10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include *   * * *  *****
#include ** *  * * * * **

int water_amount;
double price=10;

int main()
{
  ****   * * *  *   ** ** ** * *    *  ****    *** **** 

* * *** *  ****   ** ** * *  *** * *     *  ** * *

 *  ***** *****  ***    * ****** *   * * * *****   * ** = price ** * *** ** ** 
** *     *  * *  ***** * **  *   * **   *  * **   *  *****   ** *  *** = water_amount - (water_amount - 60);
**  *    ***  * * ****   *  *   *
* *  **** * *  *  ***   * **    ** ***** 

* * *    * **  **** *  *  ****  **** * * *  *  ** *  *** * ***** = price +(water_amount-50)*1;
* **    * *  *   ***** **  *** * * *** *  *  * *    *    **  *   = water_amount - (water_amount - 50);
*     *   ** ****  * ***     * 
 ** ***** *** * *****   ** ** * ***   *** *

***        *   * **  * *** *  *   **   *   *  * *  ***  * ***  = price *******  *  *
 *   **  ****  *  * * *  *  * *** * ***  **** *  **   ** *  = water_amount - (water_amount - 30);
  *   ****** * * *** *  
 *   *    ***    *    ** ** ** * *****   *  **

*   * * * ***   **  *        * *    ** **  ** * * * **       **  = price +(water_amount*0.6);
 * *** *   **    *** * * * **   *** * *   ** *** *    ** * *    * = water_amount - (water_amount - 30)
 ** * * * *** ** *  *** **** 

 * ***  * * **       *   **   ***   * * price);
 *   * * ****  * *** *  * * * * ** * * 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!