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請寫一個程式,把輸入的阿拉伯數字轉成羅馬數字輸出。

羅馬數字的規則請參考

https://zh.wikipedia.org/wiki/%E7%BD%97%E9%A9%AC%E6%95%B0%E5%AD%97

輸入說明:

會輸入一個不超過1000的正整數

輸出說明:

請將相對於輸入數字的羅馬數字輸出

輸入範例:

14

輸出範例:

XIV
[Exercise] Coding (C) - asked in 2017-1 程式設計(一)AD by (18k points)
ID: 34979 - Available when: Unlimited - Due to: Unlimited
| 1k views

6 Answers

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Hidden content!
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int did(char a)
{
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* * * ** * ** ** * ** return 500;
* * * * ******** **** return 1000;
* *** ** * *
* ** *** ******* ** 0;
}
int main()
{
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* * ** int sum;
* ** ** * ** char s[1101];
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}
answered by (236 points)
0 0
prog.c: In function 'main':
prog.c:5:1: error: stray '\343' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
 ^
prog.c:5:2: error: stray '\200' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
  ^
prog.c:5:3: error: stray '\200' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
   ^
prog.c:5:4: error: stray '\343' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
    ^
prog.c:5:5: error: stray '\200' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
     ^
prog.c:5:6: error: stray '\200' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
      ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[4002]' [-Wformat=]
 while(scanf("%s",&a)!=EOF)
               ^
prog.c:10:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[4002]' [-Wformat=]
 scanf("%s",&b);
         ^
prog.c:136:9: warning: implicit declaration of function 'abs' [-Wimplicit-function-declaration]
 int sum=abs(suma-sumb);
         ^~~
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
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{
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}
answered by (215 points)
edited by
0 0
prog.c:1:1: error: expected identifier or '(' before '.' token
 .
 ^
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
**** * * * *** *
int main()
{
char *th[] = { * *** ** *** ** ** * *
char *hun[] = { ** ** ** * ***** ** * * ** ** ** ******** * * **** * * ***** ** *** ** * ** * * * ** * * * ** *** * ** * * ** };
char *ten[] = { * ** * * * **** *** * * * * *** ******** * ** * ** ** *** *** ** * * * ** *** * * * * * * *** * * ** * ** * * ** };
char *one[] = { ** * * ** * * * * * * * ** * * ** ** *** ** * * ** *** ** ** ******* ** * ** * ************** * * * *** ** *** ** };
int input;

while( scanf( ** **** ** * ** ) != EOF )
* ** * *** * ** * * th[ * * ], hun[ ** ** * ], ten[ ** * ], one[ ** * ] ); * **
* * 0;
}
answered by (100 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* ** * * *** ** ***


int main()
{
char *** = { * * ** *** ***** * * **** * ** * ** ** *** ** ** };
char * * * = { * *** *** * * ** * * *** * ** * ** *** *** **** ** * * * *** ** * ** * * * *** * * * * * * * * ** * * * ***** * * * ** ** * * };
char *ten[] = { * ** * ** * * * ** ** * ** *** **** **** * * * * ** ** * * ** ** * * * * * *** ** * **** * **** * ** * ** *** ** **** * **** };
char *one[] = { * * * *** * *** * * * ** ******** * * * **** ** * **** *** * ** * *** ** * ** * * * * ***** **** ****** * * * * * ** };

int input;

* * * ******* ** ** * );
printf( * ** *** * * ** thousand[ * **** ], hundred[ ** * ], ten[ *** *** ** ], one[ input%10 ] );

return 0;
}
answered by (174 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
* * ** **** * ***
int main()
{

* ** * *** char * = { * ***** ** * ** * * * ** * * * * *** * };
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* * * * int n;

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* *** * ** * printf( * * ** * ****** ** * n/1000 ], hundred[ *** ], ten[ * ], one[ n%10 ] );

return 0;
}
answered by (160 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
#include ** * * **


int main()
{

** * * * *** ** thousand[2][5]={ ** *** * ** *** **** * * };
*** ** * * * **** ** ****** hundred[10][5]={ * * * *** ********* * ** ** * * ** * * ** * * * * ** ****** * * ** *** * ** *** *** **** *** ** ** * * * ** * ** };
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* * * * * ** * * * *** * * * ** * ** * *** *** *** thousand[ input/1000 ], hundred[ (input/100)%10 ], ten[ (input/10)%10 ], one[ input%10 ] );

* **** * * ** * ** 0;

}
answered
0 0
Case 0: Correct output
Case 1: Correct output
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