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A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 26465 - Available when: Unlimited - Due to: Unlimited

edited by | 22.5k views

91 Answers

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Hidden content!
#include *** *** ***
#include * **** *

int water_amount;
double price=10;

int main()
{
* * * ** *** * * *** *** * ***** * * *** ** * *

* *** * * *** **** ******* * * **

* * **** ** * ** *** * ** ******* * * = price ******* * *
* * * * * *** * * **** * * ** * ** *** * * ** = water_amount - (water_amount - 60);
* * *** * ***** ***
** * * ** * * * ** *** *******

* ****** * ** * * * **** ** **** * ** * = price +(water_amount-50)*1;
**** ** * * * ***** *** * *** * *********** * ****** = water_amount - (water_amount - 50);
*** ***** * * * **** *
* ** * ** ****** *** ** * * * ***

**** *** * * **** * **** * ** * * * * * = price * **** * * *
* ** * ** * ***** *** **** * * ** ** ** **** *** *** = water_amount - (water_amount - 30);
****** * *** *** *
*** *** * **** * * **** * *** * *

*** * * * *** *** **** ** * ** ** ** = price +(water_amount*0.6);
** * * * * **** * * *** ** *** * **** ** * * = water_amount - (water_amount - 30)
* ** ** * * * **

* * * * * **** **** * ** * *** *** ** price);
* ** ****** * 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00
0 0
Thanks!
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