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AD 20161027 期中考 6
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目前的所得稅累進稅率為：
0-520000 5%
520001-1170000 12%
1170001-2350000 20%
2350001-4400000 30%
4400001-10000000 40%
10000001- 45%
請撰寫一程式，由使用者輸入所得後計算出所得稅輸出。
sample input:
1000000
sample output:
83600
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
points)
ID: 15427 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
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Oct 27, 2016
by
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
** **** * * * * * **** * * * * i=0,
* * *** * ** * * * ** **** * * *** * * * ** * **
* * * * * * * * * * * * ** * * *** * * ***
**** *** * * * * * * * * * * ** * ** * ** ** * *
* ** ** * * ** * * * = i*5/100;
* * * **** * * * * * *** ** * * * **** * * * * * ** * * **
* ** * ** **** *** * * ** = ((i-520000)*12/100)+(520000*5/100);
* * ** *** * * *** * ** ** *** ** * ** ** * * * * * * * * * ** * *
*** ** * * * **** * * = * * * ** * * ** * * * * ** * * *
* ** * * * ** ** *** ** ** *** * ***** * * * **** * * **
* * * * ** ** * * = *** * ***** ** * * * * * * ** * *** *
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* * ** * * *** * * * ** = * ** * *** * *** * * * * * * ** * * * ** * * *
* * * ****** * * * ** * * if(i>=10000001)
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* * * * ** * * * * * ** * *** ** * *
* * ** ** * ** * * * * ** * ** *
** * * * * *** * * * * 0;
}
answered
Oct 27, 2016
by
410423016
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Hidden content!#include <stdio.h>
int main()
{
int money;
** *** * * * * * * input your money:");
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** * *** ** * * * * ** * * ** * *** * * ***** ** * *
***** ** ** ** * * ** ** 0;
}
answered
Oct 27, 2016
by
cityhunter0412
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-30
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
**** *** * ** * *** * ** n = 0 , tax = 0 ;
** **** * * * * * * * * * * * **** *** * * * **
* * ** * * * ** * ** *
* * * ** * * * * ** * ** n <= 520000 )
* * * ** ** ** * *
* ** * * * * * * * **** *** ** * * **** * * * * * * = n * 0.05;
*** * * * *** * * * * ** * * * * * * * *** * * ** * ** * * * * * * *
** * * * * * ** ** ** * * * * ** * ** * * * ** ** ****
**** * ** * * * ** * * * * ** * * ** ** * 0;
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* *** * * * ** * * * n <= 1170000 )
** * * * ** * * *
* * * * * * * * ** * * ** * *** * ** * = 520000*0.05+ (n-520000)*0.12;
** * * * * *** * * * * * ** ** * * **** * * * * * * * *
* * * *** * **** * * ** * * * * ** * * * * * * **** * * * *
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*** * * * ** * * *
* * * ** * * ** * * * * * *** * ** * * * * ** * * = 520000*0.05+ (1170000-520000)*0.12+ (n-1170000-520000)*0.2;
* * *** * * * * * ** * ** * * * ** * **** ** * * * * **** *** *
*** * * * ** * ** * ** * * ** * * * * * * * ** ** * *** * ** * *
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* * ** * * * ** * *** * *
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* * * * * * * * ** *** *
* ** * * *** ** ** ***** * *** * * ** ** * = 520000*0.05+ (1170000-520000)*0.12+ (2350000-1170000-520000)*0.2 + (n-2350000-1170000-520000)*0.3;
** * * ** * * * ** * * * * ** * ** * * ** * ***
* * ** * * * ** * * * * *** * ****** ** * ** * * * * * * * * ****** *
* ** * ** * ** *** * **** * *** * * * *** ** * 0;
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* *** ** *** * * * ** * n <= 10000000 )
* ** ** *** ** ** ** * ** **
* ** * * ** * ** * * * *** **** ** * = 520000*0.05+ (1170000-520000)*0.12+ (2350000-1170000-520000)*0.2 + (4400000-2350000-1170000-520000)*0.3 + (n-4400000-2350000-1170000-520000)*0.4;
* * ** ***** * * * * * * ** * * ** * * ** ** * * ** * ** * * * * * *
* * ** * * * ** ** ** ** * * *** **** *** ** * * * ** * * * *** ** ** * *
* * **** *** ** * * ** * *** * ** * * ** ** **** * * * 0;
* * ***** * * * * *
** *** **** * ** * * * * = 520000*0.05+ (1170000-520000)*0.12+ (2350000-1170000-520000)*0.2 + (4400000-2350000-1170000-520000)*0.3 + * *** * *** * * * * *** + * * **** * ** * * * **** * ***
* * ** * * ** * * * * * * * * * *** ** * ** * **
* * * * * ** * * * * * * ** * * * *** *
**** **** * ** * ** *** *** ** * 0;
}
answered
Oct 27, 2016
by
Phoenix666
