3 like 0 dislike
11k views

Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited

edited by | 11k views

86 Answers

0 like 0 dislike
Hidden content!
#include ** * *** * *

int main()
{
* * **** * * ** * **** *** x,y;
** * * * ***** * ** * a=0,b=0;
* * ** **** *** *** * * * *** * * ***** **** *
** *** * * * * * ** * ***** **
** * ** ** * * * ** *
*** *** * * * * *** * ** Ratio: %g%%",a);
* ** * ** * *** * ** ** ** ***
* * * * * *** * ** ***** ** *** Ratio: %g%%",b);

}
answered by (54 points)
0 0
prog.c: In function 'main':
prog.c:11:14: error: unknown conversion type character 0xa in format [-Werror=format=]
     printf("%\n");
              ^
cc1: all warnings being treated as errors
0 like 0 dislike
Hidden content!
#include * *** **

int main (void)

{
***** * * ***** * * * *** * a,b;
* ** * ** ***** ** * * * ******* ** *** ** ****
***** * *** ** * ** *** ** ** * Ratio: %g%%\nFail Ratio: * * ***** * * ******

* * * * * * ****** 0;
}
answered by (-204 points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* *** **** * *

int main() {
*** * ** *** ** * **** *** a,b;
* *** **** *** * ** c;
* ** * ** ** ***** * *** ** *** %d", &a, &b);
***** *** * ** * ** * *
**** ** ** *** * * * * * p,f;
** *** * *** * *
* ** ***** * * * *
**** * * p2,f2;
*** * * ** ** * * * **
** ** * ** * * * **
**** * *** * * * ** ** * *** * * Ratio: %d%%\n", p2);
**** *** ***** ** *** * *** Ratio: %d%%", f2);
}
answered by (-120 points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* ** ** * *** *



int main() {
** **** * **** *** ** * ** a,b;
******** * *** * * c;
** ***** * * * ** * * * ** * * %d", &a, &b);
*** *** * ******* * * ******
* * *** * * *** p,f;
*** * * ** ** ** **** ** **
* **** ** * ** *** * *** * *
* * * * **** *** p2,f2;
* * * *** * *** * * *** **
***** **** * ** ** ** ***** **
* ** * * * **** ** ** *** Ratio: %d%%\n", p2);
* ****** * *** * *** ** * * * * Ratio; %d%%", f2);

}
answered by (-120 points)
0 like 0 dislike
Hidden content!
**** * ** * * * *



int main() {
* * * * ** * * *** ** * a,b,c;
**** ** **** ** * * * * %d", &a, &b);
**** * * *** *** **
*** ** *** *** * *** p,f;
* * ******* ** * * * ** ** *
** * *** ** * ********
*** * **** * ***** ** * p2,f2;
** * * * * * ** ***** * *** **
* ** ** * * ** * ** **
* ** *** ** * *** * * ** *** *** * Ratio: %d%%\n", p2);
* * * **** * *** ** * * ***** *** * ** * Ratio; %d%%", f2);

}
answered by (-120 points)
0 like 0 dislike
Hidden content!
#include ** ** ** *

int main(void)
{
*** * * * ** ** a,b,sum1,sum2;
**** **** ***** ** ** * * *** * *** * * ** *
***** * **** * * = a*100/(a+b);
** * * ** ** ** * * *** * * = b*100/(a+b);
** * ****** **** **** * * * *** * Ratio: * **** ***
* * * * * ** * ** * ** * ** * * * Ratio: * * * *

****** * *** * * * ** * 0;

}
answered by (-323 points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>



int main(void)

{
* * **** *** ** * **** a,b,sum1,sum2;
*** ** *** *** ******* ** ** *** *** ** * **
** ** * ** **** *** **** * = a*5;
* ** * *** * ** *** = b*5;
** * **** * * * * * **** (sum1>40)
*** *** * *** ** **** ***** * * * * * *** * ** ** **** * * * Ratio: %d%%\n",sum1);
*** *** ***** ** *** ******
* * ** * * * * * * * * ** *** ***** ****** * ** ** Ratio: %d%%",sum1);
* ** ** * * * * * * * *** ***** *** * **
** *** * ** *** * * ****** * * ** ** *** Ratio: ** * ** **
* **** * ** * *** * *
*** * **** ** *** * * *** ** * ****** * * ** * * * Ratio: %d%%",sum2);
** * **** *** *** * ** ** * * 0;



}
answered by (-323 points)
0 like 0 dislike
Hidden content!
** **** * * *
int main(void)
{
* * *** * * * * ** *** a, b,success, fail ;
** * ** * * * *** * * *** ** *** * * ** * * *
* * * ** * * *** ** **** * ***
*** ** ** * * * * * * * *
* ** * * ** * * ** * * * ** *** * Ratio: %g%%\nFail Ratio: * **** ** success, fail);
* * * ** * ** 0;
}
answered by (-304 points)
0 0
prog.c: In function 'main':
prog.c:5:13: error: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Werror=format=]
     scanf("%d%d", &a, &b);
             ^
prog.c:5:15: error: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Werror=format=]
     scanf("%d%d", &a, &b);
               ^
cc1: all warnings being treated as errors
0 like 0 dislike
Hidden content!
** * *** * ***



int main() {
* * ** * * * * a,b,c;
*** ** *** *** ******* * *** %d", &a, &b);
******* *** *** **** * ** *
** ** * *** ** * * ** * * p,f;
** * ** *** *** ** *
* ** * ** **
** ***** * * * * ** * **** p2,f2;
** *** *** * * * *** ** *
* * * * **** * ** *** ***** *
* * ** **** * ** * ******** * * * * Ratio: %d%%\n", p2);
* ** ** ** ** *** *** * * * * * Ratio; %d%%", f2);



}
answered by (-120 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>



int main(void)

{
* * ** * ** * ** **** * a,b,sum1,sum2;
** * **** ***** *** ****** * * * **** * * * ***** *
* * ****** * * ** ** **** ** = a*5;
******* * ** *** ** * = b*5;
* * *** ***** * * (sum1>40)
** * * * ** ** * **** ** * ** * * * ** * * * ** * ** ****** Ratio: %d%%\n",sum1);
** *** *** ** * **** * * ***
* ** *** ** * ** **** ** * ******* * * ** *** ** * ** * Ratio: %d%%",sum1);
* *** * ***** *** ** **** ** *
**** ** ** * *** * ** * * ***** * ** * * *** ** *** * ** * ** Ratio: **** ** *****
* * * * * ** *** *
** * *** *** * * ** *** ** *** ** * * * * ** Ratio: %d%%",sum2);
* * * ****** * * * **** 0;



}
answered by (-323 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.26
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users