10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include  * * *  ***** 
#include **     *  *  ** ** 

int water_amount;
double price=10;

int main()
{
* * **** *   ** * ** *   ***  *  **     * **** *****  *  *   *  * 

*   *  * * * *    *** *  *****     ** **  ***   *  *  * 

* *    *****   **  *  * ****  *** ** **** **  * ** * = price  ** **  *** *  *** 
 *  * ** * * ** * * **   **  *  ***     **  ** *  * *  *  = water_amount - (water_amount - 60);
*   ** **   *****    *
  *   *****  * *    *** *  * *  **   ** **  

**  ***  **** *  *  * *  ** * *  ***  ****  *  * *  *  ** = price +(water_amount-50)*1;
**  *    * *  * *****  **  *** *   *  ****   * * **   *  * = water_amount - (water_amount - 50);
  ***  * * *** * *   **  
***** *  ****  * **  * **  * ** **   *****  

  * **** * *  *    **   *  *** * * *  * *  *    *** **** = price  *  ***   *  
*   *  * *   ** ***  * **   *   * ***  *  * *** * * ****** = water_amount - (water_amount - 30);
*** **** **** **   ** **   * *
* **  *  * **   * *     *    ******   **  ***     

   * *** *****    ****  **     *****   * **** *  * *  * = price +(water_amount*0.6);
* *  *****   **** **** *******  ** **  * *     *  ****  = water_amount - (water_amount - 30)
***  ** *   *  *      **  **  * *

*   *  *    * *    *   **   ***      ****   ** price);
***** *  *** **  **  **  *  *    0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!