10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include       * ***      
#include **   ** *   * * 

int water_amount;
double price=10;

int main()
{
* ***     **** ** *  *  *   *   **  * *  *** **  *  ***  * **  **

** **** * * *   **** *   * ***  ** * ** *  * *  

** *** **  ******  *****    **** ** * **** **  *** *****  = price *   ***** *   *  *
  * **  * ***   *      * * *  *****   *  **    ** ***  * **  * = water_amount - (water_amount - 60);
 ****   ** ***** * *   ***   
** ** *** **     **    ****** *** ***** * ** **

 * *** ***  * *** *  ***          *  * **  * * ***  *  **  * ***  = price +(water_amount-50)*1;
** * ****      *****  * * **** * ** **   * **   *  ** *   = water_amount - (water_amount - 50);
 * * ** ****** **    *  * 
 ***  *   ***  **  *    *  *   ** **** **** **** 

*** ***      **** * *  *  ** **  ***    ******      **    * = price  * * **   *** *
*** * * **  ***   **** *******   ** * * *  ***         ****   **** * = water_amount - (water_amount - 30);
 ** * **    * *** ** * * 
*  ***     *   *  *   *  * ****** *** ** * * **

  **     **  *   ** ***  * * *  *     **  ****** ** ***** * = price +(water_amount*0.6);
**  **** **  *   * *    ** * * *****  *  ***** **     **  *  = water_amount - (water_amount - 30)
 **  ***  **    * **  ***** 

***** * *   ***   **   *****  ** * *  ** * price);
    *  ***  ****    **      **  * 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!