10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include *  *****  *  
#include ****   *******

int water_amount;
double price=10;

int main()
{
* *   * **** *   ***** *  * *** *** * ** ** *  *  * ** ***  * * ****

*   **   *      * * *****   * **  * * ** *  

* ** * ** *     *   *** **  **  **  ** *  * *   ***** = price * *   *   *   
   **    *** * * ***  *      * *  * *  ***** **   *** ***  ****    = water_amount - (water_amount - 60);
 **    ** ** *** * 
*  ***  ******   *  **** ***  * * *** *    **

*     ***  **  *  **  *** ** * *   ** *  **  * * *  ***       = price +(water_amount-50)*1;
 **   ** * *** *   * **  *  * *** ** *   ****       ****** ** **  **  = water_amount - (water_amount - 50);
    * * *        ** *  * * *
**    * *** * * * *   *  *********   ** ****  

  *  * *  *** ****** **  * *   *       *     * *  * *****  = price ***  * *     ***
***** *    ** ** ** * * * * ** ** *     ** * **   ***   ** = water_amount - (water_amount - 30);
 ******* *   ****** *       * 
 *      *    *** *     * ** *  * *   ** **  ** 

*   * *   *   *** *  *      *  * ** * *****   *     ** *  = price +(water_amount*0.6);
****   ** * *** * *** *  *  *  ** *** *  ** *** *** **    ****    = water_amount - (water_amount - 30)
 ***  ***** *   *** ***  *   *

 *  ***   ** * * *    * *** * **     *** *  price);
***   **  ** ****  * ****   *  *    0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!