10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include * * *  **  **** 
#include ***   ** *

int water_amount;
double price=10;

int main()
{
 **     ******  *** *   **  *  * **    **    * *    **    *

  *  ***   * * * ** ** **   *   ** ** **  ****** 

 * * **     ** ** *  **   *    ****  * **       * * ** *** * = price **  *****  
**   *  *** *    *   **    ****       * ** ** * ***  * ***   = water_amount - (water_amount - 60);
   ***   * **          *     **  
*** *    **  * **** * * *        * *  *  *  **

 **     *** *** **  *** **    *    **  ** ** *  **   ***   * = price +(water_amount-50)*1;
   ** *  *   ** * **  * *******  **   *  *  ***   * *   *  *   ***  = water_amount - (water_amount - 50);
 ****  ** **  ***  * * * *****
 *    *** *   * ** *   ****** **   *  **   *    ***

**    ** * ******* ** *  **   * * ***   ****      *** *     = price  * *** ***   ***** 
   ** **  *  *  *     *    **   ***   **   * **  **  ***   ****** **  = water_amount - (water_amount - 30);
 *  *  ** **      * ****    **
 * * ** ** ******   *     * * *  * *    ** *

 ********* *  *  **  *  * *** *  ***    *  *  ** *  *  = price +(water_amount*0.6);
*  ****** * **        * *********   **    *    * *** ** *****  * = water_amount - (water_amount - 30)
*  **     *** ****  ***

       * *  *  *   ***  * **  ***** ***** *** *  price);
  ********   * ** ***  * ** 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!