0 like 0 dislike
4.5k views
請設計一程式,由使用者輸入N個數字,求這些數字的平均。使用者輸入的第一個數字N代表接下來會有多少個數字要求平均,接下來的N個數字就是需要計算平均的數。輸出請輸出到小數點後6位。

sample input:

10 1 2 3 4 5 6 7 8 9 10

sample output:

5.500000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AD by (18k points)
ID: 15385 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

edited by | 4.5k views
0 0
Called for Help

121 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
*** * ** ** * **** * * ** n=0,i;
*** * ** *** ** * *** *** x=0,z=0;
* * ** * ** ****** * *** ** * * *** * * * * * *

    
*** * * **** * ** ** ** * ** *
***** **** ** * **  
******* * **** * * * ** * **** ** ***** * * *** ** ***** *
* * * * *** ** * ****** * ** * * **** = z + i;
*** ** * * ** * *******
* * * * * ** * ** * * = z/n;
*** **** ** * ** ** *** * * ** ** * ** *
* * ** *** ** * * ** **** *** ** * *** **
** *** * * * ** ** 0;

}
answered by (156 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * * *** **** * *



int main()

{
*** ** ***** * i,j,k,l;
***** ** * ** ***** ** *
** ********* **** **** * * **** * * **


**** * **** ** *
* ** * * ** *** ** n[i];
**** ** * *** * * **** *
* ***** * * * * * * * * * = 0;k < i;k++)
* * * * * * * ** * ** * ** * n[k]);
**** * ** * * * **
* *** * ** ** *
** ** ** *** ***** ** = 0;
* * * * * * ** * *
* ** * * * * * * ** = 0;k < i;k++)
** * * ** * ****** = l + n[k];

   
** **** * ** ** m;
* * *** **** *** = l / i;

   
* * ** * **** * ** * * ***** * * *** * ** *
*** **** **** ***** **
** * ** * **** * * **** ** * * ** **
***** * * * * *** ** 0;

}
answered by (-264 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* ** ** * * * ** *



int main()

{
* * *** * * * * **** * i,k,l;
********* ** *** * * ***
*** ** * * * * * *** ** ** * ** * ***** **
** ** ** * * ** *** n[i];
** ** ** * ** **
* ** * ** * *** * = 0;k < i;k++)
** **** **** * ** * ***** *** *** * * * * n[k]);
** ** * ***** ***** ** * *
* * * * ** ** *** ****
* * * * * * * * * *** = 0;
* * ** *** ******* * *
* *** * ** **** * ** **** = 0;k < i;k++)
** * * * *** **** **** = l + n[k];

   

   
*** * ** * ** **
** * *** *** * * * *** ** **** ** ***** / i);
***** ** **** *** * ***
* ** * ** * * ** * **** *** ** ** * *
* ** ** * * ** ** 0;

}
answered by (-264 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** ** ** ** * *



int main()

{
* * * **** * * ** * i,k,l;
**** **** *** * * *
**** * ** * * *** * * * *** * ** ** ***
** ** *** **** n[i];
** ** * * *** * **
* ** ** ** * ** * ** ** = 0;k < i;k++)
* * * ** ** * * ** * ** * ** * ** * * ** n[k]);
* * * ****** * * * **
** * ** **** ** * ** * *
* * * * *** **** * * = 0;
** * * ********* **
** ** * * *** **** * = 0;k < i;k++)
****** * ** ** *** ** * * = l + n[k];

   

   
* ** * * *
* *** * * * * * **** * * * * * * ** * / i);
*** *** ** ** * *** *
** * * * ** * * * * * *** ** *
* ***** * * * *** * * 0;

}
answered by (-264 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    int n,a[2000]={0},sum=0,i=0;
** * * *** ** ****** * ans;
*** * * *** ** **** * * * ***** * * * ** ** * * *****
** * ** * **** * * *** * *
* *** * * *** ** * * *** * * ***** ** * ** ** ** ** **** *
* * * * * * *** * **** * * ***
* * **** *** ** * * * ** *** *** ** *** * ** *
* * *** * * * ** ****** * * ******


