10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include  ** ** *** ***
#include ****  **   **  *

int water_amount;
double price=10;

int main()
{
* * * *  ** *   *  ** *  *  ****   * ***  ** ******  * *

*    **  **      *****   *** ***  * * * * *   *** 

***   ** **    *   *   *    **** * ***  *** * *     **   **    = price ****  *   *    **
* ***** *  ***   **** ***** * ** ********  **   *****     *   = water_amount - (water_amount - 60);
* ** **  *  ** ** *******
 *  * * *    * ***  ***  *    *    *    * **   *

***  * *         **     * * * * * *  * * * **  * *  * * *  = price +(water_amount-50)*1;
  ****  ***   *  ** * * *  ** *** *  *   *** *** ** * *** ***     * = water_amount - (water_amount - 50);
**  *    *** *   **  **  *    * 
** ***  **    * * *   *** **  *  ** ** *  ***** *** 

        * *  **     **  **** * *   * ** ** *  **  **** = price   **  ** *** **
** ** ** * ** * **   * * **  * * **    *  *** **  * * ** **** ** * = water_amount - (water_amount - 30);
 * *** * * * *** ***     
*****  *  *   **  * ***     *  * ***   *   **** 

  *      * * **  *** *** **      * ** * *** * *   **     * = price +(water_amount*0.6);
    * **** * ****     * * *  ****    * * ***  *******  * *    *   = water_amount - (water_amount - 30)
*       ********     * *** *

  * ***  *******   ** **** *** * *** **     price);
 ***   *   * ** *** *  * *  *  *  * 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!