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A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 26465 - Available when: Unlimited - Due to: Unlimited

edited by | 13.9k views

91 Answers

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Hidden content!
#include * * ** *
#include * * *

int water_amount;
double price=10;

int main()
{
* * ** * ** *** ** ** * * **** * ***** * *

** * * * *** * * *** * * *** *****

*** * * * * * * *** * * *** *** * ** ** ** *** = price * **** ****
* * ** * * *** * *** ******* * *** * = water_amount - (water_amount - 60);
* * * * * * ** * **
* ** * * * ** *** *** * ** *** ** *** ***

* * * * *** *** *** * * * * ** ** = price +(water_amount-50)*1;
* *** * * * ** ****** * * ** ** ** ** * **** = water_amount - (water_amount - 50);
* ** * **** ** ***** *
** *** ** *** * * * *** * * * * *

*** * * *** * * * ** ** ** * **** ** *** ** * * ** = price ** * * **
* * ** ** **** ** **** ** **** * * ** * ** * ** * * = water_amount - (water_amount - 30);
** * * **** ** * *
* * ** ** * ** ** *** ****

*** ** ** * * * ****** *** * * **** *** * = price +(water_amount*0.6);
* * * * * * * * ** * **** ** ****** = water_amount - (water_amount - 30)
*** * * * *

** * ** * * * *** ** ** price);
** ** ** * * * * ** * 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00
0 0
Thanks!
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