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AD 20161027 期中考 6
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目前的所得稅累進稅率為：
0-520000 5%
520001-1170000 12%
1170001-2350000 20%
2350001-4400000 30%
4400001-10000000 40%
10000001- 45%
請撰寫一程式，由使用者輸入所得後計算出所得稅輸出。
sample input:
1000000
sample output:
83600
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
points)
ID: 15427 -
Available when:
2016-10-27 18:30:00
-
Due to:
2016-10-27 21:00:00
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Oct 27, 2016
by
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
** * * * * ** * **** i=0,
* *** * * * * * *** * * * ** * ** * * * * *** *
* * * * * ** * * ** ** * * * ** * *** **** *
* * ** * ** * ** * * * * * ** * * * * ** * *** * *
**** * * * * ** * * * * * = i*5/100;
* *** ** * * * * ** * * * * * * *** * * * *** * * * *
** * * * ** * * ** * * = ((i-520000)*12/100)+(520000*5/100);
* * * ** * * * * * * * ** ** * * ** * *** * * * * *
* * * * ** * *** * * * = * * * * * * * * ** * * ** **
* *** ** * * * * * ** * * * ** ** **** * * * * ** * ***
* * * * * ** * * = * ** * * * ** * * ** ** * * * * * *
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* **** *** * * * ** = * * *** * * ** * * * ** * ** * * *** *** ** * * * * * *
* * * *** * * * ** * * * if(i>=10000001)
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** ** ** * * ** ** * * * ** * ** *
* * * ** *** * ** * * ** ** * * * **** **
*** * * ** * * ** * * * * 0;
}
answered
Oct 27, 2016
by
410423016
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Hidden content!#include <stdio.h>
int main()
{
int money;
* * * * * * * ** * * * * * * * input your money:");
** * * ** * * * * ** ** * ** * * * *
***** * ** * * *** * * ** * ** * * * *
** * * * ** * * ** * **** * * ** * ** *** *** *
* * ** * * * ** * * ** * ****
*** * *** * **** * ** *** ** * * * ** if(money<=1170000)
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* * ** ** * ** * *** * if (money<=2350000)
*** ** * * ** ** * * * ** * * ** ** ** * ***** ** * * * * ** * *
** * * * * * * * ** ** * if (smoney<=4400000)
* ** * * * * * * ** ** ** * * ** ** * * * * ** *** * *
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*** * * **** * * ** * if (money<=10000000)
* *** * * * * * ** * * * * * * * * ** * * * * * * ** * *** * **
** *** * * ** ** *
*** * * * ** * * * * * * if (money>10000000)
* ***** * * * ** ** * * * * ** **** * **** ** * * ** * * * ** * * * * * * *
** * ** * * * * * * ** * * * * * * ***** * *
** * * * ** * * *** * * * * 0;
}
answered
Oct 27, 2016
by
cityhunter0412
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* ** * * * * * ** * n = 0 , tax = 0 ;
* ** * * * * * * ** * * ** * **
* * * * * ** **** **** *
* * * * * * ** * **** n <= 520000 )
* * * ***** * * * *
* ** *** **** ** * * * * ** * *** * ** * * *** = n * 0.05;
* *** * * * * * *** ** ** * * * ** * * * * ** * * **
* ** * ** * * *** * * * ** * * * *** ** * * *** * ** * ** ** ** *** ** **
* * *** ** ** * **** * * * *** ** * * ***** * * * 0;
** * * ** * ** * * * * * ***
* * **** *** * ** n <= 1170000 )
* * * * * * * * * * * ***
* * * * * * * ** * * * ** * * * * * *** = 520000*0.05+ (n-520000)*0.12;
* *** * * * * * * * * * * * * * * * * ** * * * * * ** * **
** ** **** * * * * * * * * ** * * ** * * * * ** * *** ** ** * *
* * *** * * *** * * ******* * ** ** * * ** ** * 0;
*** * * ** * * * *
* * * * ** ** * ** * n <=2350000 )
* ** *** * * * ** ** *
* *** * ** * * * * ** ** * * ** * * * * * ** * ** = 520000*0.05+ (1170000-520000)*0.12+ (n-1170000-520000)*0.2;
