10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include  *** *  *** ** 
#include   * *****  ** * *

int water_amount;
double price=10;

int main()
{
*   *  *  *  *   **   *  * *  **      *   * * * *** *******  ** **

*   * *** * * *   *  *  ****  * ** *****   ***

  **   *** ***   * *** * **  * *       **  **   **      ****    = price ***  **  ****** *
**      *    ** *   *   ****  *** ******* *  *   *** **    ***    * = water_amount - (water_amount - 60);
  ****  * * ** * *    **   *   
*  **** ****   **     ** *    * *  **  *** * *** 

* *****  * *  *  * *  ***  * **      * ****   * * *  *  * = price +(water_amount-50)*1;
 ** **  **  *   *  * *** *** * **** ** **  *     *  ****  = water_amount - (water_amount - 50);
 **   **   ***  *** ****  
  ******* * *  ** *** * * * * * *   *  * **  **

*   *  ***     * ** * ******  * *   *** * *    *****   ****** = price   ** *** *****  * *
*  *  * *   *  *   **** *  *  *  *  ** **  *** **     ** **** = water_amount - (water_amount - 30);
* *   *** **  * **  *  *** *  
**  *  *  * *  ***    *** **** *  **** **** *

******* *****  **  ** *** ** ** * * *   **  *  **      = price +(water_amount*0.6);
  * *     *****    * ***   * * * ** *** * **   **    * * *  **  = water_amount - (water_amount - 30)
   * * ** ***    *    

** *      ** **** *  *  **  * ** *  *  **   ***  price);
 * * *    *     **  *** ** * * 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!