0 like 0 dislike
478 views
整數的運算會因為整數所佔的記憶體大小而有限制,無法計算太大以及太小的數字,但是如果利用字元以及陣列的結合,就可以大大的提升整數運算的範圍,請設計一個程式,讓使用者輸入兩個很大的整數,程式會把兩個整數相加後輸出。

輸入說明:輸入會包含兩個正整數,兩個正整數之間會用一個空白隔開,兩個正整數相加的結果不會超過五十位數。'

輸出說明:請將兩數相加的結果輸出。

輸入範例:

999999999999999999999999999999 999999999999999999999999999999

輸出範例:

1999999999999999999999999999998
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 478 views

16 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
* ** *** * ********* * **** ** * * *** *
* * ** * * ** ******* * * **

    {
* ** * ** * * ***** * * ** * ****** *** ****** *
** * *** ***** * ** ******* ****** ** *
** * * * * * **** ** * * *** ** ** * * * * *** **** * * ** * *** *** * * ** *
**** * *** * ** *** *** * * * * * *** ** *** * * *** * * * ***** * ** * * * ***** * * = a[n] + b[n];
*** * * * *** ** *** ** * ** * ** * *** *** ** * ***** * ** * * if(a[n]+b[n]>='10')
*** *** * *** * * ***** *** *** ** * **** **** ** * * ** **** *****
*** ** * * ** *** ** ***** * ***** ******** ** ** ** ***** * *** ** * * * * = a[n] + b[n] - '10';
* ** * * ****** ***** **** * * * ** * * * ** * * ***** ** *** *** * ** * * * * * *** * * * *
***** ** * *** * * * * *** * ** * *** * * * * ** * * ** * * *
** *** ** ** * * * ***** ** ** * * *** **
*** * ** ***** * * * ** * * * ** *** if(t == 1)
** ** * * *** ** *** * ** * *** **
* ** * ****** * * * * * ***** ** *** * ** * * * * *** * * ** *** ** **
**** ***** * ** ****** ** *** * * * * ** * * * ** * * * ** * **** * ***** ****** *** *** **** = a[n] + b[n] + '1';
* **** ** * * * * * * * * * * * * * ** *** ** * ** * * if(a[n]+b[n]>='9')
* ******** **** ** * * * * * **** ** ** * * * ** **** *** **
*** ** *** ** * ** * *** * * *** * * * ** * * ** * * *** * ******** ** *** ******* * = a[n] + b[n] - '9';
* *** *** * * ** * * ** * * ** **** ** *** ** * * * ** * ** *** ** * ***** *** * ****** * *** **
* ***** * ** *** * ** *** * * * * * *** * ****** * *** *** *
**** * **** *** ****** ** ** ** ** ****

    }
* * ** * * ** ***** * *

    {
****** * ** * * * * * * **** ** ** ** *** * **** ****

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
* * * ** *
* * * * * *****

int main ()

{

int *


* *** *** ** ** * ** * ** ** * *
** ****** *** * ****


* * 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include * **** ***** *

#include <ctype.h>

#include <math.h>

#include <stdlib.h>



int main(){
* * * * * ** ** * * a[100],b[100];
* * *** * *** * * * sum[200];
* * *** ** *** * ** la,lb,lm,i,j,k;
*** * * ** ** * ** *** * ** ** * %s",a,b);
** ** * ** *** * ******* * = strlen(a);
*** * * * ** * * = strlen(b);
* ** *** ***** ** * * * * * ****** *
** * * ** * * ** * * * ** ******** * * **** = a[i];
* * *** * * ** *** * **** *** * * * *** * * * * * ***** * *****
* *** * ** * ******** *
* * * * * ****** ** *** * ** * * * * *** *
******* ********* ** *** *** * * **** * * ** **** += b[i]-48;
***** * * * **** ** * ** * *** * * ***** ** *** * ***** **
* ** **** * ** ** *
** * ***** ** * **** = strlen(sum);
*** ** ** * * * ** *** *
** * ** **** * *** ** ** * * ** *** * * * * *** ** * ** ****** * * *****
*** ***** * ****** * ***
* ** ** * ** * * ** 0;

}
answered by (-216 points)
0 like 0 dislike
Hidden content!
* ** * ** **
* ** **** * * ***





int main ()

{
* a , b ;
*** * * * **** ** * , * *
* *** * * * * , ** *** *
*** * **** ,a+b);
* ** * * *** * * 0 ;



}
answered by (-87 points)
0 like 0 dislike
Hidden content!
#include <stdio.h>

#include <stdlib.h>



int main()

{

    char a[50]={0};

    char b[50]={0};

    char c[50]={0};

    int n,t=0;
**** * *** ** * * * * ***** * * * *** * *
** *** * *** ** **** *** ** * * *** *

