10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include *   *** **** *
#include   * **  **** *  *

int water_amount;
double price=10;

int main()
{
* * **  *    *   *  * * ****** * *    *******   * *  ***  * *

**  ***  *   ** ****  * *   *  **  ** * * *  * *

*    * ** * ** *        *** *      ***   *   **** * *  **   * = price  *** *** * * **  *
 ** * *  **** * ***     * *  **  *            ***    *   ***  = water_amount - (water_amount - 60);
 ***  *  ** **  **   **   *
 * ******* * *   ***    ** *  *** ** ** **

*****    *  * *** * * *  *    **** *** *  **  * **  *   *  *  * * = price +(water_amount-50)*1;
   ** *** **  ***** *   *  * ** **** *  ****  ** ** *   * *   * = water_amount - (water_amount - 50);
 *  **** * *   ** * ** ** 
**** * ** ***** *****  ** ***** * *** * *** **

* *     **** ***  *    *  **  * ***  ******* * *  *  = price        *  **** **
* ***  ***  * **  *   ***  * ** *** ****  **  ** ***    ****     = water_amount - (water_amount - 30);
*  * ***      **   *    ***
 *** **    ** * *** **  ****** **    ** *** 

 *     ***  **  * * * ** **   *  ******   **     * * * **** = price +(water_amount*0.6);
*   *   *  * *  * **  *** ***  ******** *   *  ************  ** = water_amount - (water_amount - 30)
 *  ** *** **    **** * *   

 **    ** * * *** ** * * * * **** ******  ****  * price);
* **   * ***      * * * ** * * 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!