10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include  ** * *** ****  
#include   *   * **** *

int water_amount;
double price=10;

int main()
{
*  * *   *     ****  * ** * * * ** **    ** *  * ** ***  **  ** **

*  **  **   * ***   ** *     *  *  *  **  

** *  **  ** **     ******* ** ***  * **     ** * *    * = price * ***   ****** *
* ****  *     * *     ***  * **  * * * *  ** * *********** *  ****    = water_amount - (water_amount - 60);
    ********* * *****    * ** 
   ***    * * *  **** **   * * * **    ***

**  *       ***   **       * **    **  ** ** *  **      = price +(water_amount-50)*1;
**** **    *  **     *** *   * * ** * *   ****  * *   *     * * = water_amount - (water_amount - 50);
 *** *******     **    ******
 ** * ** * *** *     **  **   **  * * *** *** 

*   ****   * *  * * *  *** *    *  * **   *** *  *  *  *   = price *    * **** **
****** * * * * ** * **  * *  ***  ***  *** ***  ** * ** * **  *  = water_amount - (water_amount - 30);
 **   **** * * * ***  ** *  *   
   ** ** **  ****     * *** *** ******  * * *   **

*** * **  *** **     *   *** ***    *  * *  *  **  = price +(water_amount*0.6);
* **** * *   **** ****     ** * *  *  * ****** ** *  *      ***  **  *  *  = water_amount - (water_amount - 30)
 * *       *     ***     

**  * *** * ** *****   ** ***** *    *   ****     price);
  *****  *  ********  ***   * 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!