10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include ** **   * ** *  * 
#include * *  ***   *   *

int water_amount;
double price=10;

int main()
{
 **  **** ** ****  * *   ** ****  *** ***   *     * * *  * *

 * *  **     **** * **   ***** * ***  ** 

*  *   * ** *** ** *** ** * * *  *  *  *****  *     *** ** = price  *  *******  ** *
  *  *  ** ***** *** **  *** * *** * * *  *   ***   *** **** = water_amount - (water_amount - 60);
**** ** ** * *** *  ***       
 *   *  **** * * *      *    ***  *  ** * * **

 * *  * * * *   *** *   **** ** * *  **  *** **     *  **** ** = price +(water_amount-50)*1;
* *  * ***********  **** *  *    ** *  **   *  *****     * **** = water_amount - (water_amount - 50);
        **     * ** *  * ****   *
 * * * *   ** ** *    ***  *** *  **  ** *** 

  * *  **  * **   ***** *** **** * * *    *** *    *** **   * = price  **   *      *
 ****  *   ***    ** * ** *  * *  * *  ** ***  *** *   *****  = water_amount - (water_amount - 30);
  *** ***  *  ***    *   * *  ** 
  *      **  *** *  * *     * * ***      ***

 * **** *  **   *   * **** ***** * *    ******  * **   ***  = price +(water_amount*0.6);
***  * * * **** * ** *   *   *    **      *  *  ** **   = water_amount - (water_amount - 30)
 * * *  *** ***     **      *

  * *** **  * **** * *  * * *  *****   ** ****  price);
  * * **  ******   * ** * **    **  0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!