[Exercise 03] Caesar Cipher Decoder

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You have received an encrypted message from Julius Caesar-- the message is ebiil.  You are asked to decipher the message in order to understand what Caesar trying to say to you.

Hint

Luckily, Caesar has given you a hint, he says: 'I, myself, encoded the message by shifting every word backwards by 3.' 

Solution

Write a program that receives 5 characters 'ebiil'. Then decode those characters into 5 new characters.

Example

#include <stdio.h>

int main(int argc, char *argv[]) {


	char a;
    	char b;
	 	
	scanf("%c%c", &a, &b);
	
	//decode the message how??
	
	printf("%c%c", a,b);
	
	return 0;
}

Input

ebiil

 

 

 

 

 

 

 

 

 

 

Output

hello

** REMEMBER ** 
This is an online-compiler, don't put anything except the codes. If you want to make a comment, please use // or /* */

[Exercise] Coding (C) - asked in Chapter 2: Syntax structure of the C language by (5.9k points)
ID: 26955 - Available when: Unlimited - Due to: Unlimited
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22 Answers

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Hidden content!
#include<stdio.h>

int main (int argc,char *argv)
{
    char a;
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}
100/100 answered by (244 points)
0 0
Case 0: Correct output
Case 1: Wrong output
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#include    *  * ** *** 
int main(int argc, char *argv[]) {


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}
100/100 answered by (221 points)
0 0
prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c%c%c%c%c", &a, &b, &c, &d, &e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("%c%c%c%c%c", a+3,b+3,c+3,d+3,e+3);
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
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0 0
Case 0: Correct output
Case 1: Wrong output
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Hidden content!
int main(int argc, char *argv[]) {


*  ** *   char a;
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}
50/100 answered by (244 points)
0 0
prog.c: In function 'main':
prog.c:10:2: warning: implicit declaration of function 'scanf' [-Wimplicit-function-declaration]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
  ^~~~~
prog.c:10:2: warning: incompatible implicit declaration of built-in function 'scanf'
prog.c:10:2: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:10:25: warning: format '%c' expects a matching 'char *' argument [-Wformat=]
  scanf("%c %c %c %c %c %c", &a, &b,&c, &d,&e);
                         ^
prog.c:12:6: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
      ^
prog.c:12:12: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
            ^
prog.c:12:18: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                  ^
prog.c:12:24: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                        ^
prog.c:12:30: warning: assignment makes integer from pointer without a cast [-Wint-conversion]
  if(a="e",b="b",c="i",d="i",e="l")
                              ^
prog.c:14:2: warning: implicit declaration of function 'printf' [-Wimplicit-function-declaration]
  printf("hello");
  ^~~~~~
prog.c:14:2: warning: incompatible implicit declaration of built-in function 'printf'
prog.c:14:2: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:18:5: warning: incompatible implicit declaration of built-in function 'printf'
     printf("errol");
     ^~~~~~
prog.c:18:5: note: include '<stdio.h>' or provide a declaration of 'printf'
commented by (4.3k points)
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Hidden content!
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100/100 answered by (183 points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
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Hidden content!
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100/100 answered
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
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Hidden content!
#include *   *** ** ** * *
#include *****  *  ***   

int main(int argc, char *argv[]) {
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}


INPUT
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OUTPUT
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100/100 answered by (243 points)
0 0
prog.c:27:1: error: unknown type name 'INPUT'
 INPUT
 ^~~~~
prog.c:30:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'OUTPUT'
 OUTPUT
 ^~~~~~
prog.c:30:1: error: unknown type name 'OUTPUT'
commented by (4.3k points)
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Hidden content!
*   ** *****  * 

int *    * argc, char *** ***  {


*  ***    * * char a;
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}
50/100 answered
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
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Hidden content!
#include *     ***** * 

int main(int argc, char *argv[])
{
*  *     *   * letterj;
 *** **     * * *   * * * *    letteri;
* * * *    * *** *** ** *   * letterm;
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***  *****  *  ** *  *  * * **  = lettere +3;
****   * *** * ** **** *** ** **  = lettern +3;
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  ** * *** ** * ** *****

 *** ***** *  *    0;
}
100/100 answered by (220 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
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Hidden content!
**** *   **   ** ******  

***  *    **  *  *    ****   {

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100/100 answered by (283 points)
edited by
0 0
prog.c:1:16: fatal error: stdio: No such file or directory
 #include<stdio>
                ^
compilation terminated.
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:6:5: error: 'cin' undeclared (first use in this function)
     cin >> a;
     ^~~
prog.c:6:5: note: each undeclared identifier is reported only once for each function it appears in
prog.c:11:5: error: 'cout' undeclared (first use in this function)
     cout << a << endl << endl;
     ^~~~
prog.c:11:18: error: 'endl' undeclared (first use in this function)
     cout << a << endl << endl;
                  ^~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char *' [-Wformat=]
     printf("%c", a)
              ^
prog.c:12:5: error: expected ';' before 'return'
     return 0;
     ^~~~~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:6:11: warning: too many arguments for format [-Wformat-extra-args]
     scanf("c", &a);
           ^~~
prog.c:11:14: warning: format '%c' expects argument of type 'int', but argument 2 has type 'char (*)[5]' [-Wformat=]
     printf("%c", &a);
              ^
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
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Hidden content!
#include  *    *  ** ** *** 
#include **   *****  *  *  *

int main(int argc, char *argv[]) {
 *  *   *   **** * ****  ** ***   letterj;
 *****   * * ** *   **  ** * letteri;
 *** ***** ** *** * ** ** *     letterm;
 *      ** **    * *  **     lettere;
*   **********  ***   * *** ***  lettern;
** *  * *   ***   * ***** 
 **   **   *        ** ** *   *   ***   input the letter to encode: *         
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 *      *   * *   
 * * * * *** *** letterj = letterj +3;
  **   * *   **    * * * * * *    *   * = letteri +3;
*    *** * *  ******* *  * * * * = letterm +3;
**    ****   *     ** * * * * = lettere +3;
   **  *  *   ** * *   ***     = lettern +3;
*** ***     * ****** *** 
*  *  * *  * ** **    **     *  ***  *  * *** ** ** *  *** ***   *** *   lettere, lettern);
  **   *** ** *  *   **
*    *      *** **** *  ****  **  0;
}
100/100 answered by (220 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
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