10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include **  *  ** * 
#include ***   *   * *  

int water_amount;
double price=10;

int main()
{
 ** **      * * **** **** * ***** *   *******      *  ** **** **

   ** *  *  ***  *  * ** *  **  *   ** * * * * 

 **    *  *  * *     ** *** * **    **    * ****** **   = price *   * * ** * ****
***  * ***   ******  ** * * *** *** **** *** **    *  *** = water_amount - (water_amount - 60);
********** **  *       ***   
**    **  ******* *** *  *   **    ** ****  ***  ** 

*** ** **  **    * *  **** ****  ****    *   *  * ** *  *   *  * = price +(water_amount-50)*1;
  *   ***** ** * *  * ******* ** *  * *   ** *  **  ****    = water_amount - (water_amount - 50);
*   *** ** *  * * ***** *      *
** **** ** **  *  *  *  * *   *** * * 

  ** **  *  *   * *** *     *** ** **    * *  *** *  **  = price   * *** * **
 * * **     *** **  **  * **   * *  *** *  *  *** * * **  ** *** * **   = water_amount - (water_amount - 30);
   *** ******  *     ** *  ** *
*  **  ****   **   * ****** ** *    **** ** * 

 ** ****  * ***     *   **** * *  *  * ** *    *  *   * *     = price +(water_amount*0.6);
  *** *   **      *  ****  *** **       **  * ** ** *  *  = water_amount - (water_amount - 30)
  * * ****    *  *   * * *** 

  **  ** *   ** *  **   ** * *  *    **  * * *  * price);
  ** * ***  * ** *** **** *** 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!