10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include   *  **  **   
#include  ** **   * *

int water_amount;
double price=10;

int main()
{
  *  *****       **     **   *  ***  **     *  *** ******  *******  *

*   ** * ** ** *  * * ** ******** ** **  *  * *  

 *  ** * *  * ***** **** **  *  **   *  * *  ******  **     = price   * *  *   **   
 **    *     *     * ***   **  * * * *** * ** *  **     ** = water_amount - (water_amount - 60);
 *** ** **  ** **  **  **  
 * ** **  **    * ***** * * *    *    *  **** 

**  *     * ** *** * ** *****   *******   *      ** *** ** = price +(water_amount-50)*1;
**  * ** **   ***  **      * ***  ****     *   **** * * *** * ** * = water_amount - (water_amount - 50);
**   * *** * * *   ** ***** * 
* ***** ** * * ***  *  *  * ***              * * * 

 *  ***  **   *** * ***  *  *  * **   **** **      *** ** *  = price  *   * * ****
*  * * *  * * * **** ** * *  * *   * **  * *     ****   *** **    = water_amount - (water_amount - 30);
 **    * *  *   ***    **** 
 *** ** * ** * *   ******     *** ****   ** *  *

*** * **  * ****  ***  ** * ***   *********  *   * * ** = price +(water_amount*0.6);
  * *  ***    * ** *  *** * * *    * * * ** * *   *    **  * *  = water_amount - (water_amount - 30)
** * *  * *  *  *   *  ** * **

 * *  ** ***   * * *  *  *     *    *   **  price);
***   * *  *  **     *** *  *  0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!