0 like 0 dislike
1.1k views

Trung is bored with his mathematics homeworks. He takes a piece of chalk and starts writing a sequence of consecutive integers starting with 1 to N (1 < N < 10000). After that, he counts the number of times each digit (0 to 9) appears in the sequence. For example, with N = 13, the sequence is: 

12345678910111213

In this sequence, 0 appears once, 1 appears 6 times, 2 appears 2 times, 3 appears 3 times, and each digit from 4 to 9 appears once. After playing for a while, Trung gets bored again. He now wants to write a program to do this for him. Your task is to help him with writing this program.
Input:
The input consists of several data sets. The first line of the input file contains the number of data sets which is a positive integer and is not bigger than 20. The following lines describe the data sets. For each test case, there is one single line containing the number N.
Output:
For each test case, write sequentially in one line the number of digit 0, 1, …9 separated by a space.

Sample Input

2
3
13


Sample Output

0 1 1 1 0 0 0 0 0 0
1 6 2 2 1 1 1 1 1 1

Sample Input 2

1
5


Sample Output 2

0 1 1 1 1 1 0 0 0 0
[Normal] Coding (C++) - asked in Introduction to Computer Programming II (C++)
ID: 49740 - Available when: Unlimited - Due to: Unlimited
| 1.1k views

2 Answers

0 like 0 dislike
Hidden content!
#include<iostream>
#include<cstring>
using namespace std;
int main()
{
    int a[10],b[20];
    int k,n;
** ** * * *** * * * * ** ***** **
    for(int i=0;i<k;i++)
    {
* ** **** *** * * * * *** ***** ******** * **** *** **
*** ** * ** * ** ** *** * * * * * * *
    }
    for(int i=0;i<k;i++)
    {
**** * * * ***** ** * * * ** * *** ** **** ** * * **
*** **** * ** ** * *** * ** *** * * * * * * *** j = 0;j<=b[i];j++)
** * ******* ** ** ***** ** * * * * ** * ** *
* ** *** ** ** * * ** * * ** ** ** * * * ** ** ** ** * * **** ** * * k = j;
* ** ** ** ** ** ** * * * ** *** * ** ** ****** * * * *******
* ****** * * * ****** * * *** * ** ** **** * **** ** * ** ** *
*** * * *** ** ** ****** * ** ** * * *** *** * ******* **** * ** * ** * num =k%10;
* ** * **** ** ** * ** * * ** ** * * ** ** * *** * * * ** *** * ******* **** ***** ** **** *
* ** *** * *** ** * * ** ***** *** ** ** ** * ** ** *** * * *** ** * * * * ** * *
* **** **** * ** * * * * ** * * ** ** ***** * * ** *
****** * ** ** ** **** * * **** *** **
* * * **** * ** * ** * * ** *** * * * ** ** *** *** * *** ** ****
* *** * ** ***** ** * *** ** *** * * *
* *** * * * * **** * ** * * * ** *** * *** ***** * * *** * ** * *
* ******* * * * ** * * * ** * * ***** * **** * *
* * ** * *** **** * ** * * * ** * * j = 0;j<10;j++)
* * *** * *** * * * *** * * *** ** *
** ** *** ****** * ** ***** *** * *** * ** ** *** * ** ** * *** **
* ** ** **** * *** * * * * * *** * ** ** **** * * *** * ****** * * *** ** ** *** *** * * *** ** ** ** * * ** * ";
* ***** ** * ** *** * ***** *** ****** ** *** *** * ***** ***** *
* ***** * * *** ***** * ** * ** * *** * * *** ** * * *
** * **** * **** ** * ****** * *** * * * *
    }

    return 0;
}
answered by (-304 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
0 like 0 dislike
Hidden content!
#include <iostream>

using namespace std;

int main()
{
    int counter[10],counter2[10],arr[1000],arr2[1000];
    int n1,n2,n3,i,j=0,rem,dec,k;
    for(i=0;i<10;i++)
    {
* * ** ** *** * * *** * * * * * * *
* *** * * ** * * ****** * **** ** ** ** * ** * ** *
* **** ** * ** ** ** ** * * ** * * ** ******* *** *
    }
    cin >> n1;
    if(n1>1)
    {
******** * * ** * * * **** * * * * * >> n2;
*** * *** * * ** * * ** *** ** ** >> n3;
      
