[Exercise 03] Caesar Cipher Decoder

Question

You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

Answer 1

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int main(int argc, char *argv[]) {
*  *  * *** *** ***  * ** *****  lettera;
  * * * *    * *   * ***  letterz;
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      * ****  **  *   ***  *** ** * letterc;
   **** *   **  ****  *** **  letterv;
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   * ** *** ***  ** * *** ***  * ****    *** * *** ***   * *     *  ** ***   *****       ** **   *   **
* *  *       *   *  ** * * ** * * = lettera + 3;
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*****    * ** *****    = letterx + 3;
*  * ** ***    * ** **** * *  = letterc + 3;
** * ***  *  *  *** *    *  *    ** = letterv + 3;
*  *** ****  *    
*    * * ** *   * *******   ** **** *  **         **  *    **     * ** ** * **  ** 
*  *  ***    * *****
**  **   *** **** * **** *  ** 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output

---

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.

Answer 2

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int **    argc, char   *   {
  **** *  ** char     * *
***** * ***   
*      **  *** a =   ***
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** * **      *** c =  **    
* * ******  *** *  d = * **  
* *** * * ** ** e =     *  
* * * *        * 
** *  * * * *  a += 3;
* *******  ** * * b += 3;
 *     **  c += 3;
* ***** *  * **  d += 3;
***      *   e += 3;

* *    * * * ** * *  *   
  **   * *  ** *   *******
*     *   *   *   ** *** *
** *    ****     **  *
*  ** ***      *  ** * 
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*  * *    *  *** 
        *  ** **   * * ** ***  0;
}

Comments

Case 0: Correct output