10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include      **   *** **
#include * ***  ****  

int water_amount;
double price=10;

int main()
{
*** *****  * *** ** ***** **  * ***  *   *****  *   * **  

  ***** * * ** ** ***** *  * *** * **** *  * *    

**      * * ***     *** *  *  ****   ** *      *    ***  ** * = price ** *  *   * * *
 ***** * ***** *** *  **  * *** *** * *  **  ** * ******* *** **  = water_amount - (water_amount - 60);
**** * ***     * **   * *** ** 
   *   **  ** **** ******* ** **  *  ** * * *  

       **    ******  *  *  *   ***    ****** **    ***  *  *  = price +(water_amount-50)*1;
 * ******* **  *     * * **  ***** *   * *** **** ***   *** * = water_amount - (water_amount - 50);
*    *  *  * * **   *      **
    ****** *********** *****         **   * *  *** * *  

* * ** *** **  *  *******  *  * ***  ** ** *   *  *    = price  *** * * *** *  *
**    ***     **  *** **  * ***  * ** **** *   *  ** **  ** = water_amount - (water_amount - 30);
**  *  * * *  **** *    ***
 ****   *  * ***** * * *      **   

**  ***  **  ******* *   **  ** ***   ** **  *  **  = price +(water_amount*0.6);
    *****     **  *  ** ***  ** ** * * ** *  **** * ** ** * *  * * = water_amount - (water_amount - 30)
  *  *  *  * * *   *** **** 

*** ***  * *** ****    *   *  **  ****  ***  price);
   ** *  * *       *   * *** * 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!