[Exercise 03] Caesar Cipher Decoder

Question

You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

Answer 1

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int main(int argc, char *argv[]) {
* ** * ** ** ** **   ***** *   * lettera;
*        *     *    * ** *   letterz;
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**  *  ** ****   * **  ** * letterc;
*** ***  *    *  * * **  letterv;
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***  *** ** * ******     *   *   *** *     *   ***** *   ***  *  *  ***  *   * ** *  *****   * *  ** **    *
  **  ** ** **  *    *****   * *  = lettera + 3;
** *       * *    * ***  ***   = letterz + 3;
*    ** **  ** *  *  * **     * *  = letterx + 3;
*  ***   **   * ***** ***  ** = letterc + 3;
  *  ****  *   ** * **    *  * = letterv + 3;
  **  ****     ***
  * ** *   ****          **    *  * ****     **  *      *  *   ** ** **   *  * *
  **  **   * **  *
******** * ***  ** *** * ** *  0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output

---

Nice, it is correct. You might be wondering why your automatically-generated score is 0.
That's because it expects its output to be only 'hello'. However, what your program showed was:
     Please input the letter to encode: ebiil
     hello

Anyway, great job. Full marks.

Answer 2

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int     argc, char *  * *  {
 *  * *** * * * char * *****
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****  **   a =  * *  
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  **   *  *    *  c = ** ** 
*  * *   * * * d = * **** 
****** *  *  *  e = *** **
* * * ** *  ** ** * 
 * *  * *****   a += 3;
** * **  * *   ** b += 3;
*   *   * * c += 3;
 **  **           d += 3;
*    **** * e += 3;

  ***    **     ******
  *      *  *  * * *
*  * * **  *  *   *  
*   ** **    *   ***   
*  * *    *  *  *  ** *    
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**   *  **** 
     *  
***    ***  * * * *    * **   *  0;
}

Comments

Case 0: Correct output