10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include    *** *** * * **  
#include * * ********* *  *

int water_amount;
double price=10;

int main()
{
*  **     ****  *  ** ****** *****  ** *  * * * ****

**   * **  *    * * **   **    *** *  * 

*     *** **  *****   * ******* **  * * * * **     ******  = price *******   **  * *
 ***  * ****** *    * *  **** ** ** *   *     *    * **** *    ** * *  = water_amount - (water_amount - 60);
 * *      *  * *  *** *  ** 
 *** ****  ** * *** **  ***** *  *  **  **    **  *

** *  ** *****  ****  ** **    **   *  ** ***  ******   **  = price +(water_amount-50)*1;
**  **   ******   **  ** ** *  *********      *  *** ** ***     ** * = water_amount - (water_amount - 50);
**** *** *     * ****      *** *
* ******  ** **   *   * *  ***  * ** 

 * ** ***  ** **   ** * **  *  *   ** *   *     * **** * **  = price ** ** ** *** *
*  ****   * * * * ** ****** ** *  * **     **** * *   *     = water_amount - (water_amount - 30);
***   *    **   * * *   ***  *
      **  ** **  * *  ** **    * ***** *  *    * *  

   ***  *  *   *    * ***    *     ***  *** *  *** *****  = price +(water_amount*0.6);
  ****  * * *     ***  ***** *   *** ** *   ***** **      * ** = water_amount - (water_amount - 30)
*    ** *     *     ** * ** 

 * ****** ***   ** ***    *   ***** * * ** *    price);
*       *  * *  ***  * *****  *** 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!