0 like 0 dislike
1.4k views
請設計一個程式,由使用者輸入一個二進位的數,程式會將他轉成十進位後輸出。

sample input:

10101010

sample output

170
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15399 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

reshown by | 1.4k views
0 0
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()

{
    char a[100];
    int n,c,i;
    scanf("%s",a);
    i=1;
    c=0;
    for(n=strlen(a)-1;n>=0;n--)
    {
        c=c+i*(a[n]-'0');
        i=i*2;
    }
    printf("%d",c);
    return 0;
}

7 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

main()\

{
** * ** *** ** ** ** a[99], b[99], i, j=0, k;
** *** * * ** *** h;
* ** ** * *** **** * * ** &i);
* * * ***** ** ** ** ** *** *

   (
* ****** ** ** * **** ** **** * * a[i];
* * *** ******** * * **** *** * ** * *******

   )
***** ** ** * **** *** * **

   (
* **** * ***** ** * *** **** b[i];
** * * * ***** * * ***** * * ** * ** **
* ** ** * * ** * ******** * * ** ** *** * * *** * * ** *
* ** ****** * **** *********
*** ** *** * * *** ******* ** * *** *** * * ***** * * ** ** *
** * ** ** ***** ** ** * * * * * * *** * * *
*** *** ** ** * ** * ** * ** * ***** ** * * * = b[j];
** ** ** * * * ** *** ******* *** **** * * * * = a[k];
*** * ** ** * ** * * * ** ** ** ** * ** * * * ** * * = temp;
** * ***** *** * *** * * * * ** * * ** **
****** * * *** * *** ****** ***

   )



   if (i/2!=0)
* ** ** * * ** **** * (b[i/2] + b[(i/25)+1)/2
* ** * * *** *
*** ** *** *** * * * ******** * * = b[i/2];
** * ** * ** * * * ** * ** b[j])
* *** ** *** * 0;

}
answered by (-52 points)
0 like 0 dislike
Hidden content!
* **** * *** ** **
***** ** ** * *** * **



int *

{
** * * * * * ** ** * * ***


** *** * ** * * * * ****** ** * * * ** * * * * **** * ** ** * ** * **** * * * ***


* *** ***** ** = 128 * a + 64 * b + 32 * c + 16 * d + 8 * e + 4 * f + 2 * g + h;


* ** **** *** * * **** ***** **** *


*** *** * ***** * 0;

}
answered by (180 points)
0 like 0 dislike
Hidden content!
* *** * * * ****
* ** **** **



int * *

{
** ** ***** *** * ** * * ** *


*** * *** * ** * ** *** * ** ** *** * ** * * ** ** ** ** ************** ** ** * ** * * * *


* * * ** ** * = 128 * a + 64 * b + 32 * c + 16 * d + 8 * e + 4 * f + 2 * g + h;


* * * * ** * *** *** ** **


* ** ** * **** * ** 0;

}
answered by (180 points)
0 like 0 dislike
Hidden content!
#include * **

#include ** * ****



int main( int argc, char )

{
* ** ** * **** * iNum;
** **** * * **** **** * **** * *** ** *** *** *** **
* ** * ** * *** * * ** ***** * * *
* * ** *** ** ** * ** ** * * * ** * %d\n", iNum, iNum);


* * ** * * * ** * * * * ** * ******** *
* * ** * **** * *** * 0;

}
answered by (-74 points)
0 like 0 dislike
Hidden content!
#include ******* **

#include ** * * * * **

#include ** * ** ** *
***** * ** ** * * * *

int()

{
* * * *** * * x;
* *** ** * *** *** * temp = 0;
** * * ** ***** * * *** x;
*** *** ** *** *** (x > 0)
* * ** **
** * * * ** ** = 2 * temp +%10;
* * *** **
***** *** ***** *
** ** * * * * * ** * * temp * **** ** * endl;


** ** ** * **** * * 0;



}
answered by (-74 points)
0 like 0 dislike
Hidden content!
* **** * ** * *
** ** ** ** **

int main()

{
* * * ** ** * *


*** * ******* * ** *** **



if(n%10!=0)
* * * ** *** **

a=(n%10)*1;

}



else if(n%100!=0)

{
* *** * * ** *

}

else if(n%1000!=0)

{
**** ** * * *** *

}

else * **** **

{
*** ** ** * **** ** **

}

else *** ** * *

{
** ** **** ** **** ** ** * ****

}

else * ** ** *

{
*** **** **** **** * ** * *

}

else * * *

{
*** * **** **** *** *** * ** * * * *

}

else ** * * *

{
** * ****** * * ** ** * ** * * * ** ** * *

}
**** * *
*** **** ***** ** *

return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>





int main(){
* ** * * * ***** ** x,y=0,i,j=0,n=1;
*** *** ********** * * * *** *** * * * *

    do{
* * * * * ** * * * ****** ** *** *** * ** **** * *
* ** ** * ** * * * ** * * *** * *** * ** ***
* * *** * * *** * * **** * * * **
** *** * ** ** ******* ** * ** * * **


* * *** *** *** ** * ** ** * ** *
* ** * ** *** *** ** ** * * * ** * * *
* ** * * * * *** *** 0;

}
answered by (-126 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.80.171
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15475 - Available when: Unlimited - Due to: Unlimited
| 13 views
0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15447 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.3k views
1 like 0 dislike
37 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15446 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 4.4k views
1 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15442 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2.3k views
1 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15440 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2.2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users