10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include ***** **  ******
#include *     **   ***  *

int water_amount;
double price=10;

int main()
{
*    ***  *******     * *     ** * *   *    *      ** *  *****

*  *     ****  *** ** ***  ** *** ****   **  * *

*  * * **  *  *  *  *****   * **  **  * *  ** *   *  *     = price ****    **   * 
******  * *** ***   *  * *  *** ****   **  ** *  *****  *** = water_amount - (water_amount - 60);
*    *  *  *** ****   * * **
*   * * ******    **   * *   *** ***  ****     

**  *** * * ***  * * * ** ***     * ***  **  **    * **** *** = price +(water_amount-50)*1;
***    * * ******* ** *** **  * *     * **** *** ** **  **   **   = water_amount - (water_amount - 50);
 *  *********** *  **      *
 ***   *    ** * * **** *   ** *****     *

*** *  * *      *   **** *    ** *** ** * * ** ****  *   * = price   ****** * * ** 
**** *  *   * **** ****   * ** ****** *  *   *      ****** ***** = water_amount - (water_amount - 30);
 ** * *  * * ** **  *
  * *** **   *   **   ******   **    ****    *****

***  *****  *    * ** ** *** * * ****   * ***  *   ***  *  **  * = price +(water_amount*0.6);
*** * *  **  *    * ****  ** * **  *    * ****    ** ** *** **** = water_amount - (water_amount - 30)
  * *****    ** **   ***

 **   * * * **   *  *****    * ****  *     * price);
*  * *     *** *      *      * *    0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!