0 like 0 dislike
4.5k views
請設計一程式,由使用者輸入N個數字,求這些數字的平均。使用者輸入的第一個數字N代表接下來會有多少個數字要求平均,接下來的N個數字就是需要計算平均的數。輸出請輸出到小數點後6位。

sample input:

10 1 2 3 4 5 6 7 8 9 10

sample output:

5.500000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AD by (18k points)
ID: 15385 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

edited by | 4.5k views
0 0
Called for Help

121 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
** ****** * * * n=0,i;
* ** * * ***** *** * x=0,z=0;
* * * **** * ** *** ***** * * *** **** * ** *

    
******* ** * ** ** * ** ** ** ** **
*** * * * * * *** ****  
*** ** *** * **** *** * * * *** ** ***** * * * ** * **
** **** ****** ** * *** ***** * * *** * * = z + i;
* * ** ** * *
* * * ***** ** ***** **** = z/n;
* ***** ***** **** * * ***** ** ** ** **
* * ** * *** * *** ***** ** * * ** ** * *
* * ** * ** * 0;

}
answered by (156 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* *** ** * * * *****



int main()

{
* ***** **** * * * ** i,j,k,l;
* * ** ****** ** ****** * *
* * * *** * **** ***** * * *** * *** ** * ***


** ** *** **** *** ******* *
*** *** ******** * * ** n[i];
* ** * * * * * *** **
* ****** * *** ** * ** = 0;k < i;k++)
* * *** ** * ** ** * * ****** ****** *** ** n[k]);
*** ******* *** *
** ** * ***** * * *
** **** ** ** * ** *** = 0;
* * ** ** * * ****
* * * ** ** *** ** = 0;k < i;k++)
* ** * * * ** *** = l + n[k];

   
** ** ** * * ** *** ** m;
*** * ** ***** ***** *** = l / i;

   
** * * ** * * ** * **
*** *** *** * ** *
* *** *** ** * * * **** * **** ***
* **** * *** ***** **** 0;

}
answered by (-264 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * **** ** * *******



int main()

{
** ** * * * ** i,k,l;
* ** ** *** ** * * *
** * *** * * ** * ** ** ** ** * *** **
** * **** **** * n[i];
* * ** *** **** ** *
** ** * ** ** *** * * * = 0;k < i;k++)
** * * ** ** * ********** ** * * ** ****** * * n[k]);
* * * * ** ** *** ** *
* *** * ** * *** *
* * * * ** ** * ** * = 0;
*** * * * **** * ******** *
*** * * * **** * ** * * = 0;k < i;k++)
* * * * * * ***** * * = l + n[k];

   

   
* *** ** *** ****
**** ** ** ** * * ** *** * * * *** * / i);
* ** * ** *** * *
**** * ***** * * ** * ***** * ** ***
* *** ****** *** ** * * 0;

}
answered by (-264 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** ** ****** **



int main()

{
* **** *** * * *** ** * i,k,l;
** * * *** * * ***** *
*** *** * * * * * * *** * **** ****
*** * *** ** * * * ** * n[i];
* *** ** * * * * * *
*** *** *** **** * * = 0;k < i;k++)
*** * * ** *** * ** * * **** *** * **** **** * n[k]);
** ** ***** *** *** * *
*** * * *** * ****
*** * * ** *** * = 0;
* * * * * ** * **
** * *** * * ** **** ** ** * = 0;k < i;k++)
* * * **** ** * ** * = l + n[k];

   

   
* * * **** ** *****
** * *** ** ** * ***** *** ***** ** * / i);
** * * *** * * * * * *
* *** ** * * **** *** * * ********
* * * * ** * * * 0;

}
answered by (-264 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    int n,a[2000]={0},sum=0,i=0;
* ** * * ** * *** ** ** ** ans;
* ** *** * ****** *** ** * ** **** *** ** ******
** * * **** * **** * * * *** * **
* * *** * ** * ** * * * * * * ***** **** ** *** *** * * *
** *** * * * * *** ***** * **
* *** * ** ** ** * * * ** ** * *
* * ** * * ****** * ** *** * * ****** *** * *


