10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include      *  ** ** * *
#include  ****  * *    

int water_amount;
double price=10;

int main()
{
 *  **** *  * *   ** *   * * * ** ** **  * **         *  **

*  *         *  * *  **   * ***  ** * **** ** 

    **  ** ** ** *   *         * * *  *  ****    * * * ** *  = price *   * *** *  ****
 * * ***  *** **  * **  ***  * *** ****** *** ***  * * **  **  *** = water_amount - (water_amount - 60);
***     **  *   ***** ** *      
 * ** * *    *     **   *  *** *** **** * *    *   *

***  *  ***  *   **** * * *  ****  ********   ****  ** *** = price +(water_amount-50)*1;
  * *  ***** **   *  * *** * * * ** *  *  * ***  **** **  = water_amount - (water_amount - 50);
****     *  ** * * * * * *
*    ** * *  *    **** *    ***** ** ***   ****** *

 ****   * **   * *  *  ** **** *       *  ** *** = price ** * * *  * *** 
* ****    * *  **     **  ** * ** * * * *   *  * **** *** *   *  *** = water_amount - (water_amount - 30);
  ******   * *** *****  * * * 
****  * **     **** *    *** ** *****  * *

   ** * *  **** *  *   * *** **    *    * **** ** *****    = price +(water_amount*0.6);
** * ****  * *   *** **** ****** *    *  * *    ** *  * ** = water_amount - (water_amount - 30)
* **  *   *   ** *  * *  *   

*  **    * ** * ** *  ***  ** *** **   *  * price);
** **   **   *        *** * **   0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!