Final Exam 3 (20%)

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You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
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32 Answers

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#include <stdio.h>
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#include<stdio.h>
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#include <stdio.h>
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#include <stdio.h>
#include <string.h>
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#include<stdio.h>
#include<string.h>

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prog.c: In function 'main':
prog.c:14:1: error: expected declaration or statement at end of input
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prog.c:14:1: error: expected declaration or statement at end of input
commented by (4.3k points)
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prog.c: In function 'main':
prog.c:14:1: error: expected declaration or statement at end of input
 {
 ^
prog.c:14:1: error: expected declaration or statement at end of input
commented by (4.3k points)
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prog.c:8:1: error: expected '=', ',', ';', 'asm' or '__attribute__' before 'int'
 int main()
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prog.c: In function 'main':
prog.c:7:12: error: expected '=', ',', ';', 'asm' or '__attribute__' before '.' token
 char s1[50]. s2[50];
            ^
prog.c:7:12: error: expected expression before '.' token
prog.c:10:13: error: 's1' undeclared (first use in this function)
 scanf("%s", s1);
             ^~
prog.c:10:13: note: each undeclared identifier is reported only once for each function it appears in
prog.c:11:13: error: 's2' undeclared (first use in this function)
 scanf("%s", s2);
             ^~
prog.c:12:18: error: expected ';' before '!' token
 for (l1=0;s1[l1] ! = '\0';l1++){
                  ^
prog.c:15:22: error: expected ';' before '!' token
     for (l2=0;s2[l2] ! = '\0';l2++){
                      ^
prog.c:28:1: error: expected declaration or statement at end of input
 }
 ^
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Hidden content!
#include<stdio.h>
#include<string.h>
int main(void)
{
    int i,j,aa,bb,cnt=0,sum[51]={0};
    char a[51],b[51];
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    return 0;
}
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Hidden content!
#include<stdio.h>
#include<string.h>

int main(){
    char a[50],b[50],sum[51];
*  ** * **   * *  * * ****  *      i=0;i<51;i++) sum[i]=-1;
** **  *** **    ******    ***   * %s",a,b);


    int n=strlen(a),m=strlen(b);
    int stop=n>m?n:m;

    int carry=0;
***     ** *  *  *   *** * *  **  *  i=1;i<=stop;i++){
 *    * *  **** **     **  **  * **** ** * ** **  *    *** * * ***         *** *  * q,w;
   ** *** *  **** *   * *      ** ***   **    * *** *  ** * * *  * * ** **     
  *  ***** **** * ****  *******      *   *   **    * * **  *   * **** * *  *   *  **   *    ** *    * * *  *   **  ***  *  * * **
    ** ** ***  *  **    *  *  ***  * ** ** * * * *** ** ***  * *  *  *** *  * *   * * if(m<i)
 * ****  * ** *      **    ****  * **    * **   ** * **  *   * * * *  ****  * * * *****  ******** *** * ***  ** **  *  *  ** *
 * ** * *** * ***  *  ****  * **  **  ** * * * *** ***    **  * **** ***     *  ****
*   ******** *   *** * ***  *** *** *   *    *  * ****    * * *** ** * *        **   * **  *  *    ***** * ** **   *   * * 

**     * *   **** ***   *   * *   *     * ***   *   **   * ** *    ** ****   *** ***** **  **
** *** ** **  **** ***  **  *** ** * *** *  ***  ****  ** **** **  **    *    ********** **  * *  ***   *   * **
** *    ****   **  ** *   * **   *   * * * ** ***    *     ** *   * **  ** ** *    * *    **** *   * **   * ** ***** **  ***
***  *  *** * **  ** *** **    **  * *  *   ** ***   *  **  *  **    ** *  *  ** **  *  * *** ** *  * * *  * *  ** **** *  sum[stop-i]=1;
  ** * ** *  *       *    * *  ***  **  *** *  **    ****  * ***   * ** *** * **  *** *  ***     ***  * ** *  * sum[stop-i]=0;
 *  **    ** **   * **** *** ***  *   **     *  ****   *    * ** **  * * ***    
  **  **  *   * *   * *    **       *****    **  * *  ** ** ** *  *  ***  *
  *  *** ****** * *  ***  **      ** * * ***** **   **** ***  **   ***  ** *  * **  **     *** *  * **** **  **  * 
  ***  * ** * **    *  ***   ** **       ** *****  *  * **   * **  **   * *   *  * * *    *  **    
    }

** * * *  ****  *  ** *     *** i=0;i<51;i++){
  *  * ** *   *** **  ** *    *  * *  ****** ** ***  *** **  ** * printf("%c",sum[i]+'0');
    }


 * **** *  ** ***      **  ** *  0;
}
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Case 2: Correct output
commented by (4.3k points)
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