10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include **   ** *  
#include *    * *** *   

int water_amount;
double price=10;

int main()
{
*   ****  *  * ***** ****  **   ** **   ** *   * ** * ** * **** ****

  *    ** * *    ** * **   *  ****  * *  ***   *

**   *   *  *  * * *      ** *  *  * * ** **  ** *** *   = price   *     * * ** 
****** * *   **********  ***   **   ** *** * * ** *  **  *  *** = water_amount - (water_amount - 60);
 * * **  * **    *  * * * **
    * *  * ** ***  ** *****   *** * *** **  ***

*  ** * **** ****** ** ** ** ****** *   ****   ****** * *  * * = price +(water_amount-50)*1;
** * * * *  *  ** ** ***** ****  ** * ** ** ** *  *** **** = water_amount - (water_amount - 50);
     * *** ** * **   * ***   ****
  ** *   ** ****  *  *   *  * ****     * 

*   *********   ****  *  *  * **   ****  ******  ****   = price ** * ****** ** 
* ** ** *  * *  *   *    * * ***   *  *   * *****   **   ** = water_amount - (water_amount - 30);
 ***** * * ** *  ******  **   
 *** ** *  * ***  *  ***** ****   ***** *   

***  * *     ***       *** **    *   **** *   ** *   ** *    * = price +(water_amount*0.6);
 *** ** * ********   *  *** *   ***  * *  ** *     *  ** * **** = water_amount - (water_amount - 30)
   * **** **     ***    ** *  

*  *  * ****   **   ****** *** **  *  * * * *  price);
* * ** **   ** ** *     *  * 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!