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AD 20161027 期中考 6
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目前的所得稅累進稅率為：
0-520000 5%
520001-1170000 12%
1170001-2350000 20%
2350001-4400000 30%
4400001-10000000 40%
10000001- 45%
請撰寫一程式，由使用者輸入所得後計算出所得稅輸出。
sample input:
1000000
sample output:
83600
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
points)
ID: 15427 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
reshown
Oct 27, 2016
by
Shun-Po
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* ** * *** * * ** x=0,i=0;
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}
answered
Oct 27, 2016
by
410523005
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i,j,a,b,c,d,e;
* * ** ** ** * *** * * * * ** * * * * * ** * ** * *
if(i <= 520000)
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return 0;
}
answered
Oct 27, 2016
by
楊傑宇
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Hidden content!#include ** *** * *
#include * ** * ** * * *
int main()
{
** ** * *** * * ** * num;
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* * * * * * * ** * *** num+1);
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}
answered
Oct 27, 2016
by
610537002
(
-110
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
* ** * ***** * * *** * * * i=0,
* * * * * * * * *** * * * * * * * ** ** ***** *
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**** ** *** * ** * * ** 0;
}
answered
Oct 27, 2016
by
410423016
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-170
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Hidden content!#include * * * *
* * ** * * * * *
int main(int argc, char *argv[])
{
* * * ** * * * *** * * * * i,j,n;
* * * ** *** ** k;
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** * * * * * ** * * * * if(n * * ***** 1170000)
* ** * **** * ** * * * * * * * * * * * * ** * ** = (n - 520000) *0.12 + 26000;
* ** * * ** * ** ** ** if(n * * 2350000)
* * ** * * ** * * * * * * * ** * * * * * * * ** = (n - 1170000) *0.2 + 26000 + 78000;
** * * * * ** ** * ** * if(n **** 4400000)
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* ** ** ** ** * ** * * * if(n ** * * *
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* * ***** * * ** * * ** ** 0;
}
answered
Oct 27, 2016
by
Dhgir.Abien
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-216
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Hidden content! * * ** * * * **
int main()
{
* * ** * A,B,C,D,E,F;
* ** ***** * * * *** ** ** ***
** ** ***** ** * (A<=520000)
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* * ** ** * ** * if (A<=1170000)
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* * * * * * ** * ** * ** *** * **
}
answered
Oct 27, 2016
by
chen
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-102
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Hidden content!#include * * * *****
#include * **** * ** * ** **
int main()
{
* *** * * * *** * * ** num;
* ** ** ***** ** ** * * * *** * * * * * ** &num);
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* * ** * * * ** ** >= 10000001)
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* * *
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* * * * * ** **
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* * ** * ** * * * *** * **
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* * *** *
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* ** * * * * * ** * * ** * * * num);
* * * * * ** * *** * * * * * * * * ** *
** * ** *** * * ** * 0;
}
answered
Oct 27, 2016
by
610537002
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Hidden content! * * * * * * ** * * *
int main()
{
* * * ** * * ** A,B,C,D,E,F;
*** * * * * ** * * * * * * *
if (A<=520000)
** * * ** * ** * *
* * * ** * if (A<=1170000)
* * * * *** * ***** * * * * * **
* **** * * ** * if (A<=2350000)
* * * ** * * * * * *** * ** *** ** **** *
*** * * ** * * if (A<=4400000)
** * ** * * ** ** * ** * * ** ** * ** ** * * * * * * *
* * * *** *** if (A<=10000000)
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** * * * * *
* * * * ** ** * * **** * ** * ** *** * ** ** * *** * *** **** *** * ****
* * * * * * *** * ** * *
}
answered
Oct 27, 2016
by
chen
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Hidden content!#include<stdio.h>
* * *** * * ****** ***
int main()
{
** ** *** * ** i;
* * * * ** * * * ** a;
** *** * * * * ** *** * ** ** * * * * *
** ** * * * * * * * * * * *
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{
* ** * *** * * * * * ** * * * **
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* * ** * * *** * *
* ** * * ** * * ** *** if(i<=2350000)
* * ** * *
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*** ** * * * * ** ** * **** ** * * * **
* * * ***
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{
* * *** * * *** * * ** ** ** 470000;
* * ** * * * *** * * * * *** * * * * ***
}
** * *** *** if(i<=10000000)
** *** **** * * **
* * *** * * * *** ** ** * *
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{
*** *** * * * * ** ** * * * *** * ** * * * **
* ** * * * * *** * ** * * ** * * * * * * * *
}
* ** * * * * * *** 0;
answered
Oct 27, 2016
by
jack2234567
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int in,tax;
* *** * * ***** * * * * ** * * * * **** * ** * *** * ** ** *
* ** * * ** * * ** * *** * * * * *
* ** * * ** ** ** *** * * ****
* * *** * *** * * * * * * * * if(in<1170000)
* * * * * ** * ** * ** * * * * ** * ** *** *
*** *** * * *** * * ** ** * if(in<2350000)
* * * * ** *** * * * * ** * * * * ** * **** * * * **
* ** **** * * * * * * if(in<4400000)
* * * **** * **** * * * * ** ** * * * * ** ** * ** * * *** **
* * * ** ** * ***** if(in<10000000)
* * * * * * ** ** * * * * ** * * * *** ** ** * * * * ** * **
* * *** * ** ** * * *
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* * * * * * * * * **** ****** * ***
* * * ** * * ** ** * * * ** ** ******* *
* * * ** * ** * * * ** * * * 0;
}
answered
Oct 27, 2016
by
steven0221
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answers
AD 20161027 期中考 10
[Exercise]
Coding (C)
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asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
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(
18k
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ID: 15448 -
Available when:
2016-10-27 18:30:00
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AD 20161027 期中考 9
[Exercise]
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Oct 27, 2016
in
2016-1 程式設計(一)AD
by
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(
18k
points)
ID: 15445 -
Available when:
2016-10-27 18:30:00
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Due to:
2016-10-27 21:00:00
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11
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AD 20161027 期中考 8
[Exercise]
Coding (C)
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Oct 27, 2016
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2016-1 程式設計(一)AD
by
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(
18k
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ID: 15441 -
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AD 20161027 期中考 7
[Exercise]
Coding (C)
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Oct 27, 2016
in
2016-1 程式設計(一)AD
by
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(
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ID: 15439 -
Available when:
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AD 20161027 期中考 5
[Exercise]
Coding (C)
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Oct 27, 2016
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2016-1 程式設計(一)AD
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18k
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ID: 15421 -
Available when:
2016-10-27 18:30:00
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Due to:
2016-10-27 21:00:00
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