10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include  ** *    **  ***
#include    * ****** *  ** *

int water_amount;
double price=10;

int main()
{
*** ***  *  *** ***  * **   *  *  ** * *** *  ** ** *  **  *** *

  *** *       **** *            ****   ** *

*  *  ** * ** **** * * * **  *** ** ***  *   * * ****  *** = price      *  **** * * * 
*        *  ** ***    ** * ** ** * ******  **   *** *****     = water_amount - (water_amount - 60);
 * *  *   ** * * ***     *
 * *    *   *     **       **       * * *  **

** **  *  * ** *  * ********  ** ** ***   *     **  * ***** = price +(water_amount-50)*1;
**** ** *** * *  *   * **     * * * * *   **  **  *** *****  ****  = water_amount - (water_amount - 50);
 *  * * *** * * *      *** *****
 *** *       ** *  * ****    *  * ** ** *

*  * * * * * * *    *** *   *  ** *  * *   **** * *** = price *   ***** *  *
* **    ** * ****  * * ****  *  ** **         ******* ******  * = water_amount - (water_amount - 30);
** * *            **  **
* * * **  * ** * **** ***       **** **   ** **    *

     *    *   ** ***   *  *   *  ** **  * ** *   * **   *  = price +(water_amount*0.6);
**     * ** *  *** *  *   * **** *       **  ***  *  **  *** *  * * = water_amount - (water_amount - 30)
  *   **** * *     * ** * * 

*  ** ***** ***** * * ** **  * ****    ******  ***** price);
* *  *  **   ***** ** ** ** *  0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!