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AD 20161027 期中考 6
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目前的所得稅累進稅率為：
0-520000 5%
520001-1170000 12%
1170001-2350000 20%
2350001-4400000 30%
4400001-10000000 40%
10000001- 45%
請撰寫一程式，由使用者輸入所得後計算出所得稅輸出。
sample input:
1000000
sample output:
83600
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
points)
ID: 15427 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
reshown
Oct 27, 2016
by
Shun-Po
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
** * * * ** x=0,i=0;
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* ** * * * * * * * * ** * 0;
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}
answered
Oct 27, 2016
by
410523005
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int i,j,a,b,c,d,e;
*** * ** ** *** ** * * ** ** * ** * * * ** ** * ** **
if(i <= 520000)
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return 0;
}
answered
Oct 27, 2016
by
楊傑宇
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-202
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Hidden content!#include * * ** * * *
#include ** *** *
int main()
{
** * * **** ** * * * num;
**** * *** * ** * * * * * * * &num);
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* ** * * * * *** * * * * * num+1);
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* * ** * *** * 0;
}
answered
Oct 27, 2016
by
610537002
(
-110
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
*** * * * * * * **** * * ** ** i=0,
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** * * * * * * ** * = ((i-520000)*12/100)+(520000*5/100);
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*** ** * ** * * * * ** * *** * * ** * * *
* * * * * * * * ** * 0;
}
answered
Oct 27, 2016
by
410423016
(
-170
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Hidden content!#include ***** * ** * * *
* * * ** * * * **** **
int main(int argc, char *argv[])
{
* * ** ** * ** * * * i,j,n;
*** * * * * * ****** ** ** * * * k;
* *** * * **** * * * * * *** * **** * * **
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* * * * * * * * **** * *** * ** ** 520000)
*** **** ** * * * * ** ** * **** ** * * * * * ** ** * * * * * * * = n*0.05;
* * ** * ** *** ** * * if(n * ** 1170000)
** *** * * **** ** *** * * * * * * ** *** * * *** = (n - 520000) *0.12 + 26000;
* * * * * * * *** * * * if(n ** 2350000)
* * * ** * **** * * * ** ***** * * * ** * ** ** *** = (n - 1170000) *0.2 + 26000 + 78000;
* ** ** * * ** ** * if(n *** * ** 4400000)
* * ** * * ** *** * * * ** * * *** ** *** * * * * * = (n - * *** * *0.3 + 26000 + 78000 + 236000;
* ** * * * * ** ** ** * * if(n * * * * ** *
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* * ** * * * ** * ******* * ** ** * * * * * * * * ** **
* * * * ** * * * * * * * * 0;
}
answered
Oct 27, 2016
by
Dhgir.Abien
(
-216
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Hidden content! * * ** * * * * * *
int main()
{
* * * * * ** A,B,C,D,E,F;
* ** * * ** * ** * *** * * * *** * * * *** **** * * *
** * ** ** ** (A<=520000)
* * * * * ** * **
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** * ** ** *** ** if (A<=10000000)
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* * * ** *** *** * *
}
answered
Oct 27, 2016
by
chen
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-102
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Hidden content!#include * ** * * * **
#include * ** **** *** **
int main()
{
* * * ** * * ** * * ** **** num;
* * * * ** * * * ** * * ** &num);
* * * * * ** * **
***** **** *** * * * *** >= 10000001)
* * * * ** * * *
* * * ***** ** * * *** * * ** * = * * * ** * *** * 0.45;
* * * * * * *
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* * ** * * * ** * *
* * *** * ** * * if (num >= 2350001)
*** * ** * **
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* * * ** * * * *** * **
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* * * * ** *
* * * * * * * ** **** * * * * = * * ** *** ** *0.2;
* * * * * * * *
* * * * ** * ** * * ** if (num >= 520001)
** ** ** **** * * **
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** * * * ** *
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* * * *** * * * * * * ***
* * * * ** * ** * ** * * * * * num);
*** ** ** * ** * ** * * * *** * *
* * * * * **** 0;
