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AD 20161027 期中考 6
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目前的所得稅累進稅率為：
0-520000 5%
520001-1170000 12%
1170001-2350000 20%
2350001-4400000 30%
4400001-10000000 40%
10000001- 45%
請撰寫一程式，由使用者輸入所得後計算出所得稅輸出。
sample input:
1000000
sample output:
83600
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
points)
ID: 15427 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
reshown
Oct 27, 2016
by
Shun-Po
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
** * ** * * * x=0,i=0;
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* * * * * ** * * * *** ** * ** * 0;
** * * ** * *** *
}
answered
Oct 27, 2016
by
410523005
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i,j,a,b,c,d,e;
* * * ** * * * *** ** * * * * * ** ** * ** *
if(i <= 520000)
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else if(i <= 1170000)
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return 0;
}
answered
Oct 27, 2016
by
楊傑宇
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Hidden content!#include * * * *
#include ** ** * * ** *
int main()
{
*** *** * * * *** num;
* * * * * ** ** * ** * ** ** * * * * &num);
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**** *** ** * * **
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* * ** * * ** * * * ** ****** * * = * * * ** *** * 0.4;
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* * * ** *** * ** * * *** ** * num+1);
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* ** * * * * * * *** 0;
}
answered
Oct 27, 2016
by
610537002
(
-110
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
** * ** * ** * ** * * * * ** i=0,
** * ** * * * * * * * * ** * * * ** * * *
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** * *** * * * = ((i-520000)*12/100)+(520000*5/100);
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** ** * * ** *** * * **** if(i>=10000001)
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* * ** * * * * * * * * * * ** ** **
* * * * * * * * * ** * * ** ** ** * * * **** *
* * * * * * * ** *** ** 0;
}
answered
Oct 27, 2016
by
410423016
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-170
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Hidden content!#include * * * * ** *
* * * * * * ** *
int main(int argc, char *argv[])
{
* ** *** * * * ** **** i,j,n;
** * * ** * * **** * * * *** * k;
* * * * * * * ** * * * ** ** * * * * ** * * *
* * * ****** *
* ** ** * * * * * ** * **** * * * * 520000)
* * * * * *** * ** ***** ** * *** * * * * * * * ** * * = n*0.05;
* * **** * ** * ** * if(n * 1170000)
* * * * * * * ** * * * * * * *** *** * **** * ** * = (n - 520000) *0.12 + 26000;
* * ** * * ** ** ** * * * * * * if(n * *** 2350000)
*** * ** * * ** ** * * * * * * * * * = (n - 1170000) *0.2 + 26000 + 78000;
* * * * *** ** *** * * if(n * * 4400000)
** * * ** * ** * **** * * * * * * ** = (n - ** *0.3 + 26000 + 78000 + 236000;
* ** **** * ** * ** * ** * if(n * ** * * **
* ** *** * * ** * * * *** * * * * ** ** * * = (n - * *0.4 + 26000 + 78000 + 236000 + 615000;
* * * *** * * * * * * **
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* ** * * ** * * * ** * * * *** * * **
* * * ** * * ** *** * * * * * * ** * * * ** * * * ** **** **
* ** ** * * * *** * * * 0;
}
answered
Oct 27, 2016
by
Dhgir.Abien
(
-216
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Hidden content! * * * * * *
int main()
{
** *** * ** * * A,B,C,D,E,F;
* ** **** *** ** ** * * * * ** * * *
*** * ** ** ** * (A<=520000)
** * ** ** * * * *
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********** * * ** ** * * *
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** ** * ** ** * * if (A<=4400000)
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* ** ** * * * * if (A<=10000000)
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* * * ** * ** * * ** * ** ** * * ** * ** ** ** * * ** * * * *
* * ** * **** * * * * * ** *
}
answered
Oct 27, 2016
by
chen
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-102
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Hidden content!#include ** ** *** *
#include ** * * * * *** *
int main()
{
** * * * ** ** * num;
* * ** ** * * ** ** * * *** ** *** *** &num);
*** * * **** * *
* * * * ** * ** ** ** >= 10000001)
** ** **** * * * *
** * ** *** * ** *** * ** * * ** * = ** * ** * * * * * 0.45;
* * * * ** * * * *
* * **** ** * * if (num >= 4400001)
