10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include   ****** **   * * 
#include *** **   *    *

int water_amount;
double price=10;

int main()
{
*  **** * ** ** ******  ********  *   *         *** **  *****    ****

  ** *    *  *** *    ***** *  ** * * * ***  ** * 

 * *  *** ** *** * * **   ****   * **  * *        *  * * * * = price *   **         *  * 
 *  **   *     ** ***  ***** **   * ***  **  *   * ***   *  *  * = water_amount - (water_amount - 60);
  ** * *  *** *     *
   * *** *  ***  *  *  **  *****   **  * **   * *

        **   *****  * *  *   ***  ***   *** * ** ****** *  = price +(water_amount-50)*1;
  *** *     *** ******  * * *  ***     *** **  **  * **** ** = water_amount - (water_amount - 50);
*  **  *  *  ** ****  *  
 **   *    *  *  ***   * **  *** ****

  *** *  * ** *  **  **     * * *  *** **    * * *** *** * * = price  *  ** ***** **
*** *  **** * * * * *    *   *  * ****      * ** ***  **  = water_amount - (water_amount - 30);
** * *  **  ** *** ** ** * *
******   *  *    *******  * ***** ***  *  * *

*    **    **   * **    * **  *    **** ***  ***   *    = price +(water_amount*0.6);
 ****** *     * ****  *** ****    *    **  **  * *** *   * * = water_amount - (water_amount - 30)
  * *** ****  *   * ***    ***

 * *******        * *  * **** * ****     * ***** price);
**  **  * *   ****   ****  *** 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!