10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include  * *   * ** *** 
#include   *  *   ** **** 

int water_amount;
double price=10;

int main()
{
   *   ***  **   *  ** **   * *  ***  ******* * ***

 ** ******  ***** ** **  ****** *  ******  **  

 ** *     **  **   **  *** * *** **   **    **  * *  * = price   * *   * *     
** *  ****** ** *   **   *  * *  * *  * ** *   *  * *  **** * * = water_amount - (water_amount - 60);
*  * **** * *   *     ****  *
***  *****  ** ** * * **      ****  *** * ***

   * ***** ** *  ***    * *      * *     * *  **** * **** = price +(water_amount-50)*1;
**** **  *** ****  ****** ***  * *****  **  *  **  *     *****   = water_amount - (water_amount - 50);
  *   ** * *  ****  ****      *  *  
 ***    ** ** *    *  * *   * * *****   ***  *

 * *  * *    **   **  **  *** ***  *  * *   *  * = price *  *  * *    *  
* *   ** ** * *** *     * *  * * ****   * *  ** **** *  **     ** = water_amount - (water_amount - 30);
   **    *   *     **  **  
 **  *  *** *    *  * *  **    *    *   ** ****   ***

***  * *  * ** * **  *  ** *     *   ** * * ** *  *  **    * *  = price +(water_amount*0.6);
  **** * * * * **    * *    ** *** ** *  *   *** * * * * * *** * = water_amount - (water_amount - 30)
* *   * * *******   **    ****

* **   *  * *  *  * ***   *  *     **   **** ***   price);
*******   *      *  *     0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!