0 like 0 dislike

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數),計算其總合。C語言不提供大數資料型態,但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
Available when: 2018-01-20 09:00 - Due to: Unlimited
| 63 views

4 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char input[500],s1[500],s2[500],temp;

int i,space,sum[500],carry,temp2,flag=0;

int main(){
** **** * ** ** * ** ** * * * ** %s",&s1,&s2);
** *** ** ** * * * ** * * *

///get space
* ** ******* ** ** ** * *** * * *** ** *
*** ** * * * **** * * * ***** * ** * * * '){space=i;}
    }

///get s1
******* ** * **** **** *** * ';i++){
**** * * * *** * * ***** * ** * * **** * **** *
    }

*** * ***** *** * * ** *** * * ***
///reverse input
*** ***** * * * * ** *** ** * * ** * * **
*** * *** ** ** * * ** ***** ** * * ** *** *
****** ****** *** * ***** ** * **** ***** *** * *** * ** * * * ** *
* ** * * *** * * * * * *** *** *** * * *** * * *
    }

///get reversed s2
* ******** * * ** * * * * ';i++){
* * * * * *** * * * * * * ** *** * * * ** **** **** **
    }

///reverse s1

*** ******* * * * *** * ** * * * * * * **
*** * * * **** * * ****** ** ** ***** ** *** *

*** ** ** * * **** * ***** * * * * ** * ** ** *** * * * **
*** * ** ** ** ** * * ** * **** ** * **** * * * ** ** *
    }

///sum s1 and s2
* ** **** ** *** * * **
*** * *** ******* ** * * * ** * ** **** *
** * ** * * * * ** * ** ** * * ** ** ** ***** *** * ** * * * * *
** ***** * **** **** ** * ** * * *** * * * * * * * * * * * ***
** ******* * **** **** *** ****** * *** * * * *
* ** * *** * * ** * *** * * **
** ** ** * * * * ** * * *** **** ***** ** * * *

    }

* ****** ** *** * * * ******* * * rev:%s\n",input);
* * * * * ** * * * *** *** ** ** rev:%s\n",s1);
* ** * * * ** ***** * ** * ******* rev:%s\n",s2);
* *** * ** ** * * ** ***** * ** ** * *** ** ** *** * * **** *** ****

///reverse output
** *** * * * * * * *** *** *****
* ** *** ** * ** *** ** * * *** * * * * ********

***** *** ** * * ***** ***** *** * *** * * ** * * * * *
** * * ** *** *** * * * ** * * * ** ** *** * *
    }

///print
* ****** * ** **** *** ***** **
* * * *** * * * ** * * * *** * * * * * * * * ***** ** ** ****
** * ** * *** *** * *** * ****** * * *** ***** ** ** ** * * * *** * * ** ** *
** * * ** * ** * * * ** ** * * **** ** ** * * * *** * ****** ** ** **** * * * *** * * * *** ** * *** * *
** **** ****** ** * * *** ** * * * ** * *** ** * * *** *** * * ****** ******
* *** * ** **** * * * * * *** *** * * * * **** * * * * *

* **** * * * * * * ** *** ***** **

    }
** * ** ** *** * * * * ** ** * *
    return 0;
}
answered by (-282 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
prog.c: In function 'main':
prog.c:80:12: warning: multi-character character constant [-Wmultichar]
     printf('10');
            ^~~~
prog.c:80:12: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:80:5: warning: format not a string literal and no format arguments [-Wformat-security]
     printf('10');
     ^~~~~~
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* ** * ** * ** ***** string1[50];
** ** * ** ***** * **** ** string2[50];

* * ** * ** ** **** * ** * ***** string1);
*** * ** * * * *** * ** string2);
*** ** * *** * * * * * * arr[51]={0},i;

*** *** * ** * ** * * ** * * *** i<strlen(string1); i++)
* **** ** * ** ** * ****
*** * ***** **** * ** ***** *** ** ** **** **** += string1[strlen(string1) - 1 - i] - 48;
    }

* ******* **** * * * *** i<strlen(string2); i++)
** ***** * * **
* ** ** **** * *** * ** ** * * * * * * ** * * ** += string2[strlen(string2) - 1 - i] - 48;
* * ** **** ** **

** * * * * * ** * i<50; i++)
** **** ** * **** * *** **
* * ****** *** *** ** * * *** ** ** * * * * > 9)
*** **** **** * * ** ** * * ** * ** ***
* *** * * * ** * ** * * * * ** * * * *** ** * ** * * * * * -= 10;
****** ** ******* * * ** *** * * * * * * **** * * * * ** * ** ** *
** * ** ** ** ** * * ******* *** * *******
*** * ** *** *

* *** **** ** * * * * * i>=0; i--)
**** ** **** * * *** * *
** *** *** * * * *** * **** * * * * *** * *** != 0)
* ** ** * ** ********* ** * * * ** * * *********
* *** * * * ** *** ** ***** *

