1-4 Exercise 1: String compare function

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Each string will have two strings (string A and string B), each sub-string has 5 characters. 

Write a program with a function compare(string A, string B) for comparison

輸入兩個字串(string A, string B), 每個字串有五個字元

寫一個compare(string A, string B)函數。不能用字串函式庫

If String A == String B returns 0

If string A> string B returns 1

If string A <string B returns -1

Do not use string libraries

Example input:

gamesbegin

Example output: (because g>b => 1)

1

Example input:

iamigiates

Example output: (because m<t => -1)

-1

 Example input:

111qq111qq

Example output:

0

Remember: You may correct the cases, but your code always be revised! 

[Exercise] Coding (C) - asked in Chapter 13: Strings by (5.2k points)
ID: 40713 - Available when: 2018-01-04 18:00 - Due to: Unlimited
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53 Answers

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#include<stdio.h>
char A[5],B[5];


int compare(char A[5], char B[5])
{
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int main()
{
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}
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#include <stdio.h>
#include <ctype.h>

int compare(char A[],char B[])
{
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}
int main()
{
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}
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Hidden content!
#include<stdio.h>
#include<string.h>
char d[5],f[5];
int d_total=0,f_total=0,i;

main()
{
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}
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prog.c:6:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main()
 ^~~~
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Hidden content!
#include<stdio.h>
char A[5],B[5];
int a_sum=0,b_sum=0,i,r;

main()
{
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}
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prog.c:5:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main()
 ^~~~
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Hidden content!
#include<stdio.h>
#include<string.h>
char d[5],f[5];
int d_total=0,f_total=0,i;

main()
{
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}
answered by (-167 points)
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prog.c:6:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main()
 ^~~~
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Hidden content!
#include<stdio.h>
char A[5],B[5];
int a_sum=0,b_sum=0,i;

main()
{
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    {
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    }
}
answered by (-336 points)
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prog.c:5:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main()
 ^~~~
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Hidden content!
#include<stdio.h>
char a[5],b[5];
int a_sum=0,b_sum=0,i;

compare(string A, string B)
{
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}
answered by (-336 points)
0 0
prog.c:5:9: error: unknown type name 'string'
 compare(string A, string B)
         ^~~~~~
prog.c:5:19: error: unknown type name 'string'
 compare(string A, string B)
                   ^~~~~~
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Hidden content!
#include<stdio.h>
char A[5],B[5];
int a_sum=0,b_sum=0,i;

main()
{
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    {
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    }
}
answered by (-336 points)
0 1
prog.c:5:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main()
 ^~~~
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Hidden content!
#include<stdio.h>
char A[5],B[5];
int a_sum=0,b_sum=0,i;

main()
{
** * *   * * *** * **  *   *****  **** * *
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* *       ***  ** ** *** ***
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* *   ***** *   **  *    *  *
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    {
*  * ******  * * ** **   * *  * *** ****  *   *  ***  -1
    }
}
answered by (-336 points)
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prog.c:5:1: warning: return type defaults to 'int' [-Wimplicit-int]
 main()
 ^~~~
prog.c: In function 'main':
prog.c:23:8: error: 'returns' undeclared (first use in this function)
        returns 1
        ^~~~~~~
prog.c:23:8: note: each undeclared identifier is reported only once for each function it appears in
prog.c:23:16: error: expected ';' before numeric constant
        returns 1
                ^
prog.c:27:16: error: expected ';' before numeric constant
        returns 0
                ^
prog.c:32:5: error: expected ';' before '}' token
     }
     ^
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Hidden content!
#include<stdio.h>

int compare(char A[], char B[]) {
 ** *  ****  * *     *     *   * i;
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*  * * ** *        ** * * ** ***   *     *** *** *
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}

int main() {
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    }
 ** *    *******  * *****  * ** ****   **** ** ***  ** compare(A, B));
}
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prog.c: In function 'main':
prog.c:7:18: warning: implicit declaration of function 'compare' [-Wimplicit-function-declaration]
     printf("%d", compare(A, B));
                  ^~~~~~~
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Case 1: Wrong output
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Case 3: Correct output
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