10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include *    * *** *  *
#include * ***  ** ****

int water_amount;
double price=10;

int main()
{
 * * *    ****  *   ***   *     **    *******    *  *   *   

**  ** **  **        **   ** *  * ****    **  *   

 * ********** * * ** ********  *     **    * *  *  ** ****     = price ** **   ***   
******  ** * *  * ** ***   * * * ** *      ***    ** *** = water_amount - (water_amount - 60);
***  *****  *    *     ***
****** *     ** * * *   * ** **** **   

* *** *     ****  ***  *** *   ** *   * *   *  **** *** *** * = price +(water_amount-50)*1;
   *  * * *  *   *  * * ******* *  * *       **  * *  ***  = water_amount - (water_amount - 50);
***  *** * *   ** *****    *   
** ***    *  *  *  * * * * **   *****  * 

***** **   **  * **  *  ***  ***   *** *  ***  *** *****  * = price  * * *  * ** *** 
 *** *   ***    *** ** * ***** ** * *** ****   *** *       **  = water_amount - (water_amount - 30);
*  *  ***** * ** ** * *****  **
        **  *  * **   ** **   *   ****   * *** * 

    ***  *    ** ** **    **** *  **  * *  * *     ***   ***** = price +(water_amount*0.6);
 ****    ***        *   *** * * *   ********  ** *     **   **** = water_amount - (water_amount - 30)
   * **    **** ****   *

   **** *     *** ****** *********     * * * price);
*   *   ** *  * *  **  *** *****   * 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!