3 like 0 dislike
12.2k views

Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited

edited by | 12.2k views

86 Answers

0 like 0 dislike
Hidden content!
#include ** ** * **

int main()
{
*** ***** ** * ** * x,y;
** *** * **** * * *** ** a=0,b=0;
* ** **** * * * ** *** * * *** * ** *** ** * **********
** *** * * ** * * * *** * ** * ****
** *** * * * * * * ***
* *** *** ****** * *** * * * **** Ratio: %g%%",a);
* * * **** ** * *** * ***** **** **
* *** * * ** *** * * * **** Ratio: %g%%",b);

}
answered by (54 points)
0 0
prog.c: In function 'main':
prog.c:11:14: error: unknown conversion type character 0xa in format [-Werror=format=]
     printf("%\n");
              ^
cc1: all warnings being treated as errors
0 like 0 dislike
Hidden content!
#include ** * * *

int main (void)

{
******* * * *** * * ** * * a,b;
** *** ** ** * * * ** * ** *** * * * * **** *** * * **
** * * * * *** * ** * ** ** Ratio: %g%%\nFail Ratio: ** * **** ** **

* ****** * * * * *** ** * 0;
}
answered by (-204 points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
*** * ***

int main() {
*** *** ** ** ** *** * a,b;
* * ** * ** **** **** * * c;
* * *** *** * ** *** * ** %d", &a, &b);
* * * *** * * ***
* * * ** * * * * p,f;
* * *** * * ******** * *
* * ****** * * * * *
***** *** * ** *** * **** p2,f2;
* * ** *** * * **** *** *
** ** *** * * *** **** ***
* ***** **** **** ** * * ** * Ratio: %d%%\n", p2);
* * ** **** * ** * *** ** ** Ratio: %d%%", f2);
}
answered by (-120 points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
** ** * **** **



int main() {
* ** ** * ** *** * ** a,b;
** *** * * * ** * **** c;
* *** **** * ** ** * * * *** * * ** * * %d", &a, &b);
***** ** ** * ** * *
**** * ** ** ** **** p,f;
* ** ** ** ** * * ***** ** * *
** * * ** * *** * * * ***
** * * *** ** ** ** * * p2,f2;
* ** * ***** * ** * *** *
**** * * ** * * ** * **** **
* ** ** ** * *** * ** ** ** Ratio: %d%%\n", p2);
*** * * * ****** ******* * * ** * Ratio; %d%%", f2);

}
answered by (-120 points)
0 like 0 dislike
Hidden content!
** * * ** * *



int main() {
* * ** * ** **** ** a,b,c;
**** * ** * ****** *** * * * %d", &a, &b);
** ** * ** * * ** * *
* * *** *** * * ***** ** p,f;
* * ** * * * * * ** * ***
** ** ** * ** ** * * * * *
*** * **** **** * * * * ** p2,f2;
*** **** ** ** *** * *** * *
* *** ** * ** * *** * * *****
* **** * * * * * **** * **** ** Ratio: %d%%\n", p2);
* ** * ** * * * * * ** * ** Ratio; %d%%", f2);

}
answered by (-120 points)
0 like 0 dislike
Hidden content!
#include * ** * *** **

int main(void)
{
* * * ******** * * * a,b,sum1,sum2;
** * ** * * ** ** *** * * **** * * ***** ** ** ** **
*** * * * **** *** * = a*100/(a+b);
**** * ** * * *** * = b*100/(a+b);
* * * * * *** ********* ** *** Ratio: *** * * **
* ** * * ** * ** * *** * **** Ratio: * **** **

* * * * ** * * *** ** * 0;

}
answered by (-323 points)
0 0
-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>



int main(void)

{
* * * ******** ***** a,b,sum1,sum2;
** ******** * * * *** ***** * ** *** *** ***
*** * ** * ** * * = a*5;
* ** ** ** * ******** ** = b*5;
** * ** *** ** ** ** ** (sum1>40)
* * * ** ***** * * * * ** **** * *** ***** ** * ** * * ***** * Ratio: %d%%\n",sum1);
**** *** * * * **
* ** ***** * * * *** * ** ******** ** ** * *** *** *** * Ratio: %d%%",sum1);
* * ****** ** * ** ** * * *** *
**** ** ** * * * * *** * * * ** *** ** * * * * *** Ratio: *** **** *
** * *** * ** * *** *
* **** * * ***** * * * * * *** ** ** * * * * ** * * * * Ratio: %d%%",sum2);
* * * * * * * ** ** * * 0;



}
answered by (-323 points)
0 like 0 dislike
Hidden content!
*** * ***** ***
int main(void)
{
** * * ** ** ** * * a, b,success, fail ;
** * ** **** ***** *** **** ***** * ** ******
*** ** * ** * * * ** * * * *
*** ** * * * * *** * ** * **
* ***** *** **** * * * ***** * ** ** * Ratio: %g%%\nFail Ratio: * * * ** *** success, fail);
*** **** ** ******** * * 0;
}
answered by (-304 points)
0 0
prog.c: In function 'main':
prog.c:5:13: error: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Werror=format=]
     scanf("%d%d", &a, &b);
             ^
prog.c:5:15: error: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Werror=format=]
     scanf("%d%d", &a, &b);
               ^
cc1: all warnings being treated as errors
0 like 0 dislike
Hidden content!
* ** * ** * * ** *



int main() {
* ** * * * ** * ***** ** a,b,c;
* *** * **** * **** * %d", &a, &b);
* * ** ** *** * * ****
* ** ** *** * *** p,f;
*** * * * ***** ** *
* ** ****** *** * * * *
* * * * ** * ** * * p2,f2;
* ** * * * * * * ** **** *
**** ** *** ** ** * * *
** *** ** * * * * * * ** ** * Ratio: %d%%\n", p2);
* * *** *** * * * * ****** Ratio; %d%%", f2);



}
answered by (-120 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>



int main(void)

{
*** ** * ****** ****** *** * a,b,sum1,sum2;
* * * *** ** ** ** ** * * * * * * ** ** * *
*** ***** ** * * *** * * = a*5;
* * ** ** ** * *** = b*5;
*** * ** * *** * **** ** (sum1>40)
** *********** * ** ** * *** ** ******* ***** * ** *** Ratio: %d%%\n",sum1);
**** ***** * ** *** * *** *
*** ** **** * ******** ** * * * **** ** ** * *** ** * Ratio: %d%%",sum1);
** * * ** * ** ** * ** **
** ** ** * * ** * * * ** ** * *** *** * ** ** * ** ** ** * Ratio: ** * * *******
***** * *** * * ** **
* ** **** * * *** * * **** * * ** * * ** * *** * Ratio: %d%%",sum2);
*** * ** * ** *** ** * 0;



}
answered by (-323 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.130.213
©2016-2025

No related questions found

12,783 questions
183,442 answers
172,219 comments
4,824 users