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A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 26465 - Available when: Unlimited - Due to: Unlimited

edited by | 3.5k views

91 Answers

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Hidden content!
#include * ** * ** **
#include * * ** *

int water_amount;
double price=10;

int main()
{
* ** * ** * * * * * *** * * *

******* ** * *** ***** * * *** **

* ******** ** * * * * *** * * ** ****** ** = price **** * *** * **
* ** ** ** **** ****** * ** **** * * * * = water_amount - (water_amount - 60);
** **** *** **** *
* ** ** * * ** * ** * *** * * * **

*** *** * ***** * *** ** * * * ** * = price +(water_amount-50)*1;
*** * * ***** ** * ** * ** ** ** ** * * * * * = water_amount - (water_amount - 50);
* * * * *** * ** * *
****** * * ** * ** * * ** **** * * *

* ** * *** * **** *** * ** ** * ** **** *** = price * * ** * ** **
* * * ********** ** *** * ** ** **** ** * ** = water_amount - (water_amount - 30);
** *** *** * ** ******** *
* * * ** * * ** * * * * ** *** *

* ** *** * **** ** * *** * ** * * * * *** = price +(water_amount*0.6);
** ** ** * ** * ** ** * **** **** * * **** ** = water_amount - (water_amount - 30)
** * ** * * * ** **

* ** * *** * ** ****** ** * * *** * price);
** * ** ** * ** *** * ** 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00
0 0
Thanks!
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