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A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 26465 - Available when: Unlimited - Due to: Unlimited

edited by | 17.9k views

91 Answers

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Hidden content!
#include * ** * ***
#include * * ****

int water_amount;
double price=10;

int main()
{
**** *** **** * ** * ** * *** * ***** **

* *** *** * ******** * ****

* *** ** * * * * * * ** *** * * **** *** ** * = price * ** ** * *
** ** ** *** * ** ***** * ** * *** *** ** ** = water_amount - (water_amount - 60);
**** * * ** ** * *
**** * * ** ** * **** ********* * ** *

***** ***** * * * * * * * ****** * * * ******** = price +(water_amount-50)*1;
* * ** * * ** * ****** ****** * * * ** = water_amount - (water_amount - 50);
** ** ** * * * ** *****
*** ** * ** ** * *** * * **** ** * * *

** *** * * *** * **** ** * ******* * * * * = price *** * ****** *
**** *** ***** * ** * ** * ** ** * * ** * * *** ** = water_amount - (water_amount - 30);
* * * ******* ** * ** *
* *** * ** *** ** * * *

**** **** **** * * ** *** * *** ** *** * * *** * = price +(water_amount*0.6);
** ** ** ** * ** * ** ****** ** ** * * **** * * = water_amount - (water_amount - 30)
* *** *** **** * *

*** * ** * * * ** * ** * * **** * *** * price);
** * **** *** * * * * 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00
0 0
Thanks!
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