}
answered
Oct 27, 2016
by
610537002
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Hidden content!** * * * * * *
int main()
{
* * *** A,B,C,D,E,F;
* ***** * * ** * ********** * * * * * ** * *
if (A<=520000)
*** * * ** * **
** * * ** * if (A<=1170000)
* * ** * * * * * ** ** *** * *
* *** * * * * if (A<=2350000)
* **** * ** * * * * ** ** * * * * * * ***
* * * ** if (A<=4400000)
* * * * ** * * * * * * * ** ** * ** * ** * * ** ** * *
* ** * * * if (A<=10000000)
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* * * *
*** * **** * ** * * * * ** * * ** *** * * * * ** ** * ** * *** *** * ** *
**** * * * *** ** *** ** * * *
}
answered
Oct 27, 2016
by
chen
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Hidden content!#include<stdio.h>
* *** * * *** * **
int main()
{
* ** * * ** * * * i;
*** ** * * * * ** a;
*** * * * * * * ** * ** * * ** * ** ****
* * * * ** * ** * *** * * **
* *** * * ** *
* * ** *** *** * * ** **
*** * ****** * * ****** * * * * ** ** * * * *
* * * * * * *** * *
** * * * ** * ** if(i<=1170000)
{
** ** * * * * ** * *** *** * **** * *
* * * * * * * * * ** * ** *** ** * ** * *
* ** * * * * *****
** * * * * * ** if(i<=2350000)
* * ** ** ** ***
** * * ** ** * *** * * * * * * * ** *
* *** * * * * * * * * * ***** * * *******
* * ** * * ** * * ** *
* * ** *** ** if(i<=4400000)
{
* * * * * ** * ** *** * * * 470000;
* * ** * * * * * * * *** * * * * ** ** * ***
}
* * *** * * ** ** if(i<=10000000)
* ** * * ** **
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* ** * * ** * * * ** * *** * * *
* * ** * * * *** *
* * * * * * ** *
{
* * * * ** *** ** ** * * ** * ***
* * * * * ** * * * * * * ***** * * ** * **
}
****** ** * * * 0;
answered
Oct 27, 2016
by
jack2234567
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
int in,tax;
* * * *** ** * * * * * * * * * *
* * * ** ** *** * ** ** ** * * *
* * * * *** * ** * * * * *
** ** * * * * * * * * * * * ** if(in<1170000)
* * **** * ** ** *** * ** * * * ** * * * * *** *
** * * * * * * * if(in<2350000)
* * ** * * *** * * *** * * * * * ** * * * *
* * * ** * ** * * * * if(in<4400000)
* * * * ** *** ** * * * ** * * * * * * ** * * * ***** ** * *
* ** * *** * ** * * if(in<10000000)
** * * * * * * **** * * * * ** *** * * * * * * ** * ** * * * *
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* * *** * * * ** * * * **** ** * * * * *** * *** * * ** * * **** *** * ** * * * * **
* * * ** * * * ** ** ** ** ****** * * * * ** *
*** * * * ** * * * ** * * ** * * * ** * * **
* ** ** * * * * * * 0;
}
answered
Oct 27, 2016
by
steven0221
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AD 20161027 期中考 10
[Exercise]
Coding (C)
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asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
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(
18k
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ID: 15448 -
Available when:
2016-10-27 18:30:00
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AD 20161027 期中考 9
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in
2016-1 程式設計(一)AD
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(
18k
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ID: 15445 -
Available when:
2016-10-27 18:30:00
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Due to:
2016-10-27 21:00:00
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11
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AD 20161027 期中考 8
[Exercise]
Coding (C)
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(
18k
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AD 20161027 期中考 7
[Exercise]
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Oct 27, 2016
in
2016-1 程式設計(一)AD
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(
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ID: 15439 -
Available when:
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AD 20161027 期中考 5
[Exercise]
Coding (C)
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2016-1 程式設計(一)AD
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18k
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ID: 15421 -
Available when:
2016-10-27 18:30:00
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2016-10-27 21:00:00
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