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* * * * * * *** * * * x=0,i=0;
* *** * * * * **
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** *** * * * * * * * * 0;
* * ** * ** * *** **
}
answered
Oct 27, 2016
by
410523005
(
122
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Hidden content!#include * ** ** *** ** *
#include * ****** * * *
int main()
{
* * *** * ** * * num;
* ** ** ** * ** * ** * *** * * &num);
*** ** * * * * * *
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** * * * *** * *** * *
* * ** ** * * *** * * ** ***** *** = ** ** * * * * 0.45;
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* * * * * * * * ** if (num >= 4400001)
* * * ** * * ** * **
* **** * *** ** * * ** * * = * * ** * * * ** * * * 0.4;
* ** ** ** * ** * * *
** * ** ** ** ** * * if (num >= 2350001)
** * * * ** * * *
*** * * ** * * * ** * * * * * = * ** ** * * * *0.3;
* ** * * ** * * * *
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* * ** * ** * ** * *
* ** * * * * * * = ** * * * * * ** * * *0.2;
* * *
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* * * ** *
** * * * ** * * *** * * * = * * * ** * ** *0.12;
* * ** * * *** * *
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* * * * * * * * ** **
* * * * * ** = num *0.05;
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** ** * * * **** * * * **** * ** num);
*** * * ** * * * * * ** * * * * ** *** *
** * * * * * * ** * * 0;
}
answered
Oct 27, 2016
by
610537002
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Hidden content!#include *** * * ** * *
#include * * * * **
int main()
{
* * * * * * ** * * * ** num;
* *** * * * * * * ** * ** * * * * * &num);
* *** * ** *
* * * * *** * * * * >= 10000001)
** ** *** * ** *
* * * * * * * * * ** * * * * * ** = **** * * *** * * * ** * 0.45;
* **** ** ** * *
* ** * * * **** * * * if (num >= 4400001)
* * * * ** * **
* * ** * * *** * * * *** ** ** ** * ** * = *** * * * * * 0.4;
* * * * * ****
** * ** * ** ** * if (num >= 2350001)
* * * * *
** ** * * * * * * ** *** ** = * * * * *** *0.3;
** ** ** ** **
* * * * ** *** * * ** if (num >= 1170001)
* *** * * * * *
* ** ** * * * * *** ** * ** * * = * * ** * * * * * *0.2;
* * * *** * * * * *
* * * * * ****** *** * if (num >= 520001)
* * * * * * * * ***
** * * * * * * * * * * ** * = ***** * * * ** ** * *0.12;
* * * ** *** ** * *
* ** **** ** *** *** * if(num >= 0)
* * ** * * * * * *
* * * * * * = num *0.05;
*** ***** *** *
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* * *** * * * * * ** * **
** * * **** * * * * * ** ** ** * * * * * ** *** num);
* * * ** ** ** **** * * * *
***** * * ** * * * * * * 0;
}
answered
Oct 27, 2016
by
610537002
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-110
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Hidden content!#include * * ** * ** *
#include * ** ** * *
int main()
{
****** * ** * ** num;
** * * * * * ** * * ** * * * * * &num);
* * ** * ** ***
* * * * * ** * ** * >= 10000001)
** * ** * * * * * * *
* * * * ** * * * **** *** * = * * * * * ** * 0.45;
* *** * * *** * *
** * *** ** **** * ** if (num >= 4400001)
*** * * * *
** * *** * * * *** * * ** * * = * ** ** ** * * * * 0.4;
** * ** ** *
* ** * * * ** * if (num >= 2350001)
** * * ** ** * ** * *
* * * * * ** * * ** * * = * * ** *0.3;
* * *** ** * * **
* * * * * * if (num >= 1170001)
* * ** * * * ***
****** ** * ***** * * * * * * * * * * * * = * * ** * * * *0.2;
* * * * * **
* * ** ***** *** ** * ** if (num >= 520001)
* ** * ** * * ** *
* ** * * * ***** *** * * * * * * * = *** ***** * ** * *0.12;
* * * ** ** * * ***
* * **** ** **** *** if(num >= 0)
* * ** * * **
* * * * ** * * *** * = * * * * * * *0.05;
** * ** * *** * * *
* * ** * * ** * ** * *** * *
* * * * * * * ** *
***** * ** * * * * * * ** ** ** * * num);
* * * * * ** * ** *** * * * *
* * ** * ** *** * 0;
}
answered
Oct 27, 2016
by
610537002
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Hidden content!#include ** * * * * * *
#include * * * * ** ** * *
int main()
{
* * * ** * ** ***** * ** num;
* *** ** ***** **** ** * * * * * * * &num);
* ** *** * *
* * * * * ** ** * * ** >= 10000001)
* ** *** * ** **
* * * *** **** * * * * * ** * = ** * * ** * 0.45;
* * * * *** * *
** * * ** * ** ** * if (num >= 4400001)
* * * ** * ** * * * *
* ** ** *** * * * * ** * ** ***** = ** * * **** **** * * 0.4;
*** *** *** ** *** * * *
* ** * * * *** **** * if (num >= 2350001)
