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Write a program that reads the number of students who passed and failed in the exams and displays the percentages. For example:

輸入及格與不及格人數
輸出及格與不及格百分數

Example input:

12 8

Example output:

Success Ratio: 60%
Fail Ratio: 40%
[Exercise] Coding (C) - asked in Chapter 4: Expressions by (12.1k points)
ID: 25730 - Available when: Unlimited - Due to: Unlimited

edited by | 2.8k views

86 Answers

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answered by (-167 points)
0 0
Case 0: Correct output
Case 1: Correct output
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answered by (-167 points)
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Case 1: Wrong output
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answered by (-167 points)
0 0
Case 0: Wrong output
Case 1: Wrong output
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answered by (-167 points)
0 0
prog.c: In function 'main':
prog.c:11:32: warning: unknown conversion type character 0xa in format [-Wformat=]
     printf("Success Ratio:  %d%\n", passratio);
                                ^
prog.c:13:28: warning: spurious trailing '%' in format [-Wformat=]
     printf("Fail Ratio:  %d%", failratio);
                            ^
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answered by (-254 points)
0 0
Case 0: Correct output
Case 1: Correct output
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answered by (-32 points)
0 0
Case 0: Correct output
Case 1: Correct output
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answered by (64 points)
0 0
Case 0: Correct output
Case 1: Correct output
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answered by (54 points)
0 0
Case 0: Correct output
Case 1: Correct output
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answered by (54 points)
0 0
prog.c: In function 'main':
prog.c:5:13: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'float *' [-Wformat=]
     scanf("%d %d",&a,&b);
             ^
prog.c:5:16: warning: format '%d' expects argument of type 'int *', but argument 3 has type 'float *' [-Wformat=]
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                ^
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answered by (-32 points)
edited by
0 0
prog.c:3:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main(void)
 ^~~~
0 0
prog.c:3:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main()
 ^~~~
0 0
Case 0: Correct output
Case 1: Correct output
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