10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include  ***  * * 
#include * *  **  **** ***

int water_amount;
double price=10;

int main()
{
 *  *    **  **   * * ** * ***    **  ******  **  * *** * ****  **

 ** ***  ** **    *  ***   *  ** * * **

***  ** ****    * * **   *    ***** **** *  * *  *  **** **  *  = price  * * * *    * ***
    * ***  **  *    *** ****  **  * ** ** * *   *     *  *  = water_amount - (water_amount - 60);
 * *    * * * *   ** ***  ** 
* * * **  * ********* **** *  *   *  *   *  *** 

**  * * ** ****** *       *    ****    *      * * **  *  *** * = price +(water_amount-50)*1;
 ** * *  *    * * ***  ****** **    * * ***   **** *    ** **** = water_amount - (water_amount - 50);
 *  **     **   *** *  *   **
   *** **  ****** ** *   *  *****    ********* *   ** 

 * * **   ******  *  ***  * **      **  * **  **** = price  *  * *  *  ** *  
 * * *      *   ***    ***   *** *    *  * * ******  *  **  * * = water_amount - (water_amount - 30);
**      *  *   *   **    ***
* * *    *** * *  ** ****** * ** ** * ****  ****  *

* * ***   ***** *****      * *  * *****  *  *  *  **    = price +(water_amount*0.6);
* * ***   * ** * **  ** * ***** *  *  *    ****** *   **  ** = water_amount - (water_amount - 30)
* ****    *   * ***     *   

*  * *    ** ** ** *******   *******  *   **    price);
**  *  * ** **  *  *  ** *** * *  * 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!