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A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 26465 - Available when: Unlimited - Due to: Unlimited

edited by | 18.3k views

91 Answers

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Hidden content!
#include ****** ** * ***
#include * ***** **** **

int water_amount;
double price=10;

int main()
{
* * ** * * ** ** *** * ** ** ** * **** ** ** **** *

* ****** * ** ** * * ***** *** ** **

* ******* * * * ** *** *** ***** ** ***** * = price * ** **** *
*** ** * ** * *** ***** ********* ***** ** = water_amount - (water_amount - 60);
***** **** ** * * ** **
* ** ** ***** * * *** ** ** ** *** ** ** *

* ** * **** ** * ** * *** * * * ** ** = price +(water_amount-50)*1;
** *** ***** ** ***** ** * * *** ** = water_amount - (water_amount - 50);
** ** *** * * * ** ** * * *
* * ** **** *** * **** ** * * *** * *

* * **** * * ** * ** * * * * ** * *** * * ** = price * ** * * **
* ** * * **** *** ** * * * * **** * ** * = water_amount - (water_amount - 30);
* ** *** * * ** * * **
***** * ***** * * ** *** ** *******

* * ** * * ***** *** * *** ** ** ** * ******* ** = price +(water_amount*0.6);
****** * *** *** * * * * * ** * * ** * ** *** = water_amount - (water_amount - 30)
**** * * ** *** * ** **

** * * * ** ******** **** **** **** ** * ** * * price);
** * * *** ** *** **** ** * * 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00
0 0
Thanks!
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