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AD 20161027 期中考 6
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目前的所得稅累進稅率為：
0-520000 5%
520001-1170000 12%
1170001-2350000 20%
2350001-4400000 30%
4400001-10000000 40%
10000001- 45%
請撰寫一程式，由使用者輸入所得後計算出所得稅輸出。
sample input:
1000000
sample output:
83600
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
points)
ID: 15427 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
reshown
Oct 27, 2016
by
Shun-Po
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * * * * * *** * *** x=0,i=0;
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}
answered
Oct 27, 2016
by
410523005
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i,j,a,b,c,d,e;
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return 0;
}
answered
Oct 27, 2016
by
楊傑宇
(
-202
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Hidden content!#include * * * * **
#include * * ** *
int main()
{
* * *** * * num;
*** ** * * ** * * ** ** ** * *** * * &num);
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*** * * * * * * * **** * * 0;
}
answered
Oct 27, 2016
by
610537002
(
-110
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
* ** * ** * * * * * i=0,
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** *** * * ** ** ** * *** * * * 0;
}
answered
Oct 27, 2016
by
410423016
(
-170
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Hidden content!#include * *** **
* * * * * * * ***** **
int main(int argc, char *argv[])
{
**** * * * ** * ** * **** i,j,n;
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** * ** * * * * * * * * * if(n * 1170000)
* *** ** ** * * * ** * **** * *** * * * * * * * * = (n - 520000) *0.12 + 26000;
* * * * * * * * * **** ** if(n * * 2350000)
* * * * * * * ** * * * ** *** * * * ** ** * ** * * = (n - 1170000) *0.2 + 26000 + 78000;
* ** * * ** * * * * ** if(n * 4400000)
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*** ** * * ** * ******** * * 0;
}
answered
Oct 27, 2016
by
Dhgir.Abien
(
-216
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Hidden content!* * * ** **** * ***
int main()
{
*** *** * ** A,B,C,D,E,F;
* ** *** ** * * * * * **** * * * ** * * ***
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* * ** *** ** * *** * *** * ** *
}
answered
Oct 27, 2016
by
chen
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-102
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Hidden content!#include * * ** * ** * ***
#include *** * ** * * *
int main()
{
**** **** ** ** * * ** num;
** ** * * * ** * * * &num);
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*** ** * * * *** * * * * * * * * * num);
** * * * ** * * * * **** *** ** * * * **
** * * * * ** *** * 0;
}
answered
Oct 27, 2016
by
610537002
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Hidden content! *** * * *** * *** **
int main()
{
** * ** A,B,C,D,E,F;
* *** * * **** * ** * *** * ** ** *
if (A<=520000)
* ***** *** * * **
** ** * ** * * ** if (A<=1170000)
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* * * **** * * * if (A<=2350000)
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** **** * * ** * if (A<=4400000)
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* * ** ** * *** * * ** ** * * ** *
}
answered
Oct 27, 2016
by
chen
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Hidden content!#include<stdio.h>
* * * ** * *
int main()
{
** * ** * ** * * * ** * i;
* ** ** * * * * ** a;
* * * * * * * * ** * * * * * * * * * * **** *** *
** ** * * * * * ** * * ** * *
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{
** ** ** * * * ** * ** * ** * * * * **
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* * **** * * if(i<=2350000)
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{
* * **** * * * ** ** * * * ** * * * * 470000;
** * * ** * *** ** **** ** * **
}
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** * * * * ** *
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** * * ** *
{
*** ** ** * * * * * ** * * * * * *
* * * ** ** * * * * * ** ** *** * * * *
}
* * * *** * * * * 0;
answered
Oct 27, 2016
by
jack2234567
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int in,tax;
* * * * * ** * * * * ** ** ** ** * * **
* * * ** * * * * * ** * * *
* ** * * * * ** * * ** ** * * **
* ** * * * * ** if(in<1170000)
* ** * ** *** * ** ** * * * * * * * * * * * **
* * * * ****** * ** * * * ** if(in<2350000)
* *** * * * * * * * * *** **** * * * *** * ** ** **
* *** * * * * * * * if(in<4400000)
* ** * * * * *** *** ** * * **** ** * ** ** * * * * * * *** * *
* * * ** * ** **** * * ** * if(in<10000000)
* * * * * *** * * * * ** * ** ** * ** * ** ** ** * * * * ** * * * * *
* ** * * ****** * * * * * **
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* * * ** * * * * *** * * ** ** *
* * * * * * * * * ** ** * ** * ** * * * * *
*** * * *** * * * * * * * 0;
}
answered
Oct 27, 2016
by
steven0221
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AD 20161027 期中考 10
[Exercise]
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Oct 27, 2016
in
2016-1 程式設計(一)AD
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AD 20161027 期中考 9
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2016-1 程式設計(一)AD
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AD 20161027 期中考 8
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AD 20161027 期中考 7
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AD 20161027 期中考 5
[Exercise]
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2016-1 程式設計(一)AD
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Available when:
2016-10-27 18:30:00
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