10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include *****  *  *  
#include   ** * * **** *

int water_amount;
double price=10;

int main()
{
   * **  **** *    ***  **  * ****   * ***** * *  *   ***** ****

* *** **  *** * * **     * ***  **    ******

* ** *   *****     ***         ****  * *   **** ***   ** * = price   * *    * * *** 
 * ** * *   * ** ** *   * * * **   **** *   **        * = water_amount - (water_amount - 60);
*  *  * ** *  **  *   **  ** *
 * ***    * **    *    **  ** * *** *****  ** *  ** *

 ***** **     ** ** *   ** *  **  ***  ***** *   **    ** *  = price +(water_amount-50)*1;
*   **** **   *  ****      **     ** *** ***** * ***  ** *    = water_amount - (water_amount - 50);
*     *  ** *    *   * *   *
*** * ** **** * *** *  ****  *  *  *       

   *   * *** *** **   *  *    **  ***  *  * *  *    = price *  *  *  **      
**  *      **   * * *    *****    ** * ** * *  *     *  *  * = water_amount - (water_amount - 30);
* * ** **  *****    ******    
 *** *** *  ** * * *  ** **  * ** **  * * *

   ********     *    *     **  *** **** * *  * *  * * *   * ***   = price +(water_amount*0.6);
**  ****** * * * * **** * **    **     ** **    ***        ***  ** = water_amount - (water_amount - 30)
 ** *   *** *    ******    ** * 

*   *  *  *    *  *     **** * **  * *******  * price);
*  *     **   *    ***    * 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

---

Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

---

Thanks!