0 like 0 dislike
1.1k views

Trung is bored with his mathematics homeworks. He takes a piece of chalk and starts writing a sequence of consecutive integers starting with 1 to N (1 < N < 10000). After that, he counts the number of times each digit (0 to 9) appears in the sequence. For example, with N = 13, the sequence is: 

12345678910111213

In this sequence, 0 appears once, 1 appears 6 times, 2 appears 2 times, 3 appears 3 times, and each digit from 4 to 9 appears once. After playing for a while, Trung gets bored again. He now wants to write a program to do this for him. Your task is to help him with writing this program.
Input:
The input consists of several data sets. The first line of the input file contains the number of data sets which is a positive integer and is not bigger than 20. The following lines describe the data sets. For each test case, there is one single line containing the number N.
Output:
For each test case, write sequentially in one line the number of digit 0, 1, …9 separated by a space.

Sample Input

2
3
13


Sample Output

0 1 1 1 0 0 0 0 0 0
1 6 2 2 1 1 1 1 1 1

Sample Input 2

1
5


Sample Output 2

0 1 1 1 1 1 0 0 0 0
[Normal] Coding (C++) - asked in Introduction to Computer Programming II (C++)
ID: 49740 - Available when: Unlimited - Due to: Unlimited
| 1.1k views

2 Answers

0 like 0 dislike
Hidden content!
#include<iostream>
#include<cstring>
using namespace std;
int main()
{
    int a[10],b[20];
    int k,n;
*** * * ** * * ***** * * ** **
    for(int i=0;i<k;i++)
    {
****** * *** * **** * * ** * * *** * ** ****** ** ** *** *
** * *** * * *** ** * * ** ** *** * * * *** **
    }
    for(int i=0;i<k;i++)
    {
* ** **** * **** * ** * ****** ** * * *** * * ** *** * *
*** * * * ** ** ** * * * ** ** ** ** j = 0;j<=b[i];j++)
* ** ** * ** * *** * *** * * *** ** **
* *** * * **** * * ** *** * * * * ** * *** * * ** ** * * * k = j;
** ***** *** ** * *** * ** ** ** * ***** *** * * **** ***** *
* * * * * ** * **** *** * * * ** **** **** * * ** * ** * ***** *
** * * * ** ** ****** *** ** ** ** * * * ** ***** ** ** ***** *** * * * * * * ** ****** * * * num =k%10;
*** * * ** ** ** ****** * * * *** * * ** * * * ***** * ** ** * ** * *** *** *** * ** ***
*** * * * *** ** * ** * * ** ** * * * * ****** **** *** * *** *** *** * ** ** *** * * **
** * * * * * * * *** * * *** * * *** * * ** *** **** ***** *
** * *** * ** * ** * * * * **** ** **
** * **** ********** ***** ** ***** *** * * ** ** * *
*** * ****** * * ** *** ****** * * * * **
** * * * **** ********** ** ** * * * * ** ** * * * ** * ** *** **
* ** ** * * * *** ** * * ****** * * *
*** * ***** *** ** **** * * * * ** * j = 0;j<10;j++)
** *** ***** * * * * * ** *** * ***** *****
* * ** ** * * * *** * * *** * * ** *** ***** **
** * * * * * * * ** ** ** ** * ** * * **** * * ******* * * ****** * * ** ***** ** * ** * ** ";
* * * * * ***** ** * * ** * ** * *** *** *** ** *** * ******* **** * *** ** * *
* **** * ****** * ****** ** * **** * *** ** * * * ** * *** ** * **
* ** * * ***** ** ** * **** * * * * *
    }

    return 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <iostream>

using namespace std;

int main()
{
    int counter[10],counter2[10],arr[1000],arr2[1000];
    int n1,n2,n3,i,j=0,rem,dec,k;
    for(i=0;i<10;i++)
    {
* ** * *** * ** * * * * * ***** ** * **** *
** * ** ** * * *** * * ** * ** * ** ** * * * ** ****
* * * * * * ****** ** * * ** * ** *
    }
    cin >> n1;
    if(n1>1)
    {
*** * * ***** **** * ** * ** * * * ** ** >> n2;
*** *** * * ** * * * * * * * ***** * * >> n3;
      
