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請寫一個程式,把輸入的阿拉伯數字轉成羅馬數字輸出。

羅馬數字的規則請參考

https://zh.wikipedia.org/wiki/%E7%BD%97%E9%A9%AC%E6%95%B0%E5%AD%97

輸入說明:

會輸入一個不超過1000的正整數

輸出說明:

請將相對於輸入數字的羅馬數字輸出

輸入範例:

14

輸出範例:

XIV
[Exercise] Coding (C) - asked in 2017-1 程式設計(一)AD by (18k points)
ID: 34979 - Available when: Unlimited - Due to: Unlimited
| 1.9k views

6 Answers

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Hidden content!
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int did(char a)
{
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* * * ***** * ** if(a=='X') return 10;
** * ** * ** **** * ** return 50;
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* **** * *** * return 500;
* ** ****** *** ** * return 1000;
* ** * ** * * *
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}
int main()
{
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** * * * int sum;
* * ** ** **** char s[1101];
* * ** ** * **** ** * * * ** **
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* ** * * * ** len = * *
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}
answered by (236 points)
0 0
prog.c: In function 'main':
prog.c:5:1: error: stray '\343' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
 ^
prog.c:5:2: error: stray '\200' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
  ^
prog.c:5:3: error: stray '\200' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
   ^
prog.c:5:4: error: stray '\343' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
    ^
prog.c:5:5: error: stray '\200' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
     ^
prog.c:5:6: error: stray '\200' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
      ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[4002]' [-Wformat=]
 while(scanf("%s",&a)!=EOF)
               ^
prog.c:10:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[4002]' [-Wformat=]
 scanf("%s",&b);
         ^
prog.c:136:9: warning: implicit declaration of function 'abs' [-Wimplicit-function-declaration]
 int sum=abs(suma-sumb);
         ^~~
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
* ** * * * *

int main()
{
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    return 0;
}
answered by (215 points)
edited by
0 0
prog.c:1:1: error: expected identifier or '(' before '.' token
 .
 ^
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
** ** * *** ***
int main()
{
char *th[] = { * * * * * *** ***
char *hun[] = { ***** * * ** ****** * * ** *** * * * ** * * ** ** * * * **** **** ***** * * *** * *** ** ****** * * ** ** * * };
char *ten[] = { ******* ****** * *** * **** * * ** ** ** ****** ** * * ** * ** * * * * ** ** * * ** * ** ***** **** ** * ** * ** * * * *** *** * **** };
char *one[] = { * ******** * ** *** ** * * ******* * * * * **** ** * * ** * * ***** * ** * ** * *** **** *** * ** * *** *** * * * * * };
int input;

while( scanf( * * * *** * ) != EOF )
* * * *** ** ** th[ *** * ], hun[ ** * ** ], ten[ ***** * * ], one[ ****** ] ); * *
* * 0;
}
answered by (100 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
* **** ** * * ***


int main()
{
char * * = { **** *** * * ** * * *** ** ** * *** * * * * ** ***** };
char ***** = { * *** *** * * ** ** * * * ** *** * * * * * ** * ***** * * ** * * ** * * *** ** ** *** **** * * ** ** *** * ** ** };
char *ten[] = { *** ****** * ** * * * * *** * * ** *** **** * ** * * * * *** ** ** * ** * * *** * * **** * ** * * * **** };
char *one[] = { * ** * ** * ******* ** * *** ** ** *** * ** * ** * ***** *** ** * **** * **** * * * * ** ****** * ** *** * * * ** * * * * ** * * };

int input;

** ** ** * *** **** );
printf( ** **** ******* * thousand[ * * ], hundred[ **** ], ten[ * ** * ], one[ input%10 ] );

return 0;
}
answered by (174 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
* ** *** * ** **
int main()
{

* ** ** ** char * * = { * * ** * *** * * * ** * **** * * * * };
** *** ****** char *** *** = { ** ** ** ** * ** * ** * * ** ** ******* * ** * * * ** ** * *** ** **** * * ** * *** **** * **** ** * ***** };
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** ** * int n;

* *** while( scanf( * * ** * ***** * * * ) != EOF )
* ** * printf( ** * * * * * * *** * * n/1000 ], hundred[ * * ], ten[ * * * ], one[ n%10 ] );

return 0;
}
answered by (160 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include * *** ** *


int main()
{

***** * *** * * * thousand[2][5]={ * ** ** * * ** ** ** };
*** * * * * * ** * * *** * hundred[10][5]={ *** ****** * * ** ** * * * ** * * * * ** * * * ** * * * * ** * * ** * * * * * * *** **** ** ** * * };
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* * ** *** * * ** * input;
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* * ** * *** * *** ** **** *** * * **** ** ** *** * *** thousand[ input/1000 ], hundred[ (input/100)%10 ], ten[ (input/10)%10 ], one[ input%10 ] );

*** * ** ** ** * * * * * * 0;

}
answered
0 0
Case 0: Correct output
Case 1: Correct output
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