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A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 26465 - Available when: Unlimited - Due to: Unlimited

edited by | 25.9k views

91 Answers

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Hidden content!
#include **** * *
#include ** ****** *

int water_amount;
double price=10;

int main()
{
* * ** *** * ** ** ** ** * * * * * * ****** ** ** **

* *** * ******** **** * *** * * *** ** * **

**** ** * * ** * ***** * ******* ****** **** = price * ** ***** *
****** * * * * ****** * ** *** ** ***** ** * = water_amount - (water_amount - 60);
** ** *** ** ** ***
*** ** * ** * * ** ** **

* ** * * * * * ***** *** * *** * * *** = price +(water_amount-50)*1;
***** * * * * * * ** * ** *** * ** * * *** * * * * = water_amount - (water_amount - 50);
* ** * *** ** ** *** ** **
* * * ** * * **** ** ** ** ***

** * * *** ** * * * * * * * * * ** = price *** ** * **
* *** * * ** * * *** * ** * *** ** ** * = water_amount - (water_amount - 30);
* * * ***** * ** * * ***
* * * ** * *** * * ** ** ** ** *

** * ***** *** *** ** ***** *** * * * * = price +(water_amount*0.6);
* ** ****** * **** ** *** *** * ** ** *** ***** = water_amount - (water_amount - 30)
* ** * * ** * * * *

* ** * * *** * **** ** * ** * * * * price);
*** * ** * * *** * * * 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00
0 0
Thanks!
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