0 like 0 dislike

You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數),計算其總合。C語言不提供大數資料型態,但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
Available when: 2018-01-20 09:00 - Due to: Unlimited
| 27 views

4 Answers

0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>

char input[500],s1[500],s2[500],temp;

int i,space,sum[500],carry,temp2,flag=0;

int main(){
** * * * **** * *** ** ** * *** * * %s",&s1,&s2);
** ** ** *** ** ***** ** ** ** * *

///get space
*** * ***** *** * ******* * ** **** ** * *
* ** ** * * * * * * ** * * * *** ** *** '){space=i;}
    }

///get s1
* * *** * * ** * * * * * * * ';i++){
** **** *** ***** * * * *** *** ** ** * * *** ** ** ****** *
    }

**** * * * * * ** * * * * * *** * **
///reverse input
*** ** *** * ******** *** ** ** ** * *** *
* * **** * ** * *** *** ** * * * ** * ** * ****
******* * ** * * * ** ** * * *** * * * * * *
* * ** **** * * * ** *** * * * * *** ** ***** * ** * ****
    }

///get reversed s2
*** * * *** ***** * * **** * ** ';i++){
*** * *** * * **** * *** * * ** ** ** * * **
    }

///reverse s1

* * *** * *** * * ** *** **
*** * * * * *** * * ***** * *** *** **** *

* ******* * ** **** *** * ** **** * * ****** * * ** * * * * ** *
* * * ** * * * ** * ** * ** *** ** *** ** ****
    }

///sum s1 and s2
* * ** * * *** ** ** *
* * * ** * *** ** ***** ** * ** * **
** ****** * ** * *** ** *** *** * ** ** ** * * * * *
** ** * * * ** * ***** * * ** * *** * * ***** * * * * *
*** ** * ** *** * ** ** * **** ***** **** * * * * **** * * * * ** *
* ** * * ** ***** ** *** * * * ** * * ** * *
* * * ** * * ** * * *** * *** *** * * * **

    }

* * * * * * * * * * * * * * * *** * rev:%s\n",input);
* * * * * *** * * * * ** * ** rev:%s\n",s1);
**** * * * * * ***** **** ***** **** * rev:%s\n",s2);
***** ** *** ** *********** * * * ** ** ******* ** **** ** ** * * * * * ***

///reverse output
* * *** * * ** *** * *** ** * *
**** * ** * **** * * ** *** * * ** *** ** * ** * **

** * ****** * *** * ***** ** *** * * * * * * ** *
* * ** ** * ** * * * *** * ** **
    }

///print
*** * **** ** * *** * ***** * ** ***
* **** **** *** ***** * * * * ** *** *** * * *** ** ** ***** * * *
** ***** * *** * **** ** * ** * ** * ** ****** ** **** * * *** * * *
** ***** ** * * * * ** * * * ** * ***** ** * * * * * *** * ** ** * * ** * ** *** ******* **
* * *** * ** *** ** ** ** * * * ** * ** * *** * * ****** * * * ** * * ** *****
* * * * *** * * * *** ***** **** * ** * * *** *

* * * * **** *** **** * * *** ***

    }
** *** * *** * ** * **** *** *** *** *** **
    return 0;
}
answered by (-256 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
prog.c: In function 'main':
prog.c:80:12: warning: multi-character character constant [-Wmultichar]
     printf('10');
            ^~~~
prog.c:80:12: warning: passing argument 1 of 'printf' makes pointer from integer without a cast [-Wint-conversion]
In file included from prog.c:1:0:
/usr/include/stdio.h:364:12: note: expected 'const char * restrict' but argument is of type 'int'
 extern int printf (const char *__restrict __format, ...);
            ^~~~~~
prog.c:80:5: warning: format not a string literal and no format arguments [-Wformat-security]
     printf('10');
     ^~~~~~
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 0
Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
0 like 0 dislike
Hidden content!
#include<stdio.h>
#include<string.h>
int main()
{
* **** * * * ** ** string1[50];
**** * *** * ****** *** * string2[50];

** ** *** ** ***** * *** * ** ** string1);
* * * * ***** * **** ** ** * * ** string2);
* *** * * * **** ** * ** ** arr[51]={0},i;

**** * ** * * *** * ** * i<strlen(string1); i++)
* * ** * * * ** *****
* * ** **** * ** * **** ** ** ** * * * += string1[strlen(string1) - 1 - i] - 48;
    }

**** ***** ** * * * * ** * i<strlen(string2); i++)
** ** *** * * ** * * *
******* * * * * ** ** ** ** ** *** ** * ** ** += string2[strlen(string2) - 1 - i] - 48;
*** *** * ** **

*** ** * * ******* i<50; i++)
** * * ****
* ** * *** * ** * * ** * ** ** * * * ***** > 9)
** * **** * ** * * * ****** * * * ***
* **** ** ***** ******* ** ** * **** ** **** ** * ** * * * ** ** ** * * -= 10;
* * *** ***** ** * * ** ******* * * ** * * * * * * ** *** *** * ** ***
*** * * * ***** ** * * **** * ** * * *** * *
* * * *** *** **

**** * * *** * * * * ** i>=0; i--)
** *** ** * *** * * *
* * ** * * ******** * ** * * *** ****** * != 0)
** * ** **** * * * ** * **** ** * * ** * * * *** * **** ***
* **** * * *** *

