10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include      *  ** *** 
#include **     *  *

int water_amount;
double price=10;

int main()
{
* **  ****** *  *  *** **   ***  *** ** ** *  *** ***** *

* * *  *    ** **  ****  *** * ***  *****    * 

 * *  * ** * *  *  ****  * *** ***   *** *    * *****   = price *    ** ** **   
 **    *    * ****** ***** **     ****   *****  *  ** * ***     = water_amount - (water_amount - 60);
*   **  ** *  *   *  *  ** *
** *  *   *  ** ** ***    **** *** * * **

* **     * **  * ** * * *   **  *   * **   * * *  *   = price +(water_amount-50)*1;
  **      * ****** ** *  ** *      ***    *   *******  ***   *  **  = water_amount - (water_amount - 50);
**  **   * * **   ****  *
      *  **** * * *  ***     * *  ******* * ***

* ***  * * *    *****    *  ** *     **  * ** *        = price  *  ** * *** ** 
    *  *    **    ** ** *  *   * *       *********  * **  *  * = water_amount - (water_amount - 30);
*  *** ***     ***  * **** *
*** ***       ***  *  ** * ****  ** **    ** **

 *** *  *****  *    *** * * * *   *** ******** *     **** ** = price +(water_amount*0.6);
* * *  *** *** ****    ***** *    ***   ****  ****** *  ****  *   *  = water_amount - (water_amount - 30)
  **  *   ***   * *  **** *  

*  *    **   ** *   **  * ** ***   * ***   *  **  **  price);
 **  *  *** *    * *  **** ** ** *  * 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!