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A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 26465 - Available when: Unlimited - Due to: Unlimited

edited by | 17.8k views

91 Answers

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Hidden content!
#include **** ** * *
#include * * *

int water_amount;
double price=10;

int main()
{
* ** * ** * * **** * * * ** * * *** * * *

** * *** ** * * *** * * *** ** ** *

* * * *** ** * * ****** * ** * ** * * = price * * **** *
**** * ****** * * ** *** * *** * ** * ** ** ** * = water_amount - (water_amount - 60);
* ** *** ***** * * *****
* *** * * ******* ** ** * *

* ***** * * * * * * ** * *** **** **** * * = price +(water_amount-50)*1;
* *** *** * * * ****** * * *** ** ****** **** = water_amount - (water_amount - 50);
** * * ****** ********* *
*** ****** * * * ***** ** ** *** *** *

* * ***** ****** ******** ** * * * * * * ** = price * *** * *
* * * * ***** **** *** * **** * *** * *** = water_amount - (water_amount - 30);
** *** *** ****** * * ****
*** ** * * * * ** ** ** ** ** *** *

** * *** * * *** * **** ****** ** = price +(water_amount*0.6);
* ** ** * * * * ***** * ******* * * * ***** ** = water_amount - (water_amount - 30)
** *** * * * * * ** **

* *** *** ** * *** * * **** ** ** price);
* * * ** **** * * * * * 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00
0 0
Thanks!
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