** * *** * * * * **** * * *** *** i--)
* ** **** * **** **** * ******* *** *** * * ** * arr[i]);
}
answered by (-168 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
0 like 0 dislike
Hidden content!
#include <stdio.h>
int main (){
int s1,s2,l1,l2;
int num1[50],num2[50],sum[50];
printf("enter input 1: ");
** *** ** * ** ** * ** *
printf("enter input 2: ");
** * * * ** ** **** * *
for(l1=s1[l1]!='\0')
** * * * *** ** ***
for(l2=s2[l2]!='\0')
** ** *** * * *** * ** ****
int carry=0;
int k=0;
int i=l1-1;
int j=l2-1;
*** *** * * **
{
** ** ** * ** *** **
* ** * * * * *** *
*** * ** *** **** *** ******** * ** * * * * ** * * *
* * *** **** * * ** ****** * * ** *** ** *** * * * ** * * **** * ***** *
*** ********* ** * * ** ** * * ** * ******** **** * *** * * * *** *** * * *
** * * * * ** ***** * ** if (j>=0)
*** * * *** **** * **** * * ** *
* * ********** ** * * * ** **** ** * * ** * * ** ** * * * * * ** * **** ** * ****
* ** * * * ** * * *** ** * *** * ** * * **** * * ** ******** * ***** *
* ***** ** * ** ** ***** *** * ** if(carr>0)
*** ** * ** *** * * ***** *** **** ** *** *
*** * * *** ** * * *** ** * **** * ** **** ** * ** * ** * **** ");
* ** ** * * ** * * * * **** ** * ** *
}
for(k--;k>=0;k--)
* * ** * * * ** * ****
* ****** ** ** *** *** * ***** * * * *
* * * * ** * **** *
  return 0;
}
answered by (16 points)
0 0
prog.c: In function 'main':
prog.c:9:10: error: subscripted value is neither array nor pointer nor vector
 for(l1=s1[l1]!='\0')
          ^
prog.c:9:20: error: expected ';' before ')' token
 for(l1=s1[l1]!='\0')
                    ^
prog.c:9:20: error: expected expression before ')' token
prog.c:10:10: error: subscripted value is neither array nor pointer nor vector
   num1=s1[l1]-'0';
          ^
prog.c:11:10: error: subscripted value is neither array nor pointer nor vector
 for(l2=s2[l2]!='\0')
          ^
prog.c:11:20: error: expected ';' before ')' token
 for(l2=s2[l2]!='\0')
                    ^
prog.c:11:20: error: expected expression before ')' token
prog.c:12:12: error: subscripted value is neither array nor pointer nor vector
     num2=s2[l2]-'0';
            ^
prog.c:17:15: error: expected ')' before ';' token
 for(;i>=0;j>=0;i--;j--;k++)
               ^
prog.c:23:13: error: expected ';' before 'carry'
             carry=(num1[i--]+num2[j]+carry)/10;
             ^~~~~
prog.c:27:13: error: expected ';' before 'carry'
             carry=(num1[j--]+num2[j]+carry)/10;
             ^~~~~
prog.c:28:18: error: 'carr' undeclared (first use in this function)
         }else if(carr>0)
                  ^~~~
prog.c:28:18: note: each undeclared identifier is reported only once for each function it appears in
0 like 0 dislike
Hidden content!
#include <stdio.h>
#include <stdlib.h>
#include <string.h>


int main()
{
* * * * * * * ** a[50],b[50];
*** ** ** ** **** ** ** ** c[51]={0};
* * * * * * * * *** **** i;
* ********* *** * * *** x=0;

* *** ** ** *** *** * ** * ** %s",a,b);

****** *** *** * * ** * * ** **** ****** *
    {
*** * ** * * ******* ** * * ** * * * * * * ** ** * * *
    }

* *** ** * *** * * *** ** * **
***** * * * * *
* * * *** * * ** *** *** ** * ** * * * * ** * ** ** *******
* * * ** * ** *****


*** * * ** * ***** **** ** ***** **
** ** * * * *
***** **** * * * ** *** * *** * ***** **** * * ** * **
* * ** * ** **** *** ** *** * ** * * ** ** ***
* ****** * *** *** * * * *** * ** * ***** * ** **
* * ** * * *** * * * * ** * * * *** *** *** ** ** *** * ** * * ** *** *
** ** * * * * *** * * * * * *** **
    }

* *** * * * * *** * **** ** **** *
* * *** * ** * * ***
* * * **** *** * * ** * * *** ** *** ** ***** ** != 0)
** ***** ** *** * * * * **** ** * ** *** * *
** * * ** *** **** * ** **** *** ** *** ** *** * * * * * *** * **** * * * **
* *** * ** **** ** * ** * * ** * ** * * ** *** * ** * * **********
** * * * * * * *** **** ****** * * **
    }

* * ** * * * * * *** *
    {
* * * * ****** * * ** * ** * * * ** * *** * **
    }


* * *** *** *** * * * * ** 0;
}
answered by (-193 points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Get it on Google Play Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:162.158.79.227
©2016-2019

Related questions

0 like 0 dislike
13 answers
[Exam] asked Jan 19, 2018 in Final Exam
Available when: 2018-01-20 09:00 - Due to: Unlimited
| 63 views
0 like 0 dislike
6 answers
[Exam] asked Jan 19, 2018 in Final Exam
Available when: 2018-01-20 09:00 - Due to: Unlimited
| 38 views
0 like 0 dislike
8 answers
[Exam] asked Jan 19, 2018 in Final Exam
Available when: 2018-01-20 09:00 - Due to: Unlimited
| 45 views
0 like 0 dislike
12 answers
[Exam] asked Jan 19, 2018 in Final Exam
Available when: 2018-01-20 09:00 - Due to: Unlimited
| 66 views
1 like 0 dislike
37 answers
[Exam] asked Jan 16, 2018 in Final Exam
Available when: 2018-01-17 14:00 - Due to: Unlimited
| 106 views
9,249 questions
85,527 answers
63,421 comments
2,707 users