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請寫一個程式,把輸入的阿拉伯數字轉成羅馬數字輸出。

羅馬數字的規則請參考

https://zh.wikipedia.org/wiki/%E7%BD%97%E9%A9%AC%E6%95%B0%E5%AD%97

輸入說明:

會輸入一個不超過1000的正整數

輸出說明:

請將相對於輸入數字的羅馬數字輸出

輸入範例:

14

輸出範例:

XIV
[Exercise] Coding (C) - asked in 2017-1 程式設計(一)AD by (18k points)
ID: 34979 - Available when: Unlimited - Due to: Unlimited
| 3.3k views

6 Answers

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Hidden content!
* * * * ** *****
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int did(char a)
{
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*** * * * ** if(a=='X') return 10;
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***** ** *** *** return 100;
* ******** ** *** * * return 500;
* *** * *** * ** * ** * return 1000;
**** ** * * * **
* * ** * * * ** ** 0;
}
int main()
{
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***** * ** int sum;
***** * * char s[1101];
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* * * ** ** * * * sum = SUM1 = 0;
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}
answered by (236 points)
0 0
prog.c: In function 'main':
prog.c:5:1: error: stray '\343' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
 ^
prog.c:5:2: error: stray '\200' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
  ^
prog.c:5:3: error: stray '\200' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
   ^
prog.c:5:4: error: stray '\343' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
    ^
prog.c:5:5: error: stray '\200' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
     ^
prog.c:5:6: error: stray '\200' in program
 \xe3\x80\x80\xe3\x80\x80char a[4002],b[4002];
      ^
prog.c:6:15: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[4002]' [-Wformat=]
 while(scanf("%s",&a)!=EOF)
               ^
prog.c:10:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[4002]' [-Wformat=]
 scanf("%s",&b);
         ^
prog.c:136:9: warning: implicit declaration of function 'abs' [-Wimplicit-function-declaration]
 int sum=abs(suma-sumb);
         ^~~
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
* ** * * ** *

int main()
{
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}
answered by (215 points)
edited by
0 0
prog.c:1:1: error: expected identifier or '(' before '.' token
 .
 ^
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
** * ** * **
int main()
{
char *th[] = { ** ** ** * ** * *** * **
char *hun[] = { * **** ** * ** ** **** * * ** * ** ** * * * * * * * ** ***** * * * * * *** * *** *** *** * ** * * * ** * ** * ** * * * * **** ** };
char *ten[] = { * **** *** * **** ** * * ** ***** ** ** ** ****** * * *** * ***** * * * **** * * ** * * * ** * * **** *** * ** * };
char *one[] = { **** * * *** * * * * *** ** ** ** ** *** * * * * * * ** *** *** * ** * * * ********* * * * ******* **** * ** * * * ** *** };
int input;

while( scanf( *** * *** ** * ***** ) != EOF )
* * * *** th[ ** * ], hun[ ** * *** ], ten[ * * * ], one[ * ] ); ** * *
* * 0;
}
answered by (100 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
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Hidden content!
* * *** ** * ***


int main()
{
char ** * * = { * **** ** * ** ** * *** * ** * * };
char = { * * * ** * * ** * * * * ** * ** * ** * *** * * * ** * * * * ** *** * * ** * * * ** ** *** ** * * * **** * ** * };
char *ten[] = { * * *** *** * * ** * * * *** * *** ** * ** * **** * * * ** * ** ****** * * * ** *** * * * ** *** ** * ** * ** * * * * ** ** * * * * * * };
char *one[] = { * ** *** * * * ** * **** * * * * ** * ** ****** * * *** * ***** ** ** ** * * **** * * ** * ** *** * };

int input;

** * **** * ** ** *** );
printf( * ** * * **** ** thousand[ **** ], hundred[ ** * ], ten[ *** *** ], one[ input%10 ] );

return 0;
}
answered by (174 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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Hidden content!
** **** *** *
int main()
{

****** * *** char * * = { * * *** ** ** * * **** * * ****** ** * *** * * * ** };
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*** ** * int n;

* ** * * * while( scanf( * * * * **** * * * *** ) != EOF )
* * ** * * printf( *** * * * ***** ** *** n/1000 ], hundred[ *** * * ], ten[ ** ** ], one[ n%10 ] );

return 0;
}
answered by (160 points)
0 0
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Case 1: Wrong output
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Hidden content!
#include * *** *


int main()
{

**** * * * * ** * * thousand[2][5]={ * * * * ***** * * };
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** **** **** **** * * input;
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* *** *** **** * * * * * * * ******* ** ** *** * ** ***** * ** thousand[ input/1000 ], hundred[ (input/100)%10 ], ten[ (input/10)%10 ], one[ input%10 ] );

*** * *** ***** *** ** ** 0;

}
answered
0 0
Case 0: Correct output
Case 1: Correct output
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