10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include * ****       * 
#include    ****  ** 

int water_amount;
double price=10;

int main()
{
 *  *  *  * **    * *    *    *  ** **  *  *  *   *   * *  ** * 

* ****   *  *  **  * *   ** **** *  * ** ** *  *

*  * *    * **** **   ** *  * **      * * * *  * **   * ** = price   * *** **     
***  * *           *** ** *    *  * ***   *     *** **     * *   ** = water_amount - (water_amount - 60);
*  ** **  *  ****** **  * * **
*  **  *    *   **   * ** * *******   *   **

  *  * * **  ***  **  **   * ***    *      *   **      *   = price +(water_amount-50)*1;
*  ** * * ***     *    ***    *****   * **  * **   *  *   *  = water_amount - (water_amount - 50);
*** *  *  ** *  * *   * 
 *****  ****      *   ****     * ** ** *  ***

 ***   ***    ****** * ******  *    *** *       * ** * = price  *** *   * ***
*     * *** ** ** *   ****  ****   ***  **  ** **** * ** * * *  = water_amount - (water_amount - 30);
 ** * *  * ** **** *   *  
**  *    * * * *   **** * *     ** **** 

** ***   ** **   ***    * **    ***    **    ** ***  *** = price +(water_amount*0.6);
       ***  *** *     ***    *   * * *   **   * ************ ****  * * = water_amount - (water_amount - 30)
  ** ** *** *  *  * ** *  *   

        * *     * * **  * ****    ****   * **  price);
* **  *****   *** *   * ** *       * 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!