Final Exam 3 (20%)

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You are requested to help in writing a program to perform addition of two large number up to 50-digits. In C there is no builtin datatype for large number, but we can use characters and array to solve the problem.

Input: The input will contain two positive integers are separated by a blank, the two positive integers do not exceed 50-digits.

Output: Sum.

寫一個程式輸入兩個大數(最大50個位數)，計算其總合。C語言不提供大數資料型態，但我們可以用字元和陣列來解決這個問題。

Example input:

999999999999999999999999999999 999999999999999999999999999999

Example output:

1999999999999999999999999999998

 

[Exam] asked in Final Exam
ID: 42300 - Available when: 2018-01-17 14:00 - Due to: Unlimited
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answered by (-233 points)
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prog.c: In function 'main':
prog.c:8:12: warning: format '%d' expects a matching 'int *' argument [-Wformat=]
    scanf("%d");
            ^
prog.c:10:9: error: 'i' undeclared (first use in this function)
    for (i<=50; &m; ++i);
         ^
prog.c:10:9: note: each undeclared identifier is reported only once for each function it appears in
prog.c:15:4: error: expected ';' before '}' token
    }
    ^
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answered by (16 points)
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prog.c: In function 'main':
prog.c:6:9: warning: format '%d' expects argument of type 'int *', but argument 2 has type 'int (*)[50]' [-Wformat=]
 scanf("%d",&a);
         ^
prog.c:7:10: error: empty character constant
 if(a[i]!=''){
          ^~
prog.c:8:15: warning: comparison between pointer and integer
     for (i=0;i<a;i++)
               ^
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#include<stdio.h>

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answered by (-167 points)
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prog.c: In function 'main':
prog.c:11:10: warning: format '%d' expects argument of type 'int', but argument 2 has type 'double' [-Wformat=]
 printf("%d",sum);
          ^
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#include<stdio.h>
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prog.c: In function 'main':
prog.c:8:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
 scanf("%s",&s1);
         ^
prog.c:9:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
 scanf("%s",&s2);
         ^
commented by (4.3k points)
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prog.c: In function 'main':
prog.c:9:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
 scanf("%s",&s1);
         ^
prog.c:10:9: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
 scanf("%s",&s2);
         ^
commented by (4.3k points)
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#include <stdio.h>
#include <string.h>
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prog.c: In function 'main':
prog.c:9:14: warning: format '%d' expects argument of type 'int', but argument 2 has type 'size_t {aka long unsigned int}' [-Wformat=]
     printf("%d\n",strlen(A));
              ^
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# include <stdio.h>
# include <string.h>
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#include<stdio.h>
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prog.c:1:1: error: expected '=', ',', ';', 'asm' or '__attribute__' at end of input
 d
 ^
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Hidden content!
#include<stdio.h>
#include<string.h>
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Hidden content!
#include<stdio.h>
#include<string.h>
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/usr/lib/gcc/x86_64-linux-gnu/6/../../../x86_64-linux-gnu/Scrt1.o: In function `_start':
(.text+0x20): undefined reference to `main'
collect2: error: ld returned 1 exit status
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:12:10: error: 'i' undeclared (first use in this function)
         (i=0;i<strlen(string1);i++)
          ^
prog.c:12:10: note: each undeclared identifier is reported only once for each function it appears in
prog.c:14:6: error: 'arr' undeclared (first use in this function)
     {arr[i]+=string1[strlen(string1) - 1 - i] - 48;}
      ^~~
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s",&string1);
             ^
prog.c:11:13: warning: format '%s' expects argument of type 'char *', but argument 2 has type 'char (*)[50]' [-Wformat=]
     scanf("%s",&string2);
             ^
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:14:35: error: expected ';' before ')' token
         (i=0,i<strlen(string1),i++)
                                   ^
prog.c:14:35: error: expected expression before ')' token
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
commented by (4.3k points)
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