10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include  ***   ** 
#include * * *****   **  **

int water_amount;
double price=10;

int main()
{
*****   *   *** ****   * *****       ***  **** ****    *  * * *

 **  **    ***  * * **   **    ** ******  

** ****  * * *  * *      ** *  * ***  *  * ***    *      **  ***** = price    *****     * * 
* **    ** **  ****      *  *   *  ******* ***   *    ***  * = water_amount - (water_amount - 60);
****  * * *  * *  *   * ***** *
 *   **  **   *   ****   * ****  ******* **

 *     ***   **  * *   **   ****  *   * * * *   **** *  = price +(water_amount-50)*1;
  *** * **** *****  *  *    * * **** * ***  *   *  * * *   = water_amount - (water_amount - 50);
   ***  ***   ***  *  * * 
 ** * ****** **** * * * * ***    * * * 

**** *  *  ***  * ***  ***  * ****  *  ** ****** ***  * *  = price  *****  **   *  
 **** *        *  *  * * *   *   ** ***       * **  * **   * * = water_amount - (water_amount - 30);
 **   ** ** *  *     *** **
 ** *   ** ** *   **  ** *     * ****  *  ** *

       ** *  **  * * *    * *  **  *   *  ******  ** ** * ** * = price +(water_amount*0.6);
*   *****  ** * * * *** ****** * *    **  *  *  *****  *  ***     ** = water_amount - (water_amount - 30)
*  ****    * * ****  **   

** *       *  * **  * *   ***  ** **  *  *  *  * price);
** *** * **   * ** **  *  **  *   * 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

---

Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

---

Thanks!