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A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 26465 - Available when: Unlimited - Due to: Unlimited

edited by | 21.4k views

91 Answers

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Hidden content!
#include *** *** * *
#include *** * * *

int water_amount;
double price=10;

int main()
{
* * * *** ** * * *** *** * * ** *** * * **** * *** *** *

* ****** *** * ** ** *** ******* ***

** * * **** *** * * * * * **** * ** **** = price * ** ** * **
* * **** * * * * ****** ** * * * * * * * * = water_amount - (water_amount - 60);
* ** *** ** ****
** ******* * *** * *** *

* * ** * ** * * * * * ** ** *** * ** ***** ** = price +(water_amount-50)*1;
* * *** * * * * * * * ** ***** ** * ******* * = water_amount - (water_amount - 50);
** * * * * ** ***** *
******** ** * ** ** ** ** * * * *

** ***** ** * * * **** **** ** ****** **** *** * * * * = price * * * * * **
* * * **** * *** ** **** ***** *** * **** * ** * = water_amount - (water_amount - 30);
*** ** ** **** **
*** * *** ** ***** *** ******* *

* ** * ** * *** **** **** * *** * ** * = price +(water_amount*0.6);
* * * *** * ** * * * ** * * * * ** * * ** ** * = water_amount - (water_amount - 30)
** * ** ***** **** ***

*** * ** * ** * * ** ******** ** * * price);
******* * ***** * *** **** 0;
}
answered by (-286 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output
0 0
Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00
0 0
Thanks!
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