* *** *** ** * ** **** ********* * ** *** * * **
        {
*** * * ** * **** ** * ***** ****** ** ** * * * * * ** *****
**** *** *** * ** * ** * ** ****** ** **** * ** ** ** ** * * ** * ** * * *
*** ** ** ** ** * * ** ** * ** * ** * ** * * ** *** ***** ****
** *** * ** * * ** ** * * * * ** * ***** * *** ****** ** ** *** *** * * * * ** * * * ** **
****** * *** * *** ** ** * ** ** * * ** ** * *** * *** ** ** * **** * * * * * ***
** * * ** * * *** *** ***** * ** * ** * * ** * * * ****** *** * * * * ** *** *** **
** ** * * *** ** ** *** ** ** * *** *** * *** ** * * * * * * * * *** **** ** **** ** * *
** ** **** * *** ** * * ** * * ** * * * ******** ** ** *** * * * * * **** *** ** ** ** ** *** *
*** ** * * * * * *** ** * ***** ** * * * * * ****** ** ** * ** * ** ******** * ** * ** * *** *** **
** * * * * * *** ** * * *** * * * * *** ** ***
        }
** * ** * ** ** * **** *** * ****** * ** ** * ** * ** * *
        {
** * * * ** ** ** * * *** ** * * * ** ** * **** * * * * * ******** **** *
** *** ** ** * **** *** ** * * * **** ****** ******* * * ** *
* * ** *** *** * ** * * ** * * ** ** *** ** * * *** * ** * * ****** * * * * *** * * *
** ** ** *** * * *** * **** * *** * *** ** ** ** ** ** **** **** * ** ** *** ***** * * ***** * *** ** ** **** **
*** *** ** *** *** ** ***** *** * *** * * ** * * ** *** **
        }
* * * * ** *** * ** *** ** * * * * ** *** ** **
        {
** * * * * * *** * * * ** * * ** * *** * ** ** * * ** * * * *** ** * ** ** * *
*** ** ** * * * * * * ** **** ** * ** * * **** *** * * **** * **
*** *** * **** * ***** * * * * * ** * * **** **** * ** ** ** * *** *** * ** * *** *
* * * * ** ** * *** * ** ** * * ** * ** *** * *** ****** *** * * *** * ** ** *** * * ** *** *** ** ** **
*** * * * * * *** * * **** * ****** * * ** **** * * * * * ***** *
        }
* *** * ***** * * * **** * ** ** * ** * * * * ** * ***
        {
** **** ** ** *** * ******* *** * ** * ** ******** * * **** * * ** *
** **** ** ** ******* *** *** *** ** *** * * * * * ***** << counter[i];
* ** ** ** **** * * * *** ** ** * *** ** * **** * ** **** **** **
* * ** * ** *** * * * * *** *** * * ** * ** *** * ** ** ** ** << " " << counter[i];
** * * ** *** * ** ***** * * * ** *** * **
* ** ** * * ******* * * ****** ** * * **** ** * ***** **
****** ****** * *** *** * **** ** *** * ***** **** **** ****** *
* ****** * ***** * * *** ** * * * **
* * **** * ** *** * * * * ** **** * * * * **** * ** **** *** ** * * ***
* *** *** ** ** * ** ** * *** *** **** * ** * * *** * ******* ** << counter2[i];
** ** **** ***** **** ***** ** * ** * * * * * * ** ****
*** ** ** * * **** ** * **** ****** ** ****** * ******* * * *** * *** * << " " << counter2[i];
        }
    }
    else
    {
* * *** * **** ********* ** ** ** * *** *** ** *

* ** * ***** * ** *** *** ****** * ** * * **** ** * * **
        {
** * ** * **** * ***** * * ** ****** ** *** * ** * ** * * **
* * * * * ** * ** * * *** * * * ** *** * * ** * * ** ** ** ****
**** ** **** ** *** * * * *** *** ** * * *** * ***** *******
** ** ** ** *** ** * * * * ** * ** ** * ***** * *** * ** * * ** * ** * *
** ** *** *** ** ** * * ***** *** ** ** *** * ** ** **** * * * ** ******* ** * * * * *** * * * *
**** * * **** * * ** *** ****** * * *** ***** * * ** *** * * * *** *** * * * * ** ** *
** * *** ** * ** ** * ** ** * ** *** ** *** ** * ** ** * ** * * ** * * * * *** **** * *
* * * * * * ** * ** ** * * * ** ******* * *** ** ** *** *** * * ** **** * * * * * *
* *** * **** * *** ** * ** * *** ** ****** * *** * * ** * * * ** ***** * * * * ***
** ** ** * * * * **** ** **** * * *** * *** * ** ******* * * ** *
* * * ** * * * * * *** * ** ** * ** * *** *** *
** ********** * * ***** ** * * * * *** ** ** * * * ** *** *
        {
** * ***** * * ** * * ** * ** * * * * *** *** ** **** * * * * * ** * * * * * **
******** * * **** ***** **** * * * * * ** * *** *
**** *** ** * **** ** * * * ** * ** * ** *** **** * * ** ** *** ** * * * * *
*** * * * * * * **** * * * *** * * ** * * * * ** ***** **** **** * * ** * **** *** **** * * * *** **
***** *** * * * ** *** * ** * *** * ** * * * ** * * ********* *** ** *
** ***** *** ** ***** * ** * ** **
      
* *** * ** * * ***** *** ** *** * * * ** ********* *
****** * * *** ** ** * * *** *** **** *
** * * * * ** ** *** * * * * * * *** ** * *** * ******* *** *
*** * ** ** ** **** * *** ** **** *** ** *** * ***** * * ** * * << counter2[i];
** ** * * * * * * * ** ***** * * ** * ** *** ** ** *** ****
* * ***** *** * *** * **** * * *** *** *** * **** * * * ** * << " " << counter2[i];
        }
    }
}
answered by (-323 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
0 0
Why??
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.69.58.93
©2016-2025

Related questions

0 like 0 dislike
1 answer
[Normal] Coding (C++) - asked May 17, 2018 in Introduction to Computer Programming II (C++)
ID: 52073 - Available when: Unlimited - Due to: Unlimited
| 697 views
12,783 questions
183,442 answers
172,219 comments
4,824 users