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A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 26465 - Available when: Unlimited - Due to: Unlimited

edited by | 24.1k views

91 Answers

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Hidden content!
#include * ** * ** *
#include * *** ** *

int water_amount;
double price=10;

int main()
{
* * * ** * ** * * * *** * * ** * **

** ** * * * **** * * * * * * * *

* ** * **** ****** ** * * ***** *** *** ** * = price ** *** * *
** ** ** * * **** *** * * * ** * * * * * *** * = water_amount - (water_amount - 60);
**** * * * * **** *
* * * **** * ** ** *** * ** * *

* *** *** ***** * * *** ** *** * *** * * = price +(water_amount-50)*1;
* ** * * ***** ** ** *** * *** * ** * = water_amount - (water_amount - 50);
**** **** ****** ** * *
* *** * * ** ** **** * **** * ** *

** *** **** ***** *** ** * * * * **** * * = price * * * * **
* * *** ** *** ** ** ** ** *** ** ****** ** * * = water_amount - (water_amount - 30);
** * * * * * ** ** *
* ********* **** ** * ** * * **

* * ** * *** ***** *** * ***** = price +(water_amount*0.6);
** * ** ** ** * ** ** ** * * ** * * ** = water_amount - (water_amount - 30)
** *** * * * *** * * **

*** ***** *** * * * *** * ** *** * price);
* * ** ** *** * *** ** * * 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00
0 0
Thanks!
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