12-28 Exercise 2: Prints a table showing how many time each digit appears

0 like 0 dislike
4.9k views

Write a program that ask the user to input a serial character (max 1000). Prints a table showing how many time each digit appears in the number. You should see 'A' and 'a' as the same.

寫一個程式 求使用者輸入一字串(最大1000) 輸入字母出現的次數 (A跟a算一樣)

Example input

Write a program that ask the user to input a serial character. Prints a table showing how many time each digit appears in the number. You should see 'A' and 'a' as the same.

Example output

A 19
B 2
C 3
D 3
E 15
F 0
G 3
H 9
I 9
J 0
K 1
L 3
M 5
N 7
O 6
P 5
Q 0
R 10
S 10
T 13
U 5
V 0
W 3
X 0
Y 2
Z 0

 

[Exercise] Coding (C) - asked in Chapter 8: Arrays by (5.2k points)
ID: 39985 - Available when: Unlimited - Due to: Unlimited
edited by | 4.9k views

31 Answers

0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
char string[1000];
int ii,jj;
int  *  * *   **  * * *    * *  *   * *  ** ** * ********** * **    ** *  
int main()
{
    fgets(string,1000, stdin);
*   * ***   * **  *   *****  * *  **     **
*   * **    ***   *** ** ** * ***** *  *   ****   **   * *** ** *  *  **  **   *   *
* *   *    **  *    *  *   *   * * *  *      **   **** *  ***  *     *   *  *       
****** ***** * * * * *    *   ***    ****   *** *  * * ** ** *  ** *  **  * * ***  *
*  ** *    **** * * * *     *** ****  * *  ****   ******* ****    *  *  *   ****
 ** ** *  ** ** *  *** * *** **   *    **  *****  ** *   *** *  * *** **       * 
 * ***  **  ** *** ** * *  *  ** * ***** ** * **** * *  * ***  *   ** *** ** * **
****** * ** **  ** ** * *  *   *   ***    **   ** * ***  ** * *     **
* *  **   ***** **  ****  *** *  ** ***** ***  * * *   ****  * ** ** *   *   **
****     ***    *********   *   *  * * ** *  *  **  *   ***    * **  
* ********** **** ***  **  *  * ***  ** **    ** ** * * *  ********  ** **  * *  *
** ******  ****    ***  * * **** *** *** ** *  *  * ** *    *      ***** * *  *  
 **  ******** *   ******* *** * * **  **  *  * *****        *** ** * * ** * *   **** *    ** 
*  ** ***  ***  ***** * ***** **   **   *  ** *  * **** ** *** * * *** *  ** *
  **   * *   * *** *  **  *  *   ***  *** ****     ***  **  * * ****  * * * **  ** 
* * ** **  * *   * **    *** **   *  ***** *  * * * *** **** *   **   ** ***** 
  *** *   ** **  * *  ** * * ***** * ***   * *  *** *   * *  * *  * ** **  * 
***   * * ** * ** *   *  *** *  *** *** ****  *   *        ** ****** ** *   * ***
  **     * *  ** ** ** *      **  ** ** *      * ** *  ** *  *   ****   **  * *  
*  *  *** ******   * *** *******  **    * ** * * * * **  ***** * *** *  * *  * ** *
    * ** *****  * ** * * ** * * * **** *   * ** **  ** * *  * *   * * **** *  ** * 
 * *  *   *   ** ******  *    * ***   * ** **   ****    **     * ****** * *  
  *  *  **  * *** ***   * **   * ******** * * **  * ***  ***** * * **    * 
*  *****  **** *** * * **    *  **  * * ***  *  *    * ****  *   ** *   *  *** **      * 
* *  * *** * ** * **   ** * * *   * ** ***    * ** * **** * * *  ** * * *** * 
   **  ****** *   ** *  * ** ** *****   *      ******* ** ** *   ** **
* *      ****  ***  *** ***** *********   **          *** * * *   * * *****  *   * 

    }
    printf("A %d\n",a);
    printf("B %d\n",b);
** *  **      * *  *  * * * *   ****   ****   %d\n",c);
 ***      ** ** * **  ****   **  ** * %d\n",d);
*    ** **    *    *       *** *  ** * %d\n",e);
* * * **   * *       * ***** *  ** *  %d\n",f);
 *  * * * **  ****   *  **     * %d\n",g);
*     * * *** ** **   *   ** **  *  * *   * * %d\n",h);
** *** *** **  * * *     ****        %d\n",i);
* * * * ***** ***  **  *  *   *    **   %d\n",j);
**  * **  *  *  ***    ** * * ** * *  * ** %d\n",k);
  ** * ** ** **  * *    ** ** *** * **  %d\n",l);
** *       *** **  *****     * *  ** * *  %d\n",m);
***  * ***     * * *  * *  *  * **  %d\n",n);
****** * **    *   *  *   ******  * **  %d\n",o);
 * **** * ** **    ** **   * *** *****  %d\n",p);
*  *   * ** *** * ** * *  * *   *  *    %d\n",q);
  * *  *** ***  *****  *  **** **      %d\n",r);
*   * *  **    * *  * **** * * ***  *** %d\n",s);
   ***    * **   ***** ******* * *   * ** %d\n",t);
 *  ***** *    ** ***  * *  *     * %d\n",u);
   ***     **    ***    * ***  *   **    **    %d\n",v);
    printf("W %d\n",w);
    printf("X %d\n",x);
    printf("Y %d\n",y);
  **      *     *** ** *   ***** **   ** * ***** %d",z);

    return 0;
}
answered by (-108 points)
0 0
Case 0: Correct output
Case 1: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <stdlib.h>
char string[1000];
int ii,jj;
int * **    * *         **    ** *   * *** * * *  *  ****** ** * ** *   
int main()
{
    fgets(string,1000, stdin);
   * **   *** ***   **  * * * * ** *******
** * **** * *** *  ***    **  *****   *  *** ***  * * ** *  *****  *    **  ** *
 **** * ** *   ** * *  ** *******   ***   * **   *  *  *** *   *  *  **  **   **** *
 *  ** * * * *  * ** * * *  * * **  *** * *   *   **  **    *    ** *  **
  *** **  *  *     *     * **  *   ****  ***** ** *  * *  *   *  * ** ** *
  *    *******  ***  ** *   * * * ** * **  **** **  * *  *  * ***    *    **
   * **  **** * *