10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include  ***** * *   * *
#include *  *  * * **  

int water_amount;
double price=10;

int main()
{
 *  *   ** *  * **  *  *  **   **** ***      *     *** ** 

  *   * *    *   * * * *  *   *         *

* * **     *    ***** *  *  * ***    ***     * * * *    ** = price  *** * ****** 
*  *  *    ***  *** **  **  *  *     ***  * * **   * **    = water_amount - (water_amount - 60);
 *  *    **** * *   *** 
 * *    ** ** *    ** *  ***  *** **  *  ** 

*   ** ****  *  *  * * * *** *** **   *** *  * ** = price +(water_amount-50)*1;
* * *  **   *** * **  **** **    **  ** * *    **   * ****  * * ** * = water_amount - (water_amount - 50);
* **   *** ******  * * *** *
 *   *       **** *  *  *  *   ***    * ****  ****

 * * *   *  * *     * * *  ** * **    ** ****   ***  ***  ****  = price    ** *** ** *   **
*    * *  *  *  * ***     *** *    *  *     ***   **  * * *****   * = water_amount - (water_amount - 30);
* ***  ***  *      * * *    
  *   **     ** * *  * ******  **  **     *** *   

 ** ** *     * ** ***** ******* *  *    ***  ** *  * *** * = price +(water_amount*0.6);
  **  **  *****    * *  * ***   *   *   * ******** *** *   **  = water_amount - (water_amount - 30)
   *  *  ***     * ** ***

     * * ***** * * **     **** ***   *   *   price);
  * **** *    ** ** **   *  * * ** 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!