1-4 Exercise 3: String details

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Please write a program, the user will enter a line of characters, then the program will calculate number of digits, alphabets and another characters.

寫一個程式 輸入一個字串，計算字串裡的數字、英文字母和其他符號的次數。

Example input:

1234567890Ancdefghijklmnopqrstuvwxyz~!@#$%^&*()_+

Example output:

digit:10
alphabet:26
other:13

 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40715 - Available when: 2018-01-04 18:00 - Due to: Unlimited
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#include <stdio.h>

int main()
{
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}
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#include <stdio.h>

int main()
{
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}
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Hidden content!
#include <stdio.h>

int main()
{
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}
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#include <stdio.h>

int main()
{
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}
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Hidden content!
#include <stdio.h>

int main()
{
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}
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prog.c: In function 'main':
prog.c:10:5: warning: 'gets' is deprecated [-Wdeprecated-declarations]
     gets(str);
     ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/cco6wl33.o: In function `main':
prog.c:(.text+0x38): warning: the `gets' function is dangerous and should not be used.
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#include<stdio.h>
#include<stdlib.h>
#include<string.h>
#define LEN 300
void main(){
          int digit=0,alphabet=0,other=0;
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}
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prog.c: In function 'Input':
prog.c:9:19: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
               s[i]=NULL;
                   ^
prog.c:13:26: warning: 'return' with a value, in function returning void
                   return -1;
                          ^
prog.c:4:6: note: declared here
 void Input(char n[]){
      ^~~~~
prog.c:20:11: warning: implicit declaration of function 'Count' [-Wimplicit-function-declaration]
           Count(s,l);
           ^~~~~
prog.c:21:18: warning: 'return' with a value, in function returning void
           return 0;
                  ^
prog.c:4:6: note: declared here
 void Input(char n[]){
      ^~~~~
prog.c: At top level:
prog.c:24:6: warning: conflicting types for 'Count'
 void Count(char n[],int l)
      ^~~~~
prog.c:20:11: note: previous implicit declaration of 'Count' was here
           Count(s,l);
           ^~~~~
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prog.c: In function 'main':
prog.c:10:19: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
               s[i]=NULL;
                   ^
prog.c:12:19: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[300]' [-Wformat=]
           scanf("%s",&s);
                   ^
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prog.c: In function 'main':
prog.c:11:19: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
               s[i]=NULL;
                   ^
prog.c:13:19: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[300]' [-Wformat=]
           scanf("%s",&s);
                   ^
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prog.c: In function 'main':
prog.c:11:19: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
               s[i]=NULL;
                   ^
prog.c:13:19: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[300]' [-Wformat=]
           scanf("%s",&s);
                   ^
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prog.c: In function 'main':
prog.c:11:19: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
               s[i]=NULL;
                   ^
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prog.c: In function 'main':
prog.c:13:19: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[300]' [-Wformat=]
           scanf("%s", &s);
                   ^
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prog.c: In function 'main':
prog.c:13:19: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[300]' [-Wformat=]
           scanf("%s", &s);
                   ^
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Hidden content!
#include <stdio.h>
#include <string.h>

int main(){
    int b,d=0,al=0,o=0;
    char a[1000];
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}
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#include <stdio.h>
#include <string.h>
int main()
{
    int digit=0,alphabet=0,other=0;
    int i,n,x;
    char a[100];
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}
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Hidden content!
#include<stdio.h>
#include <string.h>



int main()
{
    int n=0,j;
    int alphabet=0;
    int digit=0;
    int other=0;
    char word[1000];
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}
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Hidden content!
#include<stdio.h>
#include <string.h>



int main()
{
    int n=0,j;
    int alphabet=0;
    int digit=0;
    int other=0;
    char word[1000];
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}#include<stdio.h>
#include <string.h>



int main()
{
    int n=0,j;
    int alphabet=0;
    int digit=0;
    int other=0;
    char word[1000];
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}
answered by (-301 points)
0 0
prog.c:36:2: error: stray '#' in program
 }#include<stdio.h>
  ^
prog.c:36:10: error: expected '=', ',', ';', 'asm' or '__attribute__' before '<' token
 }#include<stdio.h>
          ^
commented by (4.3k points)
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