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請寫一個程式,把輸入的阿拉伯數字轉成羅馬數字輸出。

羅馬數字的規則請參考

https://zh.wikipedia.org/wiki/%E7%BD%97%E9%A9%AC%E6%95%B0%E5%AD%97

輸入說明:

會輸入一個不超過1000的正整數

輸出說明:

請將相對於輸入數字的羅馬數字輸出

輸入範例:

14

輸出範例:

XIV
[Exercise] Coding (C) - asked in 2017-1 程式設計(一)AD by (18k points)
ID: 34979 - Available when: Unlimited - Due to: Unlimited
| 2.5k views

6 Answers

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Hidden content!
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int did(char a)
{
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* ** * * * ** * * return 50;
* * * *** ** ** * return 100;
* * **** * * **** ** * return 500;
*** ***** * * * * * return 1000;
* * **** ** ** *
* * * * * * ***** * **** * 0;
}
int main()
{
*** * ** ** * int len,SUM1;
* * * * * int sum;
** * * * char s[1101];
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* * * ** * ** ** * * * **** sum = SUM1 = 0;
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}
answered by (236 points)
0 0
prog.c: In function 'main':
prog.c:5:1: error: stray '\343' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
 ^
prog.c:5:2: error: stray '\200' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
  ^
prog.c:5:3: error: stray '\200' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
   ^
prog.c:5:4: error: stray '\343' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
    ^
prog.c:5:5: error: stray '\200' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
     ^
prog.c:5:6: error: stray '\200' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
      ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[4002]' [-Wformat=]
 while(scanf("%s",&a)!=EOF)
               ^
prog.c:10:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[4002]' [-Wformat=]
 scanf("%s",&b);
         ^
prog.c:136:9: warning: implicit declaration of function 'abs' [-Wimplicit-function-declaration]
 int sum=abs(suma-sumb);
         ^~~
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
**** * * *

int main()
{
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}
answered by (215 points)
edited by
0 0
prog.c:1:1: error: expected identifier or '(' before '.' token
 .
 ^
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
** * ** ** ** * ***
int main()
{
char *th[] = { * ** * *** * * * * ** * *
char *hun[] = { **** ** * *** ** * ** ** * **** ** * ** * ****** * *** * * * * *** * **** * * * ***** * * *** * ** * * ** ** };
char *ten[] = { ** ** ** * * *** * * *** * * * * * * * ** * ** * ** **** * ** * * ***** * * * * *** * * **** * * ** * ** ** };
char *one[] = { ******* * ** ** ***** * * * ** * * *** *** * * * * * * *** ** * ** ** * * * * ** ** ** *** * ***** *** * };
int input;

while( scanf( **** * *** ** ** * * ) != EOF )
* * * ** * * * th[ * * * ], hun[ * ** * ], ten[ ** * ], one[ ** * ] ); ****
* ** 0;
}
answered by (100 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
*** ** ** * *****


int main()
{
char * * = { ** ** * ** * ** * ** * * * *** };
char * = { *** * * * * * * *** * *** * * ** * *** * * ** ** * * * ** *** ** * * * * ***** ***** * ** *** *** * ****** * *** };
char *ten[] = { *** ***** * * ** * * * * * **** * ****** ** **** *** * * * ** * * * **** ** ** * *** * * *** **** ** * * **** * * ** * *** };
char *one[] = { ** ** * * * **** * * * *** * ** ** * * * ***** * * * ** ***** ** * *** * *** ***** * * * * * ** * *** ** * *** };

int input;

**** * **** * * ** * * * * * * );
printf( **** * * ******* * * thousand[ * * ** ], hundred[ * ], ten[ ** ** * ], one[ input%10 ] );

return 0;
}
answered by (174 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
** * * *****
int main()
{

* *** ** * * char * * * * = { ** * * * * * ** * * * *** * ** * ** * ** **** };
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* * * ** * int n;

* * * *** * while( scanf( *** ** ** * ** ) != EOF )
* * ** * ** printf( ** * * * ** *** * * n/1000 ], hundred[ ** * ], ten[ * ], one[ n%10 ] );

return 0;
}
answered by (160 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
0 like 0 dislike
Hidden content!
#include *** * * * *


int main()
{

** **** ** * * * ** ** thousand[2][5]={ ** *** * * * * ****** * };
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** * * * * * ** ** * * input;
**** * ** * *** * scanf( ** * * ***** * * ** &input ) != EOF )
*** ** *** * * * * **** **** ** * *** ** * ** ** ** **** * *** thousand[ input/1000 ], hundred[ (input/100)%10 ], ten[ (input/10)%10 ], one[ input%10 ] );

*** * * * * * ** * * * ** *** * 0;

}
answered
0 0
Case 0: Correct output
Case 1: Correct output
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