** * ** * * * * * ** * ** * ** * * * ***** ** ** ** * *
** * * ** * * * * **** * * * * * * ** * ** ** * * *** * *
** *** * * * * * ** * * * * ** * *** * * * * * 0;
** * * * * ** *
* * * * * * ** * n <= 4400000 )
* * * ** * ** ** ** * ** **
* * * * ** * * * * * * ** * * * * ** = 520000*0.05+ (1170000-520000)*0.12+ (2350000-1170000-520000)*0.2 + (n-2350000-1170000-520000)*0.3;
* * * ** *** ** * * * ** * * * ** * *** * * * ** * *** * *** * *
* * * **** ** * * * * * * ** * * * ** * * ** * *** * * * **** ** ** * * ** *
* * ** * * * ** ***** * * * ** * * * * * * * * 0;
** * * * * * * * ** *
** * *** * * * * * * n <= 10000000 )
** * ** * * * * * * * * *
* * ** * *** ** * * * ** * * *** *** * * * * = 520000*0.05+ (1170000-520000)*0.12+ (2350000-1170000-520000)*0.2 + (4400000-2350000-1170000-520000)*0.3 + (n-4400000-2350000-1170000-520000)*0.4;
* ** * ** * ** * * * ** *** * * ** * ** * ** * * * * * * ** ****
* ** *** ** ***** ** * * * * * ** * ** * * * * * * * * * ** * * * * * * * * * ****
***** * * ** **** * ** *** * * * * * ****** 0;
** * ** * *** ** * * * *
** ** *** ***** * * * **** * * = 520000*0.05+ (1170000-520000)*0.12+ (2350000-1170000-520000)*0.2 + (4400000-2350000-1170000-520000)*0.3 + * * * ** * *** * * * * + ** *** * * * * * * * *
* * * * * * * ** *** ** **** ***** *** * * **
* * * * * * * * * * ** ** * * *** * * * *
* * ** ** * * * * * * * * * * 0;
}
answered
Oct 27, 2016
by
Phoenix666
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
* ** * * * * * * * ** * *** x=0,i=0;
** * * ** * * * *
* * * * * * * ** * * * *** * * *
* * * * * * ****
* ** ** * * * * *** * * (x<=520000)
* * * * * * * *
* * * *** ** * ** * * *
* * * * ** * * * * ** *
* * * * * * * ** ** * * * * * if(520001<=x<=1170000)
*** * ** * * *** * * ** * *
* * * * *** * ** * * ** ** **** * * * * **
**** *** ** * * ****
** **** * ***** * ** * * * * if(1170001<=x<=2350000)
* * * * * **** * **
* ** * * ** * * ** * ** ** * * * * * * ****
* * * *** * * * * ** ** if(2350001<=x<=4400000)
* * * * * * * * **** * * * *
* ** * * ** * * * * * *** * * * *** *
* * * ** * ** *** ** * * ** *
* ** * * *** ***** ** ** * * if(4400001<=x<=10000000)
** ** * * * * ** ** **
* ** * * * ** * * *
* * **** * * * **
* ** * * ** ** * * ** * if(10000001<=x)
* * * ** * ** * * * ** **
**** * * **** * * **** * * * * * * *
* * * * ** * * ***** * * **
* * * * * *** * ** *** *
** * ** * * * * * * * *
* ** * **** * * ** * ** * *** *** * * *
* ** * ** * * * *
* * * * ** * * * * * * * * ** ** ** *
* * *** * * * ** * **** * 0;
* * ** * * **** * * * *
}
answered
Oct 27, 2016
by
410523005
(
122
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Hidden content!#include * * * * * **** *
#include * * **
int main()
{
* ** * * ** * ** **** * num;
* * ** * * * * * * * * * *** &num);
* * **** ** * *** *
* ** *** * *** ** ** * >= 10000001)
* * * * ** * *
* * * * ** ** * * * * * * ***** = * * ** **** * * 0.45;
* * * * * **
****** * ** * if (num >= 4400001)
***** * * *** *
** * * ** * * ***** * ** * ** = * *** ** * ** * 0.4;
* * * * * * * ** * **
** *** ** * ** * * * * * if (num >= 2350001)
* * * ** *** * *
* *** * * * * * ** ** * * ** * = * * * * * * * ** *0.3;
* * * * * * ** * **
**** * * ** * * * if (num >= 1170001)
*** *** ** * * * ** * *
*** *** ** * * * * * ** * = * * *** * * *0.2;
*** * * * * * * *
*** ** * ** * **** if (num >= 520001)
** * * * ** * *
** * ****** * * * * ** **** * * ** = * * * * ** ** * *0.12;
** * ****** ** * * *
** * * * * * if(num >= 0)
** * * * * ** ***
*** * * * * * * = num *0.05;
** * ** ** ** * *
** * * * * * * * ** ** * **
** * * * ** * * **
* * * * *** * * * ** **** ** ** num);
* * * * * * * * * ** * ** * * *