** * * *** * * * * ** * *** i--)
****** * * ** * * * * *** * * ** **** * **** * * ** ** ** ** **** arr[i]);
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main (){
int s1,s2,l1,l2;
int num1[50],num2[50],sum[50];
printf("enter input 1: ");
* ** *** *** ** * ** ** *
printf("enter input 2: ");
**** * *** * * * * * *
for(l1=s1[l1]!='\0')
* ******* ** **
for(l2=s2[l2]!='\0')
** *** *** * *** **** * ** *
int carry=0;
int k=0;
int i=l1-1;
int j=l2-1;
* ** *** ** * **
{
**** **** * ** * * ** * ******* **
* ** *** *** * *** ***
* * ** ** ** * * ****** * ** * * * * * **
* * * ** * ** * * ****** * * ** * * *** * ** * ** **** * * * ** ** * ** * * **
* **** *** * * ** ** *** * * ** *** *** ** * ** * * ******* *** ***** * **
** *** * * ** *** *** * * *** if (j>=0)
** * * * **** * * ***** * **** * * ** * * *
*** ** ** ** * ** * * * * * ** * * * * ** * * ** ***** * * **** **** * ** * ** **
* * * * * * ** * * * **** ** *** * * * ** ** * * *** * ** * ** * ****
**** * *** *** *** *** * * * **** * * * * * *** * if(carr>0)
* * *** ** * *** * *** * *** * ** ****
** ** * *** *** * * ***** * ** ** *** * * *** * ");
*** * * ** ** ** * * * ** * ** * * ** **
}
for(k--;k>=0;k--)
*** * ***** * ** * * * *
** ** ** * ** * * * ** * * ** ** *
* * ***** ** * *
  return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:9:10: error: subscripted value is neither array nor pointer nor vector
 for(l1=s1[l1]!='\0')
          ^
prog.c:9:20: error: expected ';' before ')' token
 for(l1=s1[l1]!='\0')
                    ^
prog.c:9:20: error: expected expression before ')' token
prog.c:10:10: error: subscripted value is neither array nor pointer nor vector
   num1=s1[l1]-'0';
          ^
prog.c:11:10: error: subscripted value is neither array nor pointer nor vector
 for(l2=s2[l2]!='\0')
          ^
prog.c:11:20: error: expected ';' before ')' token
 for(l2=s2[l2]!='\0')
                    ^
prog.c:11:20: error: expected expression before ')' token
prog.c:12:12: error: subscripted value is neither array nor pointer nor vector
     num2=s2[l2]-'0';
            ^
prog.c:17:15: error: expected ')' before ';' token
 for(;i>=0;j>=0;i--;j--;k++)
               ^
prog.c:23:13: error: expected ';' before 'carry'
             carry=(num1[i--]+num2[j]+carry)/10;
             ^~~~~
prog.c:27:13: error: expected ';' before 'carry'
             carry=(num1[j--]+num2[j]+carry)/10;
             ^~~~~
prog.c:28:18: error: 'carr' undeclared (first use in this function)
         }else if(carr>0)
                  ^~~~
prog.c:28:18: note: each undeclared identifier is reported only once for each function it appears in
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>


int main()
{
* **** **** * ** **** * a[50],b[50];
* * ***** * * * * * * c[51]={0};
** * * ** **** * * i;
* ** *** * * *** ** **** * * x=0;

** *** ** *** **** * ** * * %s",a,b);

* * * ** ** * ****** * * ** **** ** * * *
    {
* ************ * ** * ** * ***** *** ** ** * * * * *** * ** *
    }

* * ** ** *** * * * ** ** * *** ***
* *** * ** *** * **
* ** * * ***** * * *** * * ****** * ** ** ** ** ** * ** * *
* * ** *** * * * * ***


*** * *** ************ ** * * ***
* * * ** ** * ** *
***** ** **** ** ** * *** ** * **** ******* ***** * *
*** *** * * ** * * * * ** ***** ******* *
* * ** * * * * * ******** ** ** ** **** *** * * * **
** ** * * ** * * * *** * *** ** ** ** * * ** ** * *** ** * * * *
* ***** * ** * * ** * * ****** ** **** **
    }

* * ***** ****** * * *** **
** ** ** * ** ** * ** ****
* * **** *** *** *** * *** * * ** * * ** * * * != 0)
* * * *** *** ** *** * ** * ** ** ***
***** *** * * * *** * ******* * ** * ** * ** * * * * **** *****
** *** * ** ** * * *** ** *** ******* ** * * ** **** * * **
* * ** ** **** ** * * * ** ** ** ** * ****
    }

* * ** ******** * ***** * * *
    {
* * **** * * **** ** * * * *** ** *** * * * * * *** ** ** * * *
    }


* **** * ** *** * * *** * * * 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Get it on Google Play Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.68.65.234
©2016-2019

Related questions

0 like 0 dislike
13 answers
[Exam] asked Jan 19, 2018 in Final Exam
Available when: 2018-01-20 09:00 - Due to: Unlimited
| 102 views
0 like 0 dislike
6 answers
[Exam] asked Jan 19, 2018 in Final Exam
Available when: 2018-01-20 09:00 - Due to: Unlimited
| 59 views
0 like 0 dislike
8 answers
[Exam] asked Jan 19, 2018 in Final Exam
Available when: 2018-01-20 09:00 - Due to: Unlimited
| 72 views
0 like 0 dislike
12 answers
[Exam] asked Jan 19, 2018 in Final Exam
Available when: 2018-01-20 09:00 - Due to: Unlimited
| 142 views
1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
Available when: 2018-01-17 14:00 - Due to: Unlimited
| 244 views
9,463 questions
90,642 answers
70,601 comments
2,860 users