3 like 0 dislike
12.5k views

Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited

edited by | 12.5k views

86 Answers

0 like 0 dislike
Hidden content!
#include **** **** **

int main()
{
* * ** *** * ** x,y;
* * *** ** ***** ** ** * a=0,b=0;
* * ** ** ** *** ** * * ** *** * ** ** *** *
** * **** ** * ** * *** **
* * * **** * ** ***** **
***** * ****** ** ** *** *** ** Ratio: %g%%",a);
* ******* ** * ** ** *** **** **
* * *** **** * *** **** * * ** Ratio: %g%%",b);

}
answered by (54 points)
0 0
prog.c: In function 'main':
prog.c:11:14: error: unknown conversion type character 0xa in format [-Werror=format=]
     printf("%\n");
              ^
cc1: all warnings being treated as errors
0 like 0 dislike
Hidden content!
#include * ** ****** *

int main (void)

{
** * * * *** * * ** ** a,b;
* ** **** ** ***** ** * * * * **** * * ** * * ** * ***
* * * * **** ***** * ** ** Ratio: %g%%\nFail Ratio: * * * ** * * * * **

** **** * *** * * ** *** * * 0;
}
answered by (-204 points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* * ****** *

int main() {
** ** * *** * ***** ***** a,b;
* ** ***** ** * * * ** *** * c;
**** ** * * **** * * ** * * %d", &a, &b);
* ****** ** *** * **** ** *
** * *** * * * ***** p,f;
*** * * * ** * * * * ****
****** **** ***
*** ** *** * * ** *** p2,f2;
* * * * * *** * ***** * * ***
**** **** * * ** ** *
**** ** ** * * * ** ** * **** Ratio: %d%%\n", p2);
*** * * *** ****** ****** * Ratio: %d%%", f2);
}
answered by (-120 points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
* ** * **



int main() {
***** * * *** *** *** * a,b;
*** ** * ** *** * * *** c;
** * *** ******** ** * ** * * %d", &a, &b);
* * *** * * * * ** *** *
* ** ** ****** * * *** * p,f;
* * * * *** ** ***
*** ** ** * * *** ******
** * ** * * ** * p2,f2;
* * ** * ** * * **
***** ** * ** * **** * * * *
** * * * * *** * * * * * ** Ratio: %d%%\n", p2);
* ***** * * * ** * ** ** * Ratio; %d%%", f2);

}
answered by (-120 points)
0 like 0 dislike
Hidden content!
* ** ****



int main() {
** * *** ** *** * ** a,b,c;
*** * * ******* * ** ***** **** ** %d", &a, &b);
* ** *** * * *** **** *
*** ***** **** * *** p,f;
* ** * * * *** * *** *
* *** *** ** * * *** **
** * ***** * ** *** p2,f2;
* ** * **** * * * * ** *
* * ****** * ** * **** * **
** * * ** * * ** * ** * * ** **** Ratio: %d%%\n", p2);
* * * ** * ** ** * *** * *** Ratio; %d%%", f2);

}
answered by (-120 points)
0 like 0 dislike
Hidden content!
#include *** ** *** * *

int main(void)
{
******* ** ** **** * *** * a,b,sum1,sum2;
*** **** ** * ** ***** ** * * *** ***
** * ** * **** ** ** = a*100/(a+b);
* * * * * ** ** ****** ** = b*100/(a+b);
** * *** ** *** ** ** * * ** * * Ratio: * * *******
* *** **** ** *** * * * * *** Ratio: * **** * *

**** ** * * * 0;

}
answered by (-323 points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>



int main(void)

{
** * *** *** **** * a,b,sum1,sum2;
*** *** * * **** ** * * ** ** *** * *
* * ** **** * ** ** * = a*5;
**** ** ** ** *** * * * = b*5;
* * **** *** ** * (sum1>40)
* * ** * *** ** * *** * ** ** **** * ** **** ** ** * *** * ** Ratio: %d%%\n",sum1);
* *** ** ** * * ***** ****
* * ** * * * **** * * *** ******* ** ** * * * * ** Ratio: %d%%",sum1);
* *** * * * * ** * **** * **
* *** * ** * * ** * * ** * * ** ** * * ** ***** *** ** * * Ratio: * ***** * **
* **** *** * **** ** ** **
** **** * ** ** *** **** * * * ** * ** * * *** *** *** Ratio: %d%%",sum2);
** ** ** ** ** * * * * ** 0;



}
answered by (-323 points)
0 like 0 dislike
Hidden content!
* ** * ***** * *
int main(void)
{
* * *** *** * *** * *** a, b,success, fail ;
** * ** ** **** * **** ** ** **** *** *** ** ***
** * ** * ****** * * * ****
* *** * *** *** ** * *** *** *
* * **** ** * * ** **** **** * * ** Ratio: %g%%\nFail Ratio: ** * ** success, fail);
* * ******* * ** * *** 0;
}
answered by (-304 points)
0 0
prog.c: In function 'main':
prog.c:5:13: error: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Werror=format=]
     scanf("%d%d", &a, &b);
             ^
prog.c:5:15: error: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Werror=format=]
     scanf("%d%d", &a, &b);
               ^
cc1: all warnings being treated as errors
0 like 0 dislike
Hidden content!
* *** * * **



int main() {
* ** ** * ** ** ***** a,b,c;
** * *** ** **** * ** ** * * %d", &a, &b);
** *** * * *** * * **
***** *** ** ** * ** * ** p,f;
* ** ** * ** ******
* * * * ** * * * *** * *
*** ** **** * * ***** ** *** p2,f2;
* * * * * *** * * ** ****
*** * *** * * * * *** * *
*** * * * * ** *** **** * ** * * Ratio: %d%%\n", p2);
**** ** ** *** * ** ** * * ** * Ratio; %d%%", f2);



}
answered by (-120 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>



int main(void)

{
*** * **** * * * *** a,b,sum1,sum2;
**** * * ** ** ** **** ******* ** * * * * * * * *
** * ** * **** * = a*5;
***** ** *** *** * ** * = b*5;
**** * ** **** * * (sum1>40)
* * * * * * * *** *** ** * * ** *** * * * *** *** Ratio: %d%%\n",sum1);
** *** ** * ** ** **** **
* * * * ** ****** ** ** ** ** * ** *** **** * *** * Ratio: %d%%",sum1);
* ** *** * * ** * *** * ** *
** ***** *** **** ** * * * **** * * *** * ** * ***** * * Ratio: ****** * * *
* ** ********** ** * *
**** ** **** * ***** * ** ** * *** ** * ********* **** *** * Ratio: %d%%",sum2);
* * ***** **** * ** 0;



}
answered by (-323 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.58
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users