10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include   * *  ****
#include  *        ****

int water_amount;
double price=10;

int main()
{
 * * *** * **   *      ** * **    * ****  **** **** **     *

  * ***** ** **     *** ***** ******  *  

 *** *  *** **    **** ** *  ***** * *** **  * ****   **  = price ** *** **   
     *** ***  * * **  ****  *  * *  **    **** *** ** ** *  * ** = water_amount - (water_amount - 60);
 *  ** **   * **   *  *   *** *
*  *** ****    *** *   **** *      ******    * 

 **  *  * *  * *    ***** * * *  *    ****  *****      *  * = price +(water_amount-50)*1;
 *  * *** *  * * * * *** *   **** * *  * * *  ** *  **  = water_amount - (water_amount - 50);
   *   *    *** * * ****  * **
 **  *   ** * ** ** *     * **  **   * * **  

 **   *  *  *  ** ** ** *** * ** * **** **  * *    = price  *   *  * ** **
  ******** * ****   ** ******  *  * *   * * **  * *        = water_amount - (water_amount - 30);
**  ****  *****     ** *  *  
 ** ***  ** *   ** **    ** * * **  **   ** *****   

*   ******* **  * ** ***  *** ***   ****  * * ***  ** *** **     = price +(water_amount*0.6);
 ****** ** *** * *  *  *  *** * *  ********     * **   **   * * = water_amount - (water_amount - 30)
*   **  * **  *****  *      ***

 ****  ***        * *   ***  *     ***  *    *  *     price);
** * *     ** ** ****    * 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!