** ** ** **** * * *** **** *** ** * ** *** * * * **






* * * ** *** * * * * 0;

}
answered by (-146 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main (void)

{
******* * ** *** ** * counter=1,
* **** *** ** ** ****** ***** *** * *** * ***
**** ***** ** *** * ** ***** ** * * * *** * **
** * ** * ** * * j=0;
* ***** ** *
**** *** * * * *** * ****** *** * * &n);
*** ** ***** ** * * *
** * * * * ** ***** * *** counter <= n )
** * * *** *
** ********* * ** * *** * *** * * ** &i);
** * * ** * * * ** * * = j+i;
* ** ***** ** *** ** *** *
* * * * ***** ** * * *

    
** * ** *** *** ***** * = j/n ;
* * * ** ** * * *
* ** ** * ****** * ** * * * *** ** * * **** j) ;
* **** ****** *
* * * *** * ***** * 0;

}
answered by (-170 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>



int main()

{
** * * * ** * ***** A,B;
* ***** * * ** * * * D[A];
* * *** ** ** ** **** C;
* ** * * * * *** **** ** * ***** *
* ** *** **** * ** * *** * *
***** *** ** * ******** * * ** ** ** * ***
** ** ** *** **** **** ** *
** ** * * ** * ** ** ** * * * ** ***

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>



int main()

{
** * *** * * ** * ** ** A,B;
** * * ** * * ** * D[A];
* * ** ** ** * * **** * C;
* * * * *** * * * * * **** ** * ** *
* * * * * ** * ** *** ***
* * * ** ** * *** * * * * * * * **** * * * ***
** * ** *** *** ** * * ** *** *
** * * * ** * * ** ** ***** * ****** * * * **

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main (void)

{
*** * * * ** ** ** *** counter=1,
* ** *** ** * ** **** *** * * ***** ** * ** * **
*** * * ** * * *** * ** * ** * ** * * **
*** *** * * * * *** j=0;
***** * * ****
** * ** ** * * * * *************** **** *
** *** ** * ** * *** * **
* ** ***** * ** ****** * counter<=n ) {
*** ** **** * *** * * * * ** *** * *** *
** * * * * ****** * * = j+i;
*** * * * * * * * **** ** ****
* * **** * * * * *****

    
* * **** * * * *** ***** = j/n;
* **** ****** ** * *
* ****** * ** ***** * ***** **** * ** * * ** **
*** * *** *
* ** ** * **** *** * ** ** ***** *****
* * * * **** * ** ** ** 0;

}
answered by (-170 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * ** * ***** * * *



int main()

{
** ** ********** * *** * i,k,l;
* * ** ** * * * * **** **
** * * ** **** * * ** **** *** ** **
*** ** * * * * * ** * n[i];
** **** * * ** **** ** *
*** ** ******** * ** ** * = 0;k < i;k++)
* **** * *** * ** * *** ** * * * n[k]);
* *** * * ** * *****
* **** *** ** * ** ** *
* ** ** ** *** = 0;
*** ** ** ** * ** ** *
* * * * ** * ** = 0;k < i;k++)
* * ** *** ** * * * = l + n[k];

   

   
* **** * * *
* * ** * ** *** ** * ****** ** * / i);
*** ** * ** **
* * ** ** * ** * ** **** * ** * ****
* ** * **** ** * ***** *** 0;

}
answered by (-264 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.126.28
©2016-2024

Related questions

0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15448 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 389 views
0 like 0 dislike
33 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15445 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.3k views
0 like 0 dislike
11 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15441 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 610 views
0 like 0 dislike
73 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15439 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2.6k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15427 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.7k views
12,783 questions
183,443 answers
172,219 comments
4,824 users