* * * ** **** * * * ** 0;
}
answered
Oct 27, 2016
by
610537002
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Hidden content!#include *** * * * ** **
#include * **** * * *** **
int main()
{
** * * **** ** num;
** **** ** ** * * * ** * * &num);
* ** * ** * *
**** * ***** * * * ** * >= 10000001)
** * * * * * **
** * **** **** * * ** ** * * * * *** = **** * * * * 0.45;
* * * ** ** *
**** ** * * * * * * if (num >= 4400001)
** * ** * ** * * * * **
* * * * * * **** ** * ** * = * * * ** * 0.4;
** * ** * * ** * * *
* * * ** * * * if (num >= 2350001)
* ** ** * **
* * * * * ** * * * * * = ** ** * ** * *** * *0.3;
* * ** *** * * *
* ** * * * if (num >= 1170001)
** *** * *** ** *** * *
* * * ** * * * *** **** ** ** * = * * * * * * *** *0.2;
* * * * * *
**** * ** * * ** *** ** * if (num >= 520001)
** * **** * *** ** *
*** * * **** ** * ** ** * = * ** * * *** * * *0.12;
** * * * * * * *
* ** ** **** * * * if(num >= 0)
* ** * ** * * ** **
* * ** * ** * * * ** = num *0.05;
*** ** * * ** *** ** **
* ** *** * *** * * * ** * * ** *
* * * * * ** * * * * ** *
** * * ** * ** * * * * ** * * **** ** num);
* * ** * ** ** * * * ** * * ***
* ** * * ** * * 0;
}
answered
Oct 27, 2016
by
610537002
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Hidden content!#include * * * * **
#include * * ** *** ** * **
int main()
{
* * * * num;
**** ** * * * * * * * ** **** &num);
***** ** * * * *
**** **** ** ** * * * >= 10000001)
* * * * ** ** * ** *
** ** ** * * * * * * * * ** * * ** ** ** = ** * * * ** * * ** * 0.45;
* * ** ** * ** * *
* ** * * * **** * * * ** if (num >= 4400001)
* * * ** ** *
* ** * *** * * * ** ** * ** * = * ** * * *** * 0.4;
* * ** * * **** *
* * * * * ** if (num >= 2350001)
* * * * ** ** * *
* * ** * * * * * * * * * * ** ** = * * ** * * ** * *0.3;
* * ** * * * * * *
* * *** * * ** * if (num >= 1170001)
* * * * * *** * * ** *
* * * * * * ** * *** * * * * * *** = * * *** * * * *0.2;
* * * ** ** * **
* * * ** * * * * if (num >= 520001)
* **** ** *** ** **
*** * * * ** ** * *** *** **** = * ** * ** **** **** * *0.12;
* ** * * **** ** **
* * * * *** * * if(num >= 0)
* ** * * * *
** * * ** ** * * = * * * *** * *0.05;
** * * * ** * *** ****
* ** * * ** * ** * ** * * *
* ** * * ** * * *** *** * *
* ** * *** * * * * * * * ** * ** * * num);
** * * * * ** *** ** *** **** * *** * *
*** * * * *** ** * *** 0;
}
answered
Oct 27, 2016
by
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Hidden content!#include * * *
#include ** * * * ***
int main()
{
** * * ** *** * * num;
* * * * * * ** * * * ** * * * * &num);
*** * * * * * *
* * * ***** * * ** * >= 10000001)
* * * * * **** * *
* * * * ** * * ** * * * ** ** * * = * ** * * * * ** * 0.45;
* * ** ** * * * * *
* ** * * * ** *** * * * if (num >= 4400001)
* * ** * * ***
* * * *** * * ** * * ** = * *** * * ** * *** * 0.4;
* * * * *** *
* * * * * * *** * if (num >= 2350001)
* * * * *
*** ** ** ** * ** * ** ** * = ** ** * * * * *0.3;
** ****** ** * * * ** *
** * * ** * * if (num >= 1170001)
* ** * * * * ** * *
** * *** * * * * * ** * ** = ** ** * * **** *0.2;
* ** ** * *** *
* * * * * * *** * * * if (num >= 520001)
* * ** * * **** * *
* * ** * * * ** * * * * * * * * = * * **** * * * *0.12;
**** * * ***
* * * * ** * * * * ** if(num >= 0)
** ** * * ** * *
*** * **** * ** * * = * *** * * * ** *** *0.05;
* ** * * * * * *** ***
* * * *** * * * * * * *
* *** * * * * * * ** **
* * * * *** ** ** *** ** * ** *** * num);
* * * *** * ** ** * * * * * * *** ** * ** ** **
** * ** *** * * 0;
}
answered
Oct 27, 2016
by
610537002
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Hidden content!#include *** ** ** * * *
