10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include  * * *  **  
#include    *****  * *   *

int water_amount;
double price=10;

int main()
{
*  * *** *  ** *   *  ****    * **  **** *  *   ***    * * 

******  ****     ** *** * ****  ** * * **** *  

*****  * ** **  ******    **   **  *  ****      ****    *** = price   *** ** **
*      ***** * ***   *   *    ** *  * **  * *   **  **   **  = water_amount - (water_amount - 60);
*   * * ***  **** **   *** *** 
 ** **  * *  ****   * **  **  * *    * ** * *    * 

* * ***   ***  ******* **   ***** *****   *  **  * *** *** = price +(water_amount-50)*1;
 *  *     * *  ***   ******** ***  **     *  * * **  * *   * = water_amount - (water_amount - 50);
   **    ** *** *  *
**  **  * *       * ** *  **    ****    * ** *  *

   ***    **    * **  **   ***** * ***  * *  *****      = price **      *** 
*  * ******** * ** ** * ***     * **   ***  * * ****  *    **  * = water_amount - (water_amount - 30);
 * ** * *   * ***     ****   *
* * *****  ***   **  ** * *  **  ***    ******* **

*** * * * * ** ** **   ** *    ***** *   * *     ** **  **   * = price +(water_amount*0.6);
** **  * ****      ** ****** ** * *   **   *    *  * *    * = water_amount - (water_amount - 30)
  **  *** ***   * * ** ** * **

* * *   * ***  * * * **  ****  *  *****  * ****** price);
**         * ** *******  *  *   * 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!