10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

Hidden content!
#include * *  ***  
#include ** **** *  ** *   

int water_amount;
double price=10;

int main()
{
** ****      * * *  * *  * ** *     *  ***  ** *       * * 

*  ********* * **  * ** *    ***  **** ***** 

*   *  *   ***** **  * * * * ** *  * * *  ** *  **** = price **   *  * * *   
*    ** ***** ***  *   *** **  * *  *    **  *  *****  **** *  **   = water_amount - (water_amount - 60);
 *  ***** * ******* **   * *
**** ** *    *****  * *** **  ** **   *  **

* **  ****** *** * *  *  *  **  * * ** *  ***  * * ***  * = price +(water_amount-50)*1;
*** ***** * *** * *  ** * **** ****** *   *   **   * * **  *** = water_amount - (water_amount - 50);
  * *  *   * *********  *  
*  ****    *****   *** ** ***** *  *** * *     *  *  

*** * * **   **** *** * * *  * ** ** ****  ****  ** * = price ***  *       **  
 * ** * **    * *   * * * * **   *    *    * **** * *   *    ** = water_amount - (water_amount - 30);
**  * *   **     * * ********
* *  * * **    *   *** **** *** ******  *     * *

  *****  *   * *    ***   **** ** **     * * * *       = price +(water_amount*0.6);
  *   * ** ***  *   * ***   **   *   ** *****  * *   * * * * = water_amount - (water_amount - 30)
***    ****     *** ** ****  **

*** * ****        *   ****   * **  ** ***  * price);
*   ***  *      * ****** ** ** 0;
}

Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

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Your output is not exactly the same with what the question asks you to do :)
Cost: 25.00

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Thanks!