10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include  *  *   * * ** 
#include ****  * ** ** * *

int water_amount;
double price=10;

int main()
{
*****    *    ** **        ****  ****   *      ** *****  *  **  *****

*** *  *  ** ***  *** ** **  * **** ******* * * *

**   * *  ***     * * **     *       **    **  *   **  *  = price *  * * ** **
  * **** *** * ** * ** **  *** *  **   *  ** ** * *  **     **  *  = water_amount - (water_amount - 60);
** *      * *   * * *   ** 
 * **    * ** * *** ** **       * * * ***** * **  * 

 * **  *    *** *  * * * ***** * ** ***    *  *      = price +(water_amount-50)*1;
  ***** *  *  *  *  ** **    ** *   *    ***    **   *** * = water_amount - (water_amount - 50);
*  **  * ** *     ** *    ** *
   ***** *** *****  **  ** **   *     *  **  *  * 

**   **** * ***   ** **** * * * **  * * *** * ***   ** * = price   *     *** **
  *      * *  * *   ** **     ** *** * *  ***** * * **  ****   * * = water_amount - (water_amount - 30);
*  **  *** * * * *   *
***  * **   ***** * **  *   * *******   ** 

  * ** * * *   * *** * *      * ***   *  ****   = price +(water_amount*0.6);
*******    **  *  *  * **** * *   **   * ** *****   ** ***  * = water_amount - (water_amount - 30)
  * **   *******    **  *  **  * 

     ** *   *  ***  **   *** *     *   **  **** price);
*   *  ***   *     * * *     0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

---

Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

---

Thanks!