0 like 0 dislike
1.3k views
請設計一個程式,由使用者輸入一個二進位的數,程式會將他轉成十進位後輸出。

sample input:

10101010

sample output

170
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 15399 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

reshown by | 1.3k views
0 0
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()

{
    char a[100];
    int n,c,i;
    scanf("%s",a);
    i=1;
    c=0;
    for(n=strlen(a)-1;n>=0;n--)
    {
        c=c+i*(a[n]-'0');
        i=i*2;
    }
    printf("%d",c);
    return 0;
}

7 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

main()\

{
***** * *** * * * ** a[99], b[99], i, j=0, k;
** ** * * * *** * h;
* * *** ** * * ****** * * *** * &i);
***** ** *** ** * ** *** ** **

   (
* * * ******* ** **** ** ** * ** a[i];
*** * * * ** ** **** ** * *** ** * * **** ** * ** ** *** ***

   )
** *** * * * * * * * *

   (
** * * ** * * ** * *** * * ***** b[i];
* **** ** * ** * **** ** * * **** ** ** **
* * * * ** * ** * ****** * ** ** * *** * **
***** ***** * *** * * * ***** *
*** ** * *** *** ** ** * ******* **** * * *** * ***
* ** ** * * * * * * * ** *** ** * * *** * *
*** ** * ** ** * *** *** ** ** *** *** **** * ** * = b[j];
* ** * * ** * ** * ** *** * * *** *** *** ** * = a[k];
* * *** *** *** *** * * ****** **** * * * * ** * = temp;
* *** * * ** ** * ** ** ** * *** * * *
** ** ****** * ** * * * * * * ***

   )



   if (i/2!=0)
** * * ** * **** (b[i/2] + b[(i/25)+1)/2
** *** * * *
* * *** ** * *** **** = b[i/2];
**** * *** * **** * ****** **** b[j])
* ** ***** ***** * * 0;

}
answered by (-52 points)
0 like 0 dislike
Hidden content!
*** * *** * ** *
** * ** ** * *



int * *

{
** *** ****** *** * * ** * *** *


* **** ** ** **** * * * * **** * ** * * * * * * * * * ** *** ** * * **** **


* * * ** ** * * ** ** = 128 * a + 64 * b + 32 * c + 16 * d + 8 * e + 4 * f + 2 * g + h;


* * ** * ** * * ** *** *** * *****


** **** * * ** ** ** * * 0;

}
answered by (180 points)
0 like 0 dislike
Hidden content!
**** * ** ** * ***
*** * * **** ** * ****



int ** *

{
* * ** * * * ** *** * * ** *


** * *** ***** * * *** * * * ** ** * *** **** ** * * * * * *** ** ** ** *


* * * ** ** * * * = 128 * a + 64 * b + 32 * c + 16 * d + 8 * e + 4 * f + 2 * g + h;


* ** * ***** * ** * * ** * *


* ** * ** * ** * 0;

}
answered by (180 points)
0 like 0 dislike
Hidden content!
#include * ** **** *

#include * *** **



int main( int argc, char )

{
* ** * * * * ****** *** * * * iNum;
** * *** *** *** ** *** * * ** * ** ** ** *
*** *** * *** ***** ** ** * ******* ** *
**** * * * *** * **** * * * ** *** ** %d\n", iNum, iNum);


** ** * * * ** * ** * ***** ***
* * * * ** * * ** * * 0;

}
answered by (-74 points)
0 like 0 dislike
Hidden content!
#include *** * *

#include * * ** *

#include *** ********** *
** ** * *** *******

int()

{
* * ** * * ** * x;
*** * **** ****** temp = 0;
** * * * ** * **** ** *** * x;
* ******* **** * ** (x > 0)
**** ** * **
** * ****** * * = 2 * temp +%10;
** * ** * * * * *
* *** *** * ***** **
* * * ** * ** ****** ** temp *** * * endl;


*** ** * * * **** * 0;



}
answered by (-74 points)
0 like 0 dislike
Hidden content!
*** * * **** ** **
* ** ** *** ***

int main()

{
* * * * **** * ***


* * *** *** * *



if(n%10!=0)
** ** ** * ** * ** *

a=(n%10)*1;

}



else if(n%100!=0)

{
* ** ****** * * *

}

else if(n%1000!=0)

{
* * ****** * ** * *** ** ***

}

else * * ** *

{
* * * *** * ** * * ******* **

}

else * * ** * *

{
** * * ** * * * ** ** ***** *** *

}

else * **

{
* * * ** * * * * * * ***** * ** * ** **

}

else * *** * **

{
**** * * * * ******* * * ** * * * * * * * ****

}

else * * * *

{
* * * * * *** * * * ** *** * *** **** *

}
** * *****
** * * * ** *** *

return 0;

}
answered by (-248 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>





int main(){
** ****** * * ******* *** x,y=0,i,j=0,n=1;
* ** * * * ******** ** * *** * * * ******* *

    do{
** ** * *** * ********* *** ** ** **** ** * **
** * *** * * ** ** ** * * ** *** ****** ** ***
** * * * ** ******** *** ** * ** ** ** ***
* ******* * ** * *** * ****** ** * ** ***


* *** ** * *** **** ** * *** *** *
* * ** * *** ** * * * * * * ** * *
* * **** **** ** *** * * * 0;

}
answered by (-126 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.71.255.69
©2016-2025

Related questions

0 like 0 dislike
0 answers
[Resource] asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15475 - Available when: Unlimited - Due to: Unlimited
| 13 views
0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15447 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.1k views
1 like 0 dislike
37 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15446 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 3.8k views
1 like 0 dislike
17 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15442 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2k views
1 like 0 dislike
18 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 15440 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2k views
12,783 questions
183,442 answers
172,219 comments
4,824 users