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AD 20161027 期中考 6
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目前的所得稅累進稅率為：
0-520000 5%
520001-1170000 12%
1170001-2350000 20%
2350001-4400000 30%
4400001-10000000 40%
10000001- 45%
請撰寫一程式，由使用者輸入所得後計算出所得稅輸出。
sample input:
1000000
sample output:
83600
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
points)
ID: 15427 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
reshown
Oct 27, 2016
by
Shun-Po
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * * *** * **** * * x=0,i=0;
* ** * * * * ** * *
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}
answered
Oct 27, 2016
by
410523005
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i,j,a,b,c,d,e;
* * * * * ** * * * * ** *** ** * ** ** * * **
if(i <= 520000)
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return 0;
}
answered
Oct 27, 2016
by
楊傑宇
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Hidden content!#include * * * * *
#include * *** ** * * * **
int main()
{
** * * * * * **** * num;
*** ** ** * ** ** * * * &num);
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}
answered
Oct 27, 2016
by
610537002
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
* * * ** * ** * * * ** i=0,
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** * ** ** ** * * ** 0;
}
answered
Oct 27, 2016
by
410423016
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-170
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Hidden content!#include * * ** * * * *
* * *** * *** * * **
int main(int argc, char *argv[])
{
* *** * * * * * * * * * *** i,j,n;
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* * *** * ** * * ** * ****** ** * * *** * * * *** * * ** = n*0.05;
** * * * ** * ** * * * if(n ** 1170000)
* * * * ** * *** * *** ** ** * * * * **** * = (n - 520000) *0.12 + 26000;
* * * ** * ** ** ** * if(n * * * 2350000)
* ** ** * * ** * * * ** ** * ** * **** * * ** * * *** * * = (n - 1170000) *0.2 + 26000 + 78000;
* * * * ** * * * if(n ** * * 4400000)
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* * * ** * * ** * 0;
}
answered
Oct 27, 2016
by
Dhgir.Abien
(
-216
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Hidden content! * * * *
int main()
{
* ** * ** * ** A,B,C,D,E,F;
* ** * * ** **** ** ** * *
* ** * ** * (A<=520000)
* ** * * * * * *
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* * ** *
* * ** ** * * * * * * * * * * ******** *** * ** * *** * ** ***** ** *
*** * ** ** * * *** ****
}
answered
Oct 27, 2016
by
chen
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-102
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Hidden content!#include ** ** **** * *
#include * ** ** **** *
int main()
{
**** * * * * ** ** num;
* * * * * * * * ** * * *** * * ** *** * * &num);
*** *** * * * ****
* ** * * * * >= 10000001)
** * ** ** * * *
* ** * * * *** * * * *** ** * * * = ** ** ** * 0.45;
* * *** * ** * * * *
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** * * * * ** * * * *
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* * * * * if (num >= 2350001)
** * * * * ****
* * * *** * ** * * * * * * ***** *** ** = * ** ** ** * * *0.3;
* ** * * *
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* ** * *** ** * *
* * * * * * ***** * ** **** = ** *** * * * *0.2;
* * ** *** * ** * * *
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* * * * * *
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* * * ** * * * *
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* * * ** * * * **** * * * ** * *** *** num);
**** * * * * * * **** * ** ** * ****
* *** * * * * 0;
}
answered
Oct 27, 2016
by
610537002
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Hidden content! * * * ** * *
int main()
{
*** * * * *** A,B,C,D,E,F;
*** * * * ** * * * * * ** * *** *** *
if (A<=520000)
*** ** * * * ** *
* * * * * ** if (A<=1170000)
* * * ** * * * ** * * * ** **
* * * * * *** if (A<=2350000)
* * *** * * * ** * * ** * * *** * *
* * ** ** * * if (A<=4400000)
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* ** * * * **
* ** *** * * * * * * * ** * ** * ***** *** * * *** * ******* * * * * ** * * * ** * ** * *
* * * ***** * * * ** * **** *** * **
}
answered
Oct 27, 2016
by
chen
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Hidden content!#include<stdio.h>
* * ** * * * *
int main()
{
* *** * * * ** i;
* ** * * *** * * a;
** **** * * * * * ** * * *** * * * *
* ** * ** * * *** * ** * * *
* * ** * ** ***
* *** * ** * ** *** * ** **
** ** * * ****** * * * ** * ** * * * *
** * * ** ** * * * **
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{
* * * ** * * * ** ** ** * *** * ** ** *
* ** * * *** * * * ** ** * ** * * ** * * *** *
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** * ** * * * if(i<=2350000)
** * ** * ** ** * *
** * ** ** * * * * *** ** * ** * * * **
* * ** ** * * * ** * * ***
** ****** * ** ** *
** ** * ** **** * *** if(i<=4400000)
{
* * *** **** ** * * **** * * * * * * 470000;
* ** * * *** * ** * * ** * ** *** ** **
}
** * ** * * if(i<=10000000)
*** * * ****** ** * * **
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{
** * * *** ** ** * * * * * *** * * * * *
* * * * *** * * *** ** *** * * * * * * * *
}
* *** * * * * * * ** 0;
answered
Oct 27, 2016
by
jack2234567
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int in,tax;
* * ** * * * ** * * **** * * * * * ** ** *** *
*** * ** *** * *** * * * * *****
* * * * * * * * ** *** * * ** **
* * * * * * * * * ** ** if(in<1170000)
* * * * * * *** * *** ** * ** ** * * * **
* * * ** * * * *** * if(in<2350000)
* * *** ** * * * * * * * * * *** ** * * * * *** * *
* * *** * * * * * *** if(in<4400000)
** ** * * ** ***** * * ** * * * * * * * * * * * ** ** ***
* ** * *** * * * * * * * * if(in<10000000)
******** *** *** * ** * *** * * ** * * * ** * ** * * *** * * * **** * *
* * * * * * ** * * * * * *
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* * * ** ** * * * * ** * * * ** *** * * *** ** *
** * * * * * ** ****** * * * * * 0;
}
answered
Oct 27, 2016
by
steven0221
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AD 20161027 期中考 10
[Exercise]
Coding (C)
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asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
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(
18k
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ID: 15448 -
Available when:
2016-10-27 18:30:00
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Due to:
2016-10-27 21:00:00
|
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AD 20161027 期中考 9
[Exercise]
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in
2016-1 程式設計(一)AD
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(
18k
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ID: 15445 -
Available when:
2016-10-27 18:30:00
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AD 20161027 期中考 8
[Exercise]
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2016-1 程式設計(一)AD
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(
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ID: 15441 -
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73
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AD 20161027 期中考 7
[Exercise]
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in
2016-1 程式設計(一)AD
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(
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AD 20161027 期中考 5
[Exercise]
Coding (C)
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2016-1 程式設計(一)AD
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18k
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ID: 15421 -
Available when:
2016-10-27 18:30:00
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2016-10-27 21:00:00
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