0 like 0 dislike
503 views
整數的運算會因為整數所佔的記憶體大小而有限制,無法計算太大以及太小的數字,但是如果利用字元以及陣列的結合,就可以大大的提升整數運算的範圍,請設計一個程式,讓使用者輸入兩個很大的整數,程式會把兩個整數相加後輸出。

輸入說明:輸入會包含兩個正整數,兩個正整數之間會用一個空白隔開,兩個正整數相加的結果不會超過五十位數。'

輸出說明:請將兩數相加的結果輸出。

輸入範例:

999999999999999999999999999999 999999999999999999999999999999

輸出範例:

1999999999999999999999999999998
[Exercise] Coding (C) - asked in 2016-1 程式設計(一)AC by (18k points)
ID: 18075 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00

reshown by | 503 views

16 Answers

0 like 0 dislike
Hidden content!
** *** ** **
*** *** * * **** *





int main()
** *** a, b, c;
*** * ***** ***** ** * * ** ** ** **
* * = a + b;


* * *** ***** * c);


**** * ** ** * ***** ** ** **** ***



return 0;
* ****
answered by (-98 points)
0 like 0 dislike
Hidden content!
* ** ** **** *** * *


* ** * * *


* * ** ** **** **


** * *** ** *** * **




* * * ( * )

{


* * ****
* * = ** * *
*** *** * * *** * ****




** = * +




*** ** ** * *










* 0;

}
answered by (-276 points)
0 like 0 dislike
Hidden content!
*** * **** ***

#include * *** *

int main (void)

{
** * ** c;
* ** a,b;
* * * * ** * * * *** *
** * *** * * *********
* **** *
** ****** * * * ** ** ** ** *
*** * 0;

}
answered by (42 points)
0 like 0 dislike
Hidden content!
#include<stdio.h>
* *** * *** * * ****

void rect(int ,int,int *);

int main(void)

{
** ** * *** * * * a,b;
* *** ** * * * sum;


** ** ** ** *** ** ** * ** * ** *** * ** **


**** *** * * * * * *
* * * *** * * * * * ** * * ** *** *


** ******* *** * * * * * * * *
*** *** * *** *** ** * 0;

}
* * *** * ** * * rect(int x,int y,int*p1)
* * * * * * ** *
** * * * * * ** * * * * *** * ***


* **** ** *
answered by (-114 points)
0 like 0 dislike
Hidden content!
** **** * *
* *** * * * * ***



int main()



{
* * ** ** * **
** **** * * * *** * * ** ** *
** ** = num[i] + num[j] ;
**** ** * * * * * * * **
* * 0;



}
answered by (-50 points)
0 like 0 dislike
Hidden content!
#include * *** ** * *



int main (void)

{
*** ***** * * * * ***** ** ** num1,num2,sum;
* * **** * *** * ** ** * ** ** *** * *** **** * * *
* * * ****** = num1 + num2;


**** * ***** * *** * * * *** **** *****
* * * ** 0;

}
answered by (-320 points)
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.100.187
©2016-2024

Related questions

0 like 0 dislike
86 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18071 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.7k views
0 like 0 dislike
49 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18070 - Available when: Unlimited - Due to: Unlimited
| 980 views
0 like 0 dislike
62 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18067 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 1.2k views
0 like 0 dislike
21 answers
[Exercise] Coding (C) - asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18066 - Available when: 2016-12-01 18:30:00 - Due to: 2016-12-01 21:00:00
| 529 views
0 like 0 dislike
0 answers
[Resource] asked Dec 1, 2016 in 2016-1 程式設計(一)AC by Shun-Po (18k points)
ID: 18085 - Available when: Unlimited - Due to: Unlimited
| 10 views
12,783 questions
183,443 answers
172,219 comments
4,824 users