0 like 0 dislike
1.5k views
請設計一個程式,由使用者輸入一個二進位的數,程式會將他轉成十進位後輸出。

sample input:

10101010

sample output

170
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15399 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

reshown by | 1.5k views
0 0
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()

{
    char a[100];
    int n,c,i;
    scanf("%s",a);
    i=1;
    c=0;
    for(n=strlen(a)-1;n>=0;n--)
    {
        c=c+i*(a[n]-'0');
        i=i*2;
    }
    printf("%d",c);
    return 0;
}

7 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

main()\

{
* ***** * * ** ***** a[99], b[99], i, j=0, k;
** *** **** * ** h;
* ** * * ***** ** ** ********* &i);
****** ** * * * ** * * * *

   (
*** * * *** ******* * ** * * ** ** * *** a[i];
*** * *** * ** * ** * * * * * * ** ** * *** ***

   )
** * ** * *** * ** ** *

   (
*** * * *** * * **** * * * * b[i];
* ** **** * * ******* *** * ***** ** *
** * *** **** * ** *** * ***** * ** * * * ** **
******* ** * ***** * * *
** *** ** * * *** * ** * ** ** * * * * ** * *** ** *** * ** *
** * * ** ******** * * ** * ** * *** *** **
***** * * *** ** * * ****** * * * * *** ** * = b[j];
* * ** ********* ** * ** *** ** * ** * ** **** = a[k];
* * ** * * ******* *** * ** **** ** * ** ******** = temp;
* ** * ** * * * *** * * ** ** * * ** * * *
** ******** * *** ** *** ** **** *** *

   )



   if (i/2!=0)
* * * *** * ****** ** (b[i/2] + b[(i/25)+1)/2
** ** *** ** ****
** * ** *** ** * **** = b[i/2];
* * *** * * * ** **** *** ** * b[j])
* * * * *** **** ** * 0;

}
answered by (-52 points)
0 like 0 dislike
Hidden content!
* * * ***** *
* * ****



int * *

{
** *** * ******* * ***** * ** **


** *** ** ** * * * * *** * * * * * ** * *** *** ** ** *** * ** ** ** * ********** *


* * * ***** ** **** = 128 * a + 64 * b + 32 * c + 16 * d + 8 * e + 4 * f + 2 * g + h;


** ** ** * * ****** ** ****** *


* ******* * *** * 0;

}
answered by (180 points)
0 like 0 dislike
Hidden content!
* * ******* *
***** * *** * * *



int * *

{
** **** ******** *** *****


* * *** ** ** * ** * ***** ** *** *** * * ** * * *** * ** **** *** *** * ** * ** ** *


** * ***** * * * = 128 * a + 64 * b + 32 * c + 16 * d + 8 * e + 4 * f + 2 * g + h;


******** ** *** ** * * * *** *** ** ** *


* ** ** ** *** 0;

}
answered by (180 points)
0 like 0 dislike
Hidden content!
#include ***** * * *

#include * ** ** **



int main( int argc, char )

{
* ** * ** * ** * * * iNum;
* * * **** *** *** ** * * * ** * ***** **
*** ** * ***** * * * *** * * * ** * * **
**** * *** * ***** *** * ** * * ***** %d\n", iNum, iNum);


**** ** ******* ** * ** *
** ** * **** ******* 0;

}
answered by (-74 points)
0 like 0 dislike
Hidden content!
#include * * ***** **

#include * ***** **

#include ***** * *
* * * * ** * * * ***

int()

{
**** ** * *** ** * ***** x;
** * * ** ** temp = 0;
* * ***** ** *** * *** ** **** x;
*** **** **** * * ** * (x > 0)
** ** *** * *
**** *** = 2 * temp +%10;
* ** * * * * *
*** ** ******* * ** *
* *** * * ***** * * ** ** ** * temp ******* * endl;


** * ** ** ** ** 0;



}
answered by (-74 points)
0 like 0 dislike
Hidden content!
* **** * ******* **
* * *** * ** * ** * ***

int main()

{
* * *** *** ** *** *


* * * **** * * ******



if(n%10!=0)
***** ***** * * ** * **

a=(n%10)*1;

}



else if(n%100!=0)

{
***** ** * * *****

}

else if(n%1000!=0)

{
** * ** *** ** * * * **

}

else **** *

{
* ** ** ** *

}

else * ** **

{
** * **** * * * * * ** *

}

else ** ***

{
* * ********* ** * ***** * * **** ** * *

}

else *** *

{
*** * * ***** * ** * * ** **** * ***** ****

}

else * * *

{
* * * ** * **** * ** **** *** * * * * * * *

}
*** ** ***
* ** ** ******* ***

return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>





int main(){
** ** *** * * * * *** ** **** ** x,y=0,i,j=0,n=1;
*** *** * * ** *** * ** * *** ***** * **

    do{
* * * ** * * ***** * * * * *** ** *** *
* **** *** ** * *** ** * * * ** *** * **** ** **
**** * * **** ******* ***** ***** ** ** * ** ** *
*** * * * * * * ** * * * * * ** * * **


* * * * * * * *** * * *
** * * * * * * * * * ** ** *
** * * * ********* **** * ** 0;

}
answered by (-126 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.59.98
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15475 - Available when: Unlimited - Due to: Unlimited
| 13 views
0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15447 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.3k views
1 like 0 dislike
37 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15446 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 4.4k views
1 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15442 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2.3k views
1 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15440 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2.3k views
12,783 questions
183,442 answers
172,219 comments
4,824 users