** * ** *** * ** *
* ** ** * * * * * **** * ** * * * * * *** = * ** * * * *0.3;
* * * * ** ** * *
** ***** * * * ** if (num >= 1170001)
* * *** * * * *
* * * *** * * ** ** = * * * * *0.2;
* * * * *** * * * *
* * ** *** ** * * ** ** if (num >= 520001)
* * * *** * * *
* * ** ** * * ** *** = * * * * * * ** *0.12;
* * * * * * **
** * * * * * * if(num >= 0)
* * * * ** * * *
** * * ** * * * = * * * * *** *0.05;
** * ** * * ** * ** *
** * * * * * * * * *** ** * * **
*** * * * * * ** * **
* ** * ** *** ** * * ** *** * ** ** num);
** ** * ** **** * * * * *** * * * *
* * * * * * * *** ** 0;
}
answered
Oct 27, 2016
by
610537002
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Hidden content!#include * ** * * * ** *
#include * ** * * * *
int main()
{
* * * * *** * num;
**** * ** * * * * * * * * ** * ** &num);
* * ** * *
* * ** * * * * * * >= 10000001)
*** * * ** ** *** *
* * * ** *** *** * ** ** * ** = ** * * ****** * * * 0.45;
** ** * * * ** * *
*** * * * * * ** if (num >= 4400001)
* * * *
* * * ** * * * * = * * * ** * * ** ** * * 0.4;
** * * * ** ***
** ** * * * * * if (num >= 2350001)
** * ** * * *
* * ** * * * * *** * * = * ** * * *** *0.3;
** * * ** * * * *
* * * * * * * * if (num >= 1170001)
* * * ** **** * *
** *** ** ** ** * *** * * * = * * * * *** * * *0.2;
* * * * *** *
* * *** ***** * ** if (num >= 520001)
******** ** * * *
* * *** * * * * ** * *** = * ** * *** * ** *0.12;
***** * * * ****
* * * * ** * ** *** if(num >= 0)
* * ** * *
*** *** ** * *** ** = * * * * * ** *0.05;
* ** ** * * * ****** *
*** * ** * * * * * * ** ** * ** * *
* *** ** * * * ** ** * **
*** ** ** ** * * *** * * * ** *** num);
* ** * * * ** * * *** * * * ** * **
* ** * ** * * 0;
}
answered
Oct 27, 2016
by
610537002
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
* * ** ***** ** ** * ** *** i=0,
* * * * * * ** * ** ** ** * * * * * *** * ** * *
** * * * * * * **** * * * ** ** * * *** * * *
* ** ** ** *** * * * * ** * *** * ** * * **** *** *
* * ** ** ***** ** * ** = i*5/100;
* *** ** * * * ** * ** * ** * * * * * * * * * *** **** **
* * * * *** *** * * ** * * = ((i-520000)*12/100)+(520000*5/100);
******* * * * * ** * * * ** * * *** *** * *** ** * * * * ** *
*** * * * * * * * ** * * * = * * *** *** ** ** ** * * * **
* * * * ***** * ** * * * * * ** ** * * ** * * ** *** * * *
** * * * **** * * * *** * * = *** * ** * * * ** * * * * * * * *
* *** * ** * ** ** *** * * * * * * * ***** * ** * * ** ***
** * * * *** * *** * ** = * * *** ** * * *** * * ** * ** * *** * * * * * * ** *
** * * * * * **** if(i>=10000001)
**** *** * * * ** = * ** * ** * ** * * * *** ** * ** * * ** ** * * * * * * ** *
** * * ** ** ** **** ** * * * ** *** * * * **
** ** * * * ** * * * ** * * *
*** * *** * *** * * * * * *** * 0;
}
answered
Oct 27, 2016
by
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AD 20161027 期中考 10
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
points)
ID: 15448 -
Available when:
2016-10-27 18:30:00
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Due to:
2016-10-27 21:00:00
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AD 20161027 期中考 9
[Exercise]
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Oct 27, 2016
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2016-1 程式設計(一)AD
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ID: 15445 -
Available when:
2016-10-27 18:30:00
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Due to:
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AD 20161027 期中考 8
[Exercise]
Coding (C)
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Oct 27, 2016
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2016-1 程式設計(一)AD
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ID: 15441 -
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2016-10-27 18:30:00
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AD 20161027 期中考 7
[Exercise]
Coding (C)
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Oct 27, 2016
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2016-1 程式設計(一)AD
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Shun-Po
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ID: 15439 -
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AD 20161027 期中考 5
[Exercise]
Coding (C)
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Oct 27, 2016
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