0 like 0 dislike
1.5k views

Trung is bored with his mathematics homeworks. He takes a piece of chalk and starts writing a sequence of consecutive integers starting with 1 to N (1 < N < 10000). After that, he counts the number of times each digit (0 to 9) appears in the sequence. For example, with N = 13, the sequence is: 

12345678910111213

In this sequence, 0 appears once, 1 appears 6 times, 2 appears 2 times, 3 appears 3 times, and each digit from 4 to 9 appears once. After playing for a while, Trung gets bored again. He now wants to write a program to do this for him. Your task is to help him with writing this program.
Input:
The input consists of several data sets. The first line of the input file contains the number of data sets which is a positive integer and is not bigger than 20. The following lines describe the data sets. For each test case, there is one single line containing the number N.
Output:
For each test case, write sequentially in one line the number of digit 0, 1, …9 separated by a space.

Sample Input

2
3
13


Sample Output

0 1 1 1 0 0 0 0 0 0
1 6 2 2 1 1 1 1 1 1

Sample Input 2

1
5


Sample Output 2

0 1 1 1 1 1 0 0 0 0
[Normal] Coding (C++) - asked in Introduction to Computer Programming II (C++)
ID: 49740 - Available when: Unlimited - Due to: Unlimited
| 1.5k views

2 Answers

0 like 0 dislike
Hidden content!
#include<iostream>
#include<cstring>
using namespace std;
int main()
{
    int a[10],b[20];
    int k,n;
**** ** *** * * * * * *** * **
    for(int i=0;i<k;i++)
    {
* ** **** ** **** * * ** ** * ** * *** *** * **** *** * * *
* **** * * * * * * * * * ** * * **
    }
    for(int i=0;i<k;i++)
    {
****** * ** * * * * * * **** * ***** * *** **** * * *
*** **** ** * ** *** *** ***** * ** ***** * * * j = 0;j<=b[i];j++)
* * *** ** * * * ** ** *** ** * *** **** *
******* * * * * * ** *** * ** * * ** * ** * ** * * *** ******* k = j;
***** ** ** * * * * **** * **** ** * * * ** * ** **** * * ** * ***** * *
**** * * * ** * * * **** ** ** ** * * ** ** ***** ** ** **** * * *
** ** * * **** * * **** ** **** * * * *** * *** ** ****** ***** *** * **** *** * * * num =k%10;
** ***** * * ******* *** * * * ***** * * ** ** ** ** *** * * ** * * ** * * * ** ** * **
** ** *** * ** **** * ** ** ** *** * * * ** * ** **** * * ** ***** * ******* * ****
** ** * **** * ** * *** ** ***** ***** ** *** ******** * *** * * ** *
* * * * * ** ** * * *** * *** * * * **
** * ** * ***** ****** * * **** **** * **** * ***
* **** * * * ** ** * * * ****** * ** ** ****
* * * * ** ** **** ** * * ** * * * * ** * * ** * ** **** * ** **
* ** * ** *** **** ** ***** * ** * **** *
*** *** * **** * * * ** ** * * ** * *** * j = 0;j<10;j++)
* * * ***** *** ***** ** ******* *** *
* * ** **** *** *** * **** * * ** *** ***** ** * ** ** ** * * * * * * * ** *
** ** * ** * * *** * ***** * *** * ** * * ** * *** * * ** * ** **** ****** * * * ** **** ";
* * *** * ** * *** ******** * * * * * *** ** * * * * * ** *** * * ****
** ** ** ** * ** ** ** ******** * **** * *** ** ** * **** ** *** **** *****
* * ** **** ** ** ** * *** ** * * ** *
    }

    return 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <iostream>

using namespace std;

int main()
{
    int counter[10],counter2[10],arr[1000],arr2[1000];
    int n1,n2,n3,i,j=0,rem,dec,k;
    for(i=0;i<10;i++)
    {
** *** * * * * * ******** * * * ** ***** * * *
** ** * ** * * ** * * *********** *** * * * * ***
*** *** *** * ** *** * ** ** *** * * * * ** ** * * *
    }
    cin >> n1;
    if(n1>1)
    {
* *** * ****** * * *** * *** **** *** * ** **** >> n2;
* * * * * ***** * **** * ** * * * ***** ** >> n3;
      