#include * ** **** * **
int main()
{
** * * * * ** * * num;
** * * * * * ******* * * ** * &num);
** * * * * * * **
* *** * * * * *** * >= 10000001)
*** * * * ******
** ** *** * * * * * * ** * * ** *** = * * * * * ** ** * 0.45;
**** ** * * * * *
** * * * * *** * * *** * if (num >= 4400001)
* * ** ** ** * * * *****
* ** * ** *** * * * * * * * * = * ** * *** * * 0.4;
* * * **** * ** *
* * * * * ***** * if (num >= 2350001)
* * ** ** * * ** * * *
* ** ** * * * * * * *** = * ***** * ** * ** *0.3;
* * ** *** ** * * * * **
* * ** * **** ** * **** if (num >= 1170001)
* * * * ** * * *
** * * ** ** ******* * ** * * = * ** * * * * *0.2;
** ** * *** * * * **
*** * * * ** * ** if (num >= 520001)
** * * * ** * *
* *** ** * ** ** * *** * ** = * * * * ** *0.12;
** * * * * ** * ** *
* ***** * * ** if(num >= 0)
* * * ** * * *
** * *** * * * * * = ** * * * * * * *0.05;
* * ** * *** *** * *
* * * ** ** * * * * * * * * ** ** ** * *
* * * * *** * * * * ** **
* * *** ** *** ** * num);
** * * * * * * * * * * * * ** * * * **
** * * * *** * * * * 0;
}
answered
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by
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
* * * * ** *** * * ** * i=0,
* ***** ** * * **** * * * **** * *** * ** * *
* * ** * * * * * * * * * ** * * * * * * **
****** * ** * * * * * ** * *** * * * ** * * * * * *
**** ** ** * ** ** * * * * **** * = i*5/100;
** * ** * * * * * ** * * * ** ** *** * * **** * * ** * * * ** *** *
* * * * * *** * * * ** * *** ** = ((i-520000)*12/100)+(520000*5/100);
* ** * * *** * * ** * * * * *** * *** * ** * *** * * * ** * *
* * * * * * * ** = * * * * * * *** *** **** * * * * * **
* * * *** * **** * * ** **** * ** *** ** * * * * ** ** * *
* * * ** * * * ** = * ** * * * *** **** ** * * ** *** * * *
* * * * *** ** * * * * ** * * * ** * * * * * * * ** * *****
* ** * * * * ****** * = * * **** ** * * ** * *** * * *** * * * * * *
* * ** ** ** * * ** * * ** if(i>=10000001)
*** * ** * * * * * ** * = * ** * * ** ** ** * * * * * * ** * * * * * * * *** * **** ****
** * * * * ****** * * * * *** * *
* ** ** * * * * ** * * * * * ** * * * * * * * *
* * * * * *** * * * * * 0;
}
answered
Oct 27, 2016
by
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AD 20161027 期中考 10
[Exercise]
Coding (C)
-
asked
Oct 27, 2016
in
2016-1 程式設計(一)AD
by
Shun-Po
(
18k
points)
ID: 15448 -
Available when:
2016-10-27 18:30:00
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Due to:
2016-10-27 21:00:00
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AD 20161027 期中考 9
[Exercise]
Coding (C)
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Oct 27, 2016
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2016-1 程式設計(一)AD
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ID: 15445 -
Available when:
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AD 20161027 期中考 8
[Exercise]
Coding (C)
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Oct 27, 2016
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2016-1 程式設計(一)AD
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ID: 15441 -
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2016-10-27 18:30:00
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AD 20161027 期中考 7
[Exercise]
Coding (C)
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Oct 27, 2016
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Shun-Po
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ID: 15439 -
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AD 20161027 期中考 5
[Exercise]
Coding (C)
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