**** ** * * ******** ** * * ** * * * * * * * * ** * *






** * *** * **** **** **** 0;

}
answered by (-146 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main (void)

{
**** * * * * *** *** counter=1,
* * ******* * * ** ** * *** **** * ** * **
** *** *** * * ** ** * * * * **** ** *
* *** * * ** ***** ** * * j=0;
* **** ** *** *** * *
** * ** ** *** * * * ***** ** ** ** &n);
* *** * ** ** **
* * * * ****** * ** counter <= n )
** *** * * * * ***
** *** * * ** * ** * ** * * &i);
**** ** ** ****** *** = j+i;
** ** ** ** * ** ** * **
** * * ** * ****

    
* * * * ***** * ** = j/n ;
** * ** * * ** * * *
** * * *** * **** *** ** * * * * **** *** j) ;
* ** *** **** * *****
* ** *** * ** * * * 0;

}
answered by (-170 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>



int main()

{
* *** * * ** ** * * A,B;
* * ** **** * ** * ** * D[A];
**** * ** ** * ** C;
* ** * ** ** *** * * *** ** * * ********* *** * * ****
** * ** ***** * * *** * ** * *
* ** * * ** ** * * ** * ** *** *** * * * ** *
* ** *** **** * * ***
* * * * *** * * ***** * *** * * * * * * * * ****

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>



int main()

{
** ** * * * *** * A,B;
* ** * ** D[A];
* *** * *** * ** C;
*** **** ** * * * ********** * * **
* ***** ** ** * ** *** * *** *
**** ** * * ** * * * * ** * **** ** *
* ** ****** *** * * * ***** ** ** *
* * ** * ** *** * * * ** * ***** * ****** *

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main (void)

{
** * ***** ***** * ** ** * counter=1,
***** * ***** ******* * ** * * ** * * **
** * ****** * ********* * * ** *** ** **** *
* * * * * * * ** * ** j=0;
** * * * **** **** **
** ** * * ****** ** ** * * **** * * * *
* ** ** ** * * * *
*** * ** * ** ** ** counter<=n ) {
** * ** ** ** * *** * *** * * * * **** * * *
* * *** ** *** * ** *** * * = j+i;
* ** * * *** *** **** **
** *** * * * * ***** * **

    
* * * * * * ** * ** = j/n;
* * * * * ** * *******
* ** * *** * ** * **** * *** ** * ** **
* * * *** * *
** * ** * *** * * * *** * *** * *
* * ** ****** * *** ** 0;

}
answered by (-170 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
**** ***** **



int main()

{
*** * * * ** ** ** ** ** i,k,l;
***** ** *** * ***** *
* * * ** * ** ** * *** * *
* *** * * * ** ** * * * ** n[i];
**** ** **** ** ** ** *
* * *** ** ***** *** = 0;k < i;k++)
** ** * **** ** *** * *** * ** **** ** * n[k]);
*** * * ***** ****** *
* ** * * * * *
***** ** * ** * *** = 0;
*** * *** ** ** * ** *
* * **** ** * * * ** = 0;k < i;k++)
* ** **** ** ** ** = l + n[k];

   

   
***** * ****
* ** * ** **** ***** * * * * * *** * *** * / i);
* * *** *** * * *
*** * * * * * * * ** *** * ** **
******** **** * * *** ** 0;

}
answered by (-264 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.130.237
©2016-2024

Related questions

0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15448 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 389 views
0 like 0 dislike
33 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15445 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.3k views
0 like 0 dislike
11 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15441 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 610 views
0 like 0 dislike
73 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15439 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2.6k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15427 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.7k views
12,783 questions
183,443 answers
172,219 comments
4,824 users