** * *** * *** * ** * ** * *** ** * ** * ** *
        {
* ** * * ***** *** * ***** ** *** * * ** * ** * *** *** ** ***
** *** * ***** * ******** ** ****** * * **** * ** * * * ** * *** ** ** *****
* * * * ** * ** * * * ** * * * * * * ** * * ** ** ** ** * ** ****
*** ** *** * ***** ***** * * * ** * * * * * ** * ** ** **** * *** * ** ** * * **
*** * * *** *** **** ** * * ** * * * *** ** * * *** * * ** * ** ** *** * *** **** ***** ***
* * *** ****** * * * ** ***** ******** * **** ** ****** *** * * * ** * ***** *** ****** * ***
* ** * * * * * *** ** * **** * * ***** * ** ******* ******* *** * * * *
* **** *** * *** ********* *** * * **** ***** **** *** *** *** **** ** ** *** *****
** **** **** **** *** ** *** *** * * ******* * * ** * ** ** ** *** * *** * * ** **** *** ** *** *
* ** * * * * * ** * ** * * * ** *** * ***** * * ******* * * * * *** * ***
        }
*** * ** * * * * * ** ** * * ** * ** ** ** *
        {
* * * * * ** **** * ** * * * * ** **** ** * * ** * *** * ** * * ** ** ***
*** *** * **** ******** * * ***** ** ***** * ** * * *
* * * ******* ** *** * ** ** *** *** ** ** *** * *** ** *** ** ** * * * * *** * *** ** * ***
* **** * ** *** * * * * ** * * **** * * *** * * ** * * * *** * * ***** * ** **** * * ** *
** * * **** ** ** *** * * *** ** * * * * *** ** * * ** *
        }
*** * * *** ** * ** * ** *** *** ** *** *** * ** * **** *** *** ***
        {
* * * * ***** * ** ***** * *** * ** *** *** ** ** * ** ** * **** ** * ** ***
* *** * *** **** ** * ** ******* * *** * *** * *** * * * * *
* * ** * * *** ***** ** *** ** * ***** * * * * ****** ** * * *** * * ** *** ***** *
* ** *** * * * ** * * **** * * **** * * * * ** ** ** * * *** * ** * ** * **** * * **** *** ** * ** ** ***
****** * **** *** ** ** * * ****** * * ** ** ***** *** ** * **
        }
** * * * * *** * * ****** *** *** * * * ** ***
        {
* * ** ******* * ** * * * ** * ** * * ** *** * * ***
** * ** *** * ** *** * * ***** ** * ***** * *** * * **** * **** << counter[i];
* ** ** * * * ** *** *** * *** * ****** * * * * * * * *
* * ** * ****** ****** ** *** ** ** ** * ***** * ** ****** * * << " " << counter[i];
* ** * ** ***** * * ******* * * * **
*** *** * **** **** * *** **** * * * * ** ***** * *** *
** * * ** ** * * * * * ** ** * *** ***** ** ** ** * ** * *
*** ******* * * * * **** * ** * **
* ****** * *** * * ******** * * * * ** ** **** * **** *** ** **
****** * * * **** **** * * *** ** * *** * ** ***** ** * * *** *** ** << counter2[i];
* ** ** *** **** * * * ** ** *** * * *** ** ** **** ** **
** ** ** ** * * * * **** ** *** * * * * ** *** * * << " " << counter2[i];
        }
    }
    else
    {
*** * * * ** * ** * * **** *** *** * * * ** * * ***

* * * * ** * ** *** * *** ** * ** ** ***** * ** **
        {
* * * * * ** * * * ******* ** * ***** * ******* ** *** * ***** * **
****** * * ** * ****** **** ** * *** ** ************ *** ** * * ****
** * **** * * ** * ***** ** *** ***** * * *** ** * ** * ** ******* * *** *
** * ** * ** ****** * ** ***** ***** * **** * ** * ** * * * * **** ** ** * * ** * * ***
* ****** ** * *** ** *** * * ** * ****** ******** * * ** * * * * ** *** ** ** ** * ***
* * ** * * *** **** *** **** **** ** * ** *** *** ** *** ** * *** **** * * * * * ** *****
***** ** * ** *** * ** *** ** * * * * * * ********* ** * ****** ******* * * ***** * * ** **** ** ****
** ** ** *** * * * * ** ** * * * * * * ** *** * *** * * * * * ** ****** * *** ** **** **
* *** * ** ** * **** ** ** ** ** * * * * * * * ** * ****** ** ** * ** * * **** *
** * * ** * * * * * * * ** *** * ** * ** ****
** ** * * *** **** ***** * ** ** ** ** * **
* *** *** * ** ** * * * * **** * ** ***** * * * ***** * ***
        {
**** * ** * **** * ** * * * ** ** * **** ** *** ** ** ** * *** ** * *
* ** * ** * ** * * ** *** ** * * ** * *** ** ** ** ** *
* ** * * ***** *** * ** * * * ** ** * * * * ** * * ** **** ** * ** * * ** ** *** *** * * *
** ** * ** * ***** ****** * * * ** * * * * * * * ***** * *** *** *** * *** * * ** ** * *** * **** *
* *** ** * * *** ** ** *** *** * * ** * * *** * ** * * ** ** ** *
** * * * ** * ** * *** * * * * ******** * **
      
* * **** * *** *** * **** * ** * * * * *
* ** * * ** * * ** * **** **** * * ** ** *
* * ** *** ** * ** * * * * * * * ** ***** *** *** *** *** ** * * ** *******
*** ******** ******** *** ** ** *** ** * * * **** * ***** * *** * << counter2[i];
* *** *** * **** *** * **** * ***** * *** ***** *** ** ****** * * **** ** *
* * * * * * ** * *** ***** ** * *** **** **** **** ** * ** ** << " " << counter2[i];
        }
    }
}
answered by (-323 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Why??
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.214.39
©2016-2025

Related questions

0 like 0 dislike
1 answer
[Normal] Coding (C++) - asked May 17, 2018 in Introduction to Computer Programming II (C++)
ID: 52073 - Available when: Unlimited - Due to: Unlimited
| 1k views
12,783 questions
183,442 answers
172,219 comments
4,824 users