    {
* *** * * * ** ** * ****** *** ** * * ** **
* * * * * * * * * * * * ***** * * * ** * *
** *** ** **** * ** ** * ** * * * * *** * * * * * * * *** *** **
* *** *** * * ***** * *** ** ** ** * * * * ** ** *** **** * *** ** ** = a[n] + b[n];
* ** ** * **** ** ** * **** * *** * * * * * *** *** * * *** **** * if(a[n]+b[n]>=10)
* ** ** *** * * ** **** * ** * **** *** **** * *** * *** *
****** *** * * * ** * *** ** * * *** ** * ** ****** * * ** * *** * *** * * * * = a[n] + b[n] - 10;
* ** * * ** * * * * ** * * ** * *** ** ** * ** * * **** * * ** * ** *** *** * ** ***** ** * **
***** * * ** ****** * *** *** * ***** * ******** * **** *
* * * ***** *** * *** * * **** * **** ***** ******
*** ** ** * ** * * * * ** ** ** * if(t == 1)
* ** * **** ** * ** *** * * *
*** ** **** * *** * ** * ** * ** * **** ** ******* ***** * **** * * *
* ** ***** * * * ***** ***** * ** ** * * ***** ** * ** ** * ** ******* * *** ** ** ** = a[n] + b[n] + 1;
** * **** * * * ** ** ** * * * * ** * * ** ** *** * ** * if(a[n]+b[n]>=9)
**** * ** *** * * *** * * * ** * *** ** * * ********* *** ***** * *** *
* * *** ***** ** ** * ** ***** ********** ** ** **** * * ** **** ** ** * * ** ** ** ** *** = a[n] + b[n] - 9;
* * * * ** * **** * * * * ** * * **** * * * **** * *** * ******** *** * * *** ** ** * *
*** **** **** * ** *** * * * * *** ** * * * ** ** **** * ** *
** ** * ** * * ***** * ** ** * ***** *****

    }
** ** ** *** **** *** ** ** * **

    {
* * * ** * * * * * * ***** * ** *** * ** * * *** * * *****

    }

    return 0;

}
answered by (-85 points)
0 like 0 dislike
Hidden content!
# include <stdio.h>

# include <ctype.h>

int main()

{
* * * * * ** data[2];
* * * *** * ** *** *** sum;
* * ** **** ***** ** i;
* * ** * ** * *** ** * *
** * ** * * **** **
** * ****** * * ** **** * * * *** ** *** * ** *** *** ** **
*** * *** **** *****
* **** * ** * * * **** ***
*** *** ** * ****** ** ** * ***** *
**** **** ******** * * *

}
answered by (-124 points)
0 like 0 dislike
Hidden content!
#include * * * ** *
* ** * * ** ****
* * * ******
* * *** **** ***







int ** *

{


*** * * int * * * * *******
**** * * *

**** ** scanf *** * * * ** ***
**** **

** * ** **** while (a[i]!= ' ')

{
* *** ****

* ** ** i++;
** * * *

* * * *** scanf * ** ** ** * ***** * ** * ** * **

* ** ** ***

}


**** * * * scanf ***** * ***** * *


*** * * * ** while * * *** * *******
*** *** *

*** * {
* ** *** * * * ** *

* ** * * *** ** * * **** j++;
* * * ** * * *

**** ** * *** * * ** *** * scanf * *** ** ** **** * ** * *** *

* ** * * * *** * * *

* *** **** * }
* ** * *

}
* * * **

**** * for (i = 0,j = 0;;i++)
* * **

* * * ** * return 0;

}
answered by (-157 points)
0 like 0 dislike
Hidden content!
include <stdio.h>

#include *** * ** **

int main()

{
** ***** ******* * a,b,c;
* * * * ** ** **** ** *** * ** * ** *** **
* * * * * ** = a + b;
** * * * ** ** ** * ** * ** **** *** * ** * * ***
** **** ** * ** * ************
* ** * *** * *
* * * * * ******* * * * ** * *** ** ***
** * ** * * * * * * 0;

}
answered by (-42 points)
0 like 0 dislike
Hidden content!
#include *** *************

int * * * ** y=999999999;

int main()

{
** * * * * * *** **** ** * * *
* * * * * ** * *** * ***
* * * * * ** * * ** * *** *

}
answered by (-162 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* * * * ** *** * *

int main(){
** ** ** ******** a,b,c=0;
*** * * *** * ** *** * ** ** ** ** *** * * *
* ** * * ** * * * * ** * * ** * **
** ** * * **** ****** * ** * *
*** * *** * * **** * *** * ** * * * *
**** *** ****** ** * * * ** 0;





}
answered by (-140 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.6.99
©2016-2024

Related questions

0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.6k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 950 views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.1k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 499 views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,443 answers
172,219 comments
4,824 users