10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include ** *   *    * *
#include  **** ** ***  *  

int water_amount;
double price=10;

int main()
{
   *   *    **  *  ** **** ** ** * * *** ***** ****  * ******     *** *  

 *    * *  * *  **  ******   *  **  ****

********  * ****  ** *****  *******  ** **** ****       *      *   = price *  ***    * * 
    * *  **   **   ****  ** *       *  *** *   ********  * = water_amount - (water_amount - 60);
 ***  *         * ***    *  
  ** * * * *** *** *       * *********  * ***  *

**    *** * *** *****    **   ******   *** ** ****  * **  = price +(water_amount-50)*1;
**    ***** * *   *  *  ***   *   *   *   *   * **   *** *     = water_amount - (water_amount - 50);
** **** * * **** * *  * ** *
   *  ** ***    **** *  * ** *  **  * **

  * **  *    *    ** **   ************ * * ** *****  * **** *  **  * = price   *  ** ***
 * ** *     **  **** **     *******  * ** **  * * **   *   *  = water_amount - (water_amount - 30);
 ** * ******  *   **** *   **
* *  ** *  ** * ****  **** * * * * *    * 

      * *** *** *  * ******** * **  *   *****   * ** ** * **    *    = price +(water_amount*0.6);
** * *  *  *   ***  **  **     ***      **     *      * ** *  *   = water_amount - (water_amount - 30)
    *****  *   ** **** ***

   ****** *  *  *   * *    * *   *  *** ** price);
 *  *******   * ** ** *** *  0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!