***** * * ** * * *** **** * ***** ** * * * **** *** *
        {
* *** ** * ****** * * * ** **** * *** * *** ** ** ** ** * *
* ** ** ** ** * ** * * *** * **** * **** * ** * ** * * *** * * *
* **** **** *** * ** * ** * *** *** * * ** * * * ** * ** *****
* * *** * *** * * * * ** ** ** ***** ** * * ** * * * * *** * ** * *** *** * * * *
* * * * ** * ** ** * * * ** ** * ** *** * *** *** ** ** ** * * * * * *** ** ** *** * ***
* * * * *** ** *** * * ** * * * * ***** * **** **** * * * * **** * * *** ** * ** *
** *** * * **** * ** * * *** ** * ** *** * * * ** ** *** ** ** ** *** * ***** * * * *
* ** ***** ** **** * ** * ** * * * * *** * *** * ** **** *** ** * *** * * *** *
* * ** ** * * * ** ** * ** ** ** * * * * * ***** ****** *** ** * *** ***** ** * * ** *
** *** * ******* * ** * *** ** * * ** * * * ********* ** ***
        }
******* * * ***** *** ****** * * * ** * ****** *** *** * ** **
        {
** ** ** ** * * ** ***** *** * **** * * * ** * * **** ** ** * * ** * ***
****** *** * ***** *** ** * * ** ** * ***** * * *** ** *** **** ***
* * *** *** * * *** ***** * * * * * * ********* * **** ** * ** * * *** ** **** * ** **** * * * * * ** ** * *
* * ** ** ** **** * *** * ** * * * *** * *** *** ***** * *** **** ************ * ** *** *** **** ***
* *** * * * * * ***** * * * ** ** *** *** * * * ** ******
        }
**** * *** * * * * * * *** * *** ** * *** * ** *
        {
**** * * ***** * ***** * *** * ****** ** *** * * * * * ** * *** * *** * * *
* *** ** * * ***** ** *** * * ** * * ** * * ** ** ** ****** *
** *** ** **** * ***** * *** *** * ** ** ** ** * * ** *** * * * * * *** * ** **
*** ***** * * * ** * *** * ***** * ** * *** * * * ** * * ** * * * * ** **** * *** ******** ********* *
* *** * * ***** * * *** * * * *** * ** ** ******* * ** *** ** ** ***
        }
* *** * * *** **** * * *** *** ** ** *** * ** **
        {
* ** ** **** *** * * * * *** * ** * ** * * * * * *** * * ** * ** ********* **
* **** ** ** ** * * ** ** ** * ** * ** *** ** ** * **** * *** << counter[i];
** *** * * * * ** * ** * * * *** * ******* ** ** * * ***
** * * * **** ******* * * ** * * * *** **** * ** ** * ** << " " << counter[i];
*** * ****** ** * * ******* ****** * *** *
* ***** ** * **** ** ** *** *** * * * * ******* * * ** *
* * * * * * **** * ** * * * * * ** * ****** *****
** * **** * * * ** * ******** ** * * ** *** *
* ** **** ** ** * * * * ** * *** ** * * * *** ** * * **
** *** *** * *** ** * * ** ** ** ****** * ** *** **** * *** ** ** << counter2[i];
** * * ******* ** ** ** ** ** ** * *** ** **** ** *** *** * ** * * *
* * ** ** * ** ** * * * ** * ** ******* * ** ***** ** **** << " " << counter2[i];
        }
    }
    else
    {
* * **** *** ** * *** * *** *** * * * * ** ** ** **** * * * **

** ** * ** * **** * * * * * **** **** * * *** **
        {
*** * * ** **** * *** ** ** ** ** * ** * ****** ***** * * **
* ** * * ** * ** *** * ** * ****** * ** *** * ****** * ** * ** * *** *
* * * * * ** ** ** * ***** ** * *** * * ** * * * *** * *
** * ** * ** ** * ***** * * * *** * *** * ** * ** *** ** ** ** * ***** ** * ** * **
****** ** * ******* **** ** ** ** ***** ** *** ** * * **** * ** * *** **** * * ** ****** *** ***
*** ** * ** *** ** ** ** *** ** * ** **** * * * **** *** * * ** * ** * * * *** **** ** *
* * * ** ** *** * * * * ** * * * ** ** * *** * * * * ** * ** ** ** * * * ******** * * *
*** * ****** **** * * ** * **** * ******* **** ** * *** * * **** *** ** *** ** *
**** *** * * ** * **** * ** ****** * *** * * **** ** * ** * * * ** * * *** ** ** *** *
* ** * * * * ** **** * ***** **** *** * *** * ** * * ***
** * * *** * ** ** * * * ** * * ***
** ** ** * * * * ****** * ** ** ** **** * * *** * *
        {
** * * * * * ****** ** *** * *** *** ** ** * ** ** * * *** *** ****
* *** * *** * **** *** ***** * *** * ** * * ** * ***** * * ***
** * * * * ****** * *** **** ** * ** *** * ** ** * ***** **** * * * * * * **** * ** ** * *** *
*** * *** * * ** * ** * * *** **** *** ** * ** *** * ** ** * **** * * * * *** * ** * ***** * * ** *
* **** ** * *** * *** * ** *** * * * * * * * * *
** * ** *** * ** ** * * * * * *
      
*** * ** ** ** ** * *** ***** * *** * ***** * * * ** **** ***
* * * ** * * *** * * **** * ** ****** **** *
** **** ** * * ** * ** * * ** * * * * ** ** **** ** *** * *** *
**** * * * ** * * * ** * ***** ** *** * * ** ** * ** ***** * << counter2[i];
* * * *** ** ******** * ** * * ****** *** *** ** **** * ** *
***** ** ** * *** * *** *** ** ** * * * ** * ** * * << " " << counter2[i];
        }
    }
}
answered by (-323 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Why??
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.17.60
©2016-2025

Related questions

0 like 0 dislike
1 answer
[Normal] Coding (C++) - asked May 17, 2018 in Introduction to Computer Programming II (C++)
ID: 52073 - Available when: Unlimited - Due to: Unlimited
| 695 views
12,783 questions
183,442 answers
172,219 comments
4,824 users