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AD 20160929 作業 2
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請設計一程式，讓使用者輸入一個數字代表西元年，程式會判斷該年是不是閏年。
範例輸入1
2000
範例輸出1
2000 year is leap year
範例輸入2
1900
範例輸出2
1900 year is not leap year
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Coding (C)
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main()
{
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Sep 29, 2016
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楊傑宇
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
int year=0,
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Hidden content! * * ** ** *** ** **
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Sep 29, 2016
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Hidden content!#include ** * ** *
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int main()
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Sep 29, 2016
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
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}
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Sep 29, 2016
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Phoenix666
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main( )
{
int year,day;
*** *** ** * ** * * * * * * * * * * * * *** *
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* * * * * * * * * * * * ** ** * * * 0;
}
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Hidden content!#include <stdio.h>
int main()
{
** * * ** * ** * year;
* * **** * ** * * * * ** * * input year:\n");
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* * * * * * * * * * * * * * * * * ** * * ** * ** days");
* * * * ** * * * *
* * * * ** * * * 0;
}
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Sep 29, 2016
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Hidden content! * * **** * * * * *
** * * ** * ** * *
* * * * ** **** ** * ** main()
{
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* ** *** ** * * ** 0;
* * ** ** * *** * *
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Hidden content!#include *** * * * ** * *
#include * * ** * **
int main()
{
* * * ** * * * * ** *** * ** ** *** year=0;
** ** *** * *** ** * * * * * input the year\n");
* **** * * ** * * * * * * ** * * ** * * * * * &year);
*** ** * ** ** * * * *** * * * % 4 == 0 && year % 100 != 0)
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* * * * *** *** ** **** **** ** ** ** ** * * * **** year is not leap year",year);
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* * * * * * * * * * ** ** * * * ** * ** * * year is not leap * * ** * *
* * * ** ** ** ** * * * * * * * * * * * * * *
}
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main( )
{
int year,day;
* * * ** ** * * * * * ** * * * ** ** * * * * ** * **
** * ** * ** ** * * ** ** * ** * * * * **** ** * * ** ** * *
* * * ** * * ** *** ** * * * * *
*** ** ** ** ** * * * * * * ** * **** * * * * **
* ** * * *** * * ** *** ** * * && year%100!=0)
* * * * * ** ** * ** * * * * **** * ** * *
*** ** ** * * ** ** * *** * && year%100!=0)
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* ** ** * * *** ** * * ** * ***
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* * * ** ** *** ** * * * * * * * * * * * ** ** * * * ** * * * ** ****
* * * * * * * *** ** * * * * * * * * * 0;
}
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