10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include ** ** **  **  
#include ***    *** * ***

int water_amount;
double price=10;

int main()
{
* ******       **  *  *** **      ** ** *    ****** **   ***   

 ** *  *  * **** *  *  ** * * *  ** ****** * *

* ** ** *  ***  *** *  *** ** * *** *  ** ******      ** = price *** **     
** **    *  **       * * * ********     ** * ***  *** *** ** *  * = water_amount - (water_amount - 60);
 *     *  *  ****  ** ****  **
 *        ** ****  * ** *    *****  *  * *** *

  **   ***  * *   * ** ***** **    * ** **** *** ** = price +(water_amount-50)*1;
  *  ****    *  *     ***    *****   *  **  *  ***  ** ****  *   = water_amount - (water_amount - 50);
** * *  ***   ****  *** *
   * ** ** ***  *  *****  **  *** *    *      *****

* * * *     * **     * *** *  * **** *  * **** * ** *  = price   *  * ** **    
**** ** * *** *  **    **** ** *  **     **** *   * ** *  ** = water_amount - (water_amount - 30);
 ***   **   * **   *** * *   *  * 
*** * * * * **  * * *   * *** * * ****  **

 *  *           ****    * * * * ***** *    **   ***   * = price +(water_amount*0.6);
 *       ** **    * * **     *   * *    * *   ****  **  * *  *   = water_amount - (water_amount - 30)
 **  * *  **  * ** *  *  *****

*   **       * **** *  **    *  **  * *  ** *    price);
*  *  ******   *   *   **  * * ** 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!