
-170
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Hidden content!#include ** ** * * *
* ** * * * ** *** ** * *
int main(int argc, char *argv[])
{
* ** * ***** * * ** * * *** i,j,n;
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* * * ** ** *** * * ** * ** * * * * ** = n*0.05;
** * * * * * * *** * if(n ** * 1170000)
* * ** ** * * ** * * * * ** * * * * **** ** ** ** * * * * * * = (n - 520000) *0.12 + 26000;
* * * * * *** *** * ** * * * if(n * ** 2350000)
* ** * * * * * ** ***** * * * ** * * * ** *** * *** = (n - 1170000) *0.2 + 26000 + 78000;
** * * * * * * **** * ** *** * if(n * * 4400000)
** ** ** * * * *** * * ** ** * * ** * * ** ** ** = (n - ******* *0.3 + 26000 + 78000 + 236000;
** * * * ** * ** * * * *** ** * * if(n *** ** *** *
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** * ** ***** * ** * 0;
}
answered
Oct 27, 2016
by
Dhgir.Abien
(
-216
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Hidden content! *** * *** * * *
int main()
{
* ** **** * * A,B,C,D,E,F;
* * * ** * * ** * ** ** * ** ** ** * *
* * ** * ** (A<=520000)
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** * * * * * ** * * *
}
answered
Oct 27, 2016
by
chen
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-102
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Hidden content!#include * * * *
#include ** * * * ** * ***
int main()
{
* *** * * * * * * num;
* * * * * * * * *** * * * * * &num);
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*** * * *** ** * **
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*** * * *
* * *** * ** * if (num >= 4400001)
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* * * * ** ** * ** * ** * * = * * * * * * * *** ** * 0.4;
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*** * * ** *** ** * **** if (num >= 2350001)
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* ** ** * * * * ** *
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* * * * *** * **
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* ** * * * ***** *
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* *** * ** *** * **
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* * * * * ** * * ** * * * ** ** *
* **** * * ** ** *** * * 0;
}
answered
Oct 27, 2016
by
610537002
(
-110
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Hidden content!** ****** * * ** * * ***
int main()
{
* *** * * * A,B,C,D,E,F;
* * * * * ** * ** * ** ** * ** * * * * * * *
if (A<=520000)
** * ** ** * * ** *
** ** ** ** * *** if (A<=1170000)
* *** ** * * * ** * ** ** ** * * * *
* * * * * ** * if (A<=2350000)
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* *** ** ** * * if (A<=4400000)
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* * * * * * if (A<=10000000)
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* * *** ** * * ** * * ** * ** ** * ***** * *** * *** **** * *** * ** * *
* *** * ** * * * **** ** *
}
answered
Oct 27, 2016
by
chen
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-102
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Hidden content!#include<stdio.h>
* * **** * * **
int main()
{
* * ** *** * * * * i;
* ** * * * ** * * *** * * a;
* * * * * * * ** * * * * * * * * * *
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* ** * * * * **
* * * * ** ** * * * * *
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{
* * * * * * ** * * *
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* * * * * *** * * *
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* * * ** * * * *
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* **** *** * ** * *
***** * * * * * if(i<=4400000)
{
* ** * * * * * * * * * * * ** * 470000;
* * * ** * ** * * ** * ** * * ** ** **
}
** * ** ** * ** * if(i<=10000000)
* * * *
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* ** * * * * * * *
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{
* * * *** ** * * * * * *** ** *
* * * * * * * * * * *** * * * * *** *** * * ** *
}
*** ** ** * * ** * 0;
answered
Oct 27, 2016
by
jack2234567
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-190
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int in,tax;
* * * * *** * ** * * * * *** * * * ** * * * * *
* * * * * ** ** * * ** * * * * * ***
* * ** * * * * * * ** * * * * * *
* ** * ** * * * * ** * ** if(in<1170000)
* **** * *** * * * *** * * *** * ** * ** *
* * * * ** * * * ** * if(in<2350000)
* * * * * * *** * * * * * * ** * ** ** * * ** *****
** * * *** * * * * * ** if(in<4400000)
* * ** * * ** * * * *** * * * * ** * ** *** *** * *** * * * ** * * ****
* * * ** * ** ** * if(in<10000000)
* *** *** * * *** * ** * ** ** * * * * * **** * * *** * * * * * **
* ***** * * *** **** ** * *
* ** **** * * * * ** * * ****** ** * * ***** * * ** * * * * * * ** * ** ** *
* ** * * * * * * ** * * ** * * * ** * ** *** **
* * * * * * * * * * * * * * * * * * * ** *
** * * * * * ** ** * ** * * 0;
}
answered
Oct 27, 2016
by
steven0221
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answers
AD 20161027 期中考 10
[Exercise]
Coding (C)
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Oct 27, 2016
in
2016-1 程式設計(一)AD
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Available when:
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AD 20161027 期中考 9
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in
2016-1 程式設計(一)AD
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(
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ID: 15445 -
Available when:
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AD 20161027 期中考 8
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(
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AD 20161027 期中考 7
[Exercise]
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Oct 27, 2016
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2016-1 程式設計(一)AD
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AD 20161027 期中考 5
[Exercise]
Coding (C)
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Oct 27, 2016
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2016-1 程式設計(一)AD
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(
18k
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ID: 15421 -
Available when:
2016-10-27 18:30:00
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2016-10-27 21:00:00
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