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AD 20160929 作業 2
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請設計一程式，讓使用者輸入一個數字代表西元年，程式會判斷該年是不是閏年。
範例輸入1
2000
範例輸出1
2000 year is leap year
範例輸入2
1900
範例輸出2
1900 year is not leap year
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Coding (C)
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Hidden content!#include<stdio.h>
#include<stdlib.h>
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楊傑宇
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main (void)
{
int year=0,
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410423016
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Hidden content! * **** *** ** **
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answered
Sep 29, 2016
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jack2234567
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Hidden content!#include ** * * * * * *
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int main()
{
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Hidden content!#include <stdio.h>
#include <stdlib.h>
int main()
{
* ** * * ** *** ** * year = 0 ;
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}
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Sep 29, 2016
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Phoenix666
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main( )
{
int year,day;
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}
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Hidden content!#include <stdio.h>
int main()
{
* ** * * * *** ***** year;
* ** * * ** * * ** ** * input year:\n");
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* * * * * * *
* * * ** ** * * * ** * 0;
}
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Sep 29, 2016
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Hidden content!* * * * * * * *
*** ** * * * **
*** ** *** * ** * * main()
{
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* * ** * * ** * 0;
* * * * * *
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Hidden content!#include * * * ** *
#include ** * **
int main()
{
* ** * * *** * * * * * * year=0;
** ** ** *** * * * * * * * * * * input the year\n");
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** * * ** * * * ** * * * * * ** % 4 == 0 && year % 100 != 0)
* * ** * *** * ** ** ** * * *******
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* * **** *** * ** * * * * * * * if(year %400==0)
** * ** * * * * * * * * *
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* * * * * * * * *** * * * *
* *** * * *** * ** ** *
* *** * * * ** * ** * *** * * ** *** * * ** * * * * year is not leap *** *** * ** ** ***
* * * ** * * * *** * * ** * * * * ** * * * * * ** ** * ***
}
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Hidden content!#include<stdio.h>
#include<stdlib.h>
int main( )
{
int year,day;
** **** *** * * * ** ** * * * ** * * * * * * * ** *** ** ** ** *
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* * * ** * * * ** ** ** * && year%100!=0)
* **** * * ** ** * * * *** ** * * * * * ** ** * *** **
* ** * ** * * * * * * * && year%100!=0)
* * ** * * * * *** ** * * * * * * * * * ** * * * * *
* * ** * * * ** ** * * * *
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** * * * *** ** * * * ** ** ** *** * ** * ** * * * * ** ** ** **
*** * * ** ** * ** ** * * * * ** * ** ** * * ** * * * ** 0;
}
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