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A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 26465 - Available when: Unlimited - Due to: Unlimited

edited by | 25.7k views

91 Answers

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Hidden content!
#include ** ***** * ** *
#include * * ** **

int water_amount;
double price=10;

int main()
{
** * **** * *** * *** * * ** * * * ****** * * * * *** *

*** * * ***** ** * ** * *** * * **

* * *** ** * * **** * * **** ** * = price * * *** **
*** **** * * *** ** * ** * * * ** * * **** = water_amount - (water_amount - 60);
** * * ** * ** *** *
* * * ** * * * *** ** * *

**** * * ** ****** * * * * ** * ** * *** ** * = price +(water_amount-50)*1;
* ****** ** * ** * * * * * *** * * = water_amount - (water_amount - 50);
*** * ** * *** * * ***
* ** * * * *** * ** *

*** ** ** ****** * * ** ** ** ** ** * * ** = price ** ** * *
* * ** * *** * * * ** * ** * ** ** ** ********* * * = water_amount - (water_amount - 30);
* ******* *** *** * *
**** ** * *** ** * *** * **** *

** * ** * *** ** * * ** * ******** **** * * * = price +(water_amount*0.6);
* * ** * * ** * * * * **** * ** * * * * * ** * ***** = water_amount - (water_amount - 30)
* *** **** ** **

* * * ** ** ****** * ** * ***** ** * price);
****** * ** **** ** *** ** *** 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00
0 0
Thanks!
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