* *** ** *** * ***
*** ** ** ** * * * * * *** * ** * ** = * * ** * ** * * * 0.4;
* ** * ** * * * **
* * ** * * ** if (num >= 2350001)
***** ** * * *
* * * *** ***** * * * * * * * * = ** * * ** * * *0.3;
**** * * *** * *
* * ** * * * ** * ****** * if (num >= 1170001)
* * * *** ** * * *
* * ** * * ** * * * * * * * = * * * ** *** * *0.2;
* ** * * * **** * ****
** * ** * ** ** * if (num >= 520001)
* * * * * *
* * ** * ** * * * * * * **** ** = * * * * ** *0.12;
*** ** **** ** * **
*** * ** * * ** * if(num >= 0)
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* * * * ** **** * ** *
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* ** * * ** * * * ** *
* * * *** * * **** * * * * * * num);
** ** * ** * * * ** *** * ** *** * * * * **
** ** * *** * * * ** * * 0;
}
answered
Oct 27, 2016
by
610537002
(
-110
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Hidden content! * * ** *** *** **
int main()
{
* * ** * * A,B,C,D,E,F;
* * * ***** * *** ** ** *** ** ** *
if (A<=520000)
* ** * * * *
* *** ** * * if (A<=1170000)
*** * * * * * * * * * * ** **
* * * * * if (A<=2350000)
** ** * * ****** * *** * * * * * ** *
* *** ** *** if (A<=4400000)
* * * *** ** * ** * *** * * * * * * ** ** * *** * *
** * * *** * if (A<=10000000)
** * * * * * **** * * * * ** ** ** * * * **** **** ** * ** * *
*** * * * * **** *
***** * ***** * ** ** * * ** * ** * * * * * ** * ** * *** ** *** * * **** *
* * * * * * * * * * * ** *
}
answered
Oct 27, 2016
by
chen
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Hidden content!#include<stdio.h>
* ** * * * * * *
int main()
{
* ** * * * * * i;
* *** * ** ** * * * a;
** ** *** ** *** * ** * ** *** ** *
** * **** ** ** * * *
* * * * * *
* ** * ** ** ** * ** * *
* * * ***** ** ** * * ** ******* * ** * *** **
* * **** * **** * * *
* * ** * * * * * * if(i<=1170000)
{
**** ** ** * ** * * * * ** *** * *** *** *
* *** * * * ** * * * * ** ** ** * * * * ** **
** ** ** * * **
* **** * * **** * * * * if(i<=2350000)
* ** * * * * * *
* * * *** * *** ** * * *** **** *** * ** *
* *** * ** * * * * * **** ** * * * * *
*** * * * * * * *** * *
* *** * * ** * if(i<=4400000)
{
* * * * ** ** 470000;
** * * * ** * * ** * * *** ** * * * ** *
}
* *** * * ** * *** if(i<=10000000)
* * * * * ** ** **
**** ** * * * * **** * *** * ** * ** * *
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** * * * *
**** * * * ** * **
{
** * * *** * ** * ** ** * * **
* * * *** * * * ** * * * ** * * * * * ** **
}
* ***** * * * ** * * * 0;
answered
Oct 27, 2016
by
jack2234567
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int in,tax;
* * * * * * * *** * * * * * *** * * * * ** * * *** *
** ** * * * * ** * * * ** * ** *
* ** * * **** * * * * * * ** * *
*** * ** * * * ** * * * if(in<1170000)
***** **** * * * ** ** * * * * ** * * * * ***
** * * * * ** if(in<2350000)
* * ** * * ** *** * ** ** ** **** * ** ** *
** * *** * * * ** ** * **** * if(in<4400000)
* * * ** ** ** ** * * * * * * * * * * * * * * * ** ** *
********** * ** * * * * * if(in<10000000)
** ** ** *** * *** * ** * * * * *** * * * * * * * * ** ** **
* * * * ** ** * ** **
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* * * * *** **** * *** * * * * * * ** **
* ** * * * **** * * * * * * * * * *
* * ***** * * * * 0;
}
answered
Oct 27, 2016
by
steven0221
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answers
AD 20161027 期中考 10
[Exercise]
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in
2016-1 程式設計(一)AD
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Available when:
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AD 20161027 期中考 9
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in
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(
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ID: 15445 -
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11
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AD 20161027 期中考 8
[Exercise]
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(
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AD 20161027 期中考 7
[Exercise]
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in
2016-1 程式設計(一)AD
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AD 20161027 期中考 5
[Exercise]
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(
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Available when:
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