10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include  **   ***** * **
#include   *    * *** ** *  

int water_amount;
double price=10;

int main()
{
****** *** * * **** ***   * *** **** * *   *  * ** ******  *

   ****  ****   *** * *** ** *     **   * *  ***  **  

** ** *  **  * * ***      * * *  *  ***  *** *  *** ** = price    * * **  * *  
    *  ** *      * ***    ** *     * ** *  ** ** * * *      * = water_amount - (water_amount - 60);
 ** ***  *    *****  ***   *
 * **  ** *     * *****   * *    **   * * *** 

 **   * *  **    ****  ***   *  * * ** * * ** *    ****** *  = price +(water_amount-50)*1;
*   ** **   * *   *      * ****  * **  *    **     * ***** * *   = water_amount - (water_amount - 50);
 ******   ***    *****  **
* ***  ** *   * **  *  ***** ****  *   ** **  ***

*   ***** **  * * *  *  * * *  *** *  *** **** *   **  * * = price    **  **      *
*   * **  *  * *      *****    * *     ******* **  * ****** *  = water_amount - (water_amount - 30);
          *  * *    * ** 
  * *** * *** *  *  * *  *** *  *  ** ***** *****  **

* *   *  *** * **     *** *  * ******* ***    * **   = price +(water_amount*0.6);
   * ** ****     ** ** ** *    **  * ** **  * * ***   * **  **   * * = water_amount - (water_amount - 30)
 ***   *   * *  *  ***  * **** 

** *  **  * ******  * * *     *  **  ***** *    * price);
 * * ****   ** * * ** * *  *  0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!