10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include * ********    
#include       * ***** 

int water_amount;
double price=10;

int main()
{
**    **  *** * *   **** ***  ***    ******   ***  * *

 *   * **    * **** * *  ** * * ** ***  *   * 

*   * ** *****  * **   *** *   * **  **  * ***   * ** *** = price   *    ** ****
* *  ** ** * **** * **   *  **** ** *  **  **        *   * * *   = water_amount - (water_amount - 60);
***  *  * ** *****    *   
**     **   **       **  *  **   * **** *      

* *  ****   **  ****** ****** ** *  *  ******* ***** ** *  * = price +(water_amount-50)*1;
*  *** ** **  ** * ** ** * *** * *  **  *******    ***   = water_amount - (water_amount - 50);
 * * **  ***   ****  **   *  
* *   **  *  *****  * * **    ***  * ** ** * **  *

  *   *  **    ***    *** * **** *   * *** **  * *** ** = price   *** *  * *  * * 
   * * *** ** *      **     * *   **  ****  **** *     *  * ***  = water_amount - (water_amount - 30);
** **  * ***   * * ** *****      
*   ***** *   **  *** * *** *  * ***** * ***  ***

  *  ***     * * **    *   **  * ******** ****  * *****   = price +(water_amount*0.6);
 **  ****** *   **   ** ******  ** *   *   *** **   * * * ** ** *  = water_amount - (water_amount - 30)
* ** **   ****** * * **  *  

**   ** * *** * ***  ****    ***  * *  *  ** price);
 *** *  ********     * **  ****   0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!