0 like 0 dislike
15.8k views
請設計一程式,由使用者輸入N個數字,求這些數字的平均。使用者輸入的第一個數字N代表接下來會有多少個數字要求平均,接下來的N個數字就是需要計算平均的數。輸出請輸出到小數點後6位。

sample input:

10 1 2 3 4 5 6 7 8 9 10

sample output:

5.500000
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AD by (18k points)
ID: 15385 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00

edited by | 15.8k views
0 0
Called for Help

121 Answers

0 like 0 dislike
Hidden content!
#include<stdio.h>

#include<stdlib.h>

int main()

{
* *** * *** * * n=0,i;
* *** * ** * ** x=0,z=0;
** * * * *** ** * *** ***** ** ** * *

    
*** ** * ** * * ** ** * ** * * *
* *** * ** ** **  
** ** * ** * ** * * ** ** * * * * *** * *** * ** ** * ** ***
* * ** * * * ** ** *** * **** * * **** *** * = z + i;
* ***** *
*** * * *** * ******* = z/n;
* * * * **** *** * * * * *** * *****
* ** **** ** ** ** *** *** * *
* *** ** *** * * * * 0;

}
answered by (156 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * ** *** * **



int main()

{
* ** ** ** * * ** * i,j,k,l;
* * ** ** ** ****
* * * * ** * * * * * * * * *** ** * * *


****** ****** * ** ** * * *
** * ** ** * * ** * n[i];
* ** ** ** * *** **
* *** * * * ** * * *** = 0;k < i;k++)
* ** ** * * ** * * ** * * * * * n[k]);
* ** * ** * ** * **
** *** * * ** **** ***
** * **** ** ** = 0;
* ** * ******* * * ****
* *** * * **** * * * * = 0;k < i;k++)
*** * ** ***** * * = l + n[k];

   
* * ****** *** * * m;
**** * * ** * * ** = l / i;

   
* ** ** ***** **** ** ***** ***** ** ***
* * * * * ** * *** *** *
* * * * * ********* * * ** ** * *** **
** * ** ** **** ** ** ** 0;

}
answered by (-264 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
*** * ***** * * *



int main()

{
*** * * * * ** i,k,l;
* ** * * *** ** * * **
* * * *** *** * **** * ***** ****** * ** **
**** *** * * **** * ******* n[i];
* * * * * * ****** **
* ** * * * * **** * = 0;k < i;k++)
** * ** ** ** * * *** ****** * * * * * * *** * * n[k]);
* * * * * ** * * ****
* ** ** * **** * * **
***** * * ***** *** * ** = 0;
* * * *** * * * *
**** * * * * **** * ** = 0;k < i;k++)
** ** * **** * * * ** = l + n[k];

   

   
***** **** ** *
* * *** *** * ** ***** *** ***** * * *** **** * / i);
* ***** * * * *** ***
*** * *** * *** * *** * ** ** ** * * * ** **
** ** * ** *** *** * 0;

}
answered by (-264 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
** * ***** *



int main()

{
* ** * * **** ** * ** * i,k,l;
* *** * **** * * * *
*** * * * *** * ** * * ******* ** *
******** ** * * * **** * n[i];
* * ** ***** **
* ** *** *** * * * = 0;k < i;k++)
* ***** * ** ** *** * * **** * ** *** ** * n[k]);
*** ***** *** * *******
*** ***** * * ** *
* * ** * ** **** **** ** *** = 0;
* **** * * ** ** * *
** ** * ** * * * ** = 0;k < i;k++)
* ** ** *** * * **** = l + n[k];

   

   
* ** * * * **
** * * ***** ** ** * **** * * * ** / i);
* ** *** * *****
* ** *** * ** *** * * * *** ** * * ****
**** ** **** * * ** * *** ** 0;

}
answered by (-264 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    int n,a[2000]={0},sum=0,i=0;
** * **** * **** *** * * * ans;
** * ** * ** *** *** *** * ** * ** ** **** ***
* ** * * * **** * * *** * * **
* * ***** * * * **** * ** ** *** ** ** ** * ** ******
* ** **** ** * * * *** * * ** *********
* * *** * * * ** * *** * *** **** * * * ***** *
** ** * ***** * **** **** * ********* ** **** * *


* * ** * * *** * * ** ** ** * ** * **** * ** * ** **






* *** **** * ** ** 0;

}
answered by (-146 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main (void)

{
* ** ** *** * * counter=1,
* **** ** * * *** * * * * ** **** ** * ***
* * * ** * ****** *** ***** * * ** ** * * *
* * * * * ** * *** ** **** * ** ** j=0;
** ** *** ** * *****
* * ******* * * * *** * ** * * * &n);
* * * * *** ** ***
****** * ***** * **** *** counter <= n )
*** ** * * ****
* * *** * * * ***** * * *** * * ** &i);
* ** * * * * *********** = j+i;
* * ** * **** *** **** ** *
* ** * * ***** *

    
**** *** **** *** = j/n ;
***** ** *** ** ****
* * ** * ** * * *** ** ** * * * * * j) ;
* * *** * *** * ** *
***** *** * *** *** ** * ** 0;

}
answered by (-170 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>



int main()

{
*** ** *** ** A,B;
* * * *** * * ** ** * D[A];
* **** * * ****** ** *** C;
* *** *** ** **** ** * ** ** **** **** * ***
* * * * * * ******* * ** * * **
*** ** * ** ** ** *** ** * * ** *** ***
** * **** * * ** * *** * * *
*** * ** * * * * ***** * *** *

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>



int main()

{
* * ** ** * * ** * A,B;
** * *** * ** * * D[A];
* ** *** * * * *** C;
* * * * * * * *** * **** * ***** ***
* * ** ** ** * * **** * * ** *** **
***** * * * * * * * *** ** ** ** * *
**** * * * * * *
* ** *** * **** ** ** * * * * **

}
answered by (-102 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main (void)

{
* ** * * *** *** * *** counter=1,
* ******* ** **** **** * * *** * ** ** *** ** * **
* *** **** * ** * * * * ** ****** ** **** **
******** * ** *** * * * j=0;
*** * ** * * **** * ***
* ** ** ** ** ** **** * * * ****** ** *** *
**** * * *** * * * ***
* **** ** *** ***** * ** counter<=n ) {
* * * **** ** * * **** ** * ** ****** * ** *
*** * ** * ** = j+i;
*** * ** * * * * * * ** **
**** ** ***** ** ** ***

    
* * ** *** *** *** = j/n;
* ** * * * * *** * * * *
* *** ** * * *** * **** * ****** * ****
** * *** * * * ***
** * * * ***** * * ** * ** ** ** *
* * ** ** * * * * * 0;

}
answered by (-170 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * *** ** ***** **



int main()

{
** ** **** ******* i,k,l;
* ******** * ** *
* * *** * *** * * ** ***** **** * *** *
** *** * * ** * * n[i];
** * ***** *** **
****** * * * ** * ***** * = 0;k < i;k++)
** * **** * ** ** ** * * * ** **** n[k]);
* **** * ** ** *
** * * * * * * ***
** * ** ** *** = 0;
* * * * *** * *** **
** * * ** * * ** ** = 0;k < i;k++)
* * * ********* * * = l + n[k];

   

   
* * ** *** **
** *** ** *** **** * * * ** * ** ******* / i);
*** ** * * * ** * **
***** * *** ** * **** * ** * **
* * **** ** * *** *** ** 0;

}
answered by (-264 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:104.23.243.202
©2016-2026

Related questions

0 like 0 dislike
5 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15448 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 1.5k views
0 like 0 dislike
33 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15445 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 5.4k views
0 like 0 dislike
11 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15441 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 2.9k views
0 like 0 dislike
73 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15439 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 10.2k views
0 like 0 dislike
41 answers
[Exercise] Coding (C) - asked Oct 27, 2016 in 2016-1 程式設計(一)AD by Shun-Po (18k points)
ID: 15427 - Available when: 2016-10-27 18:30:00 - Due to: 2016-10-27 21:00:00
| 6.8k views
12,783 questions
183,442 answers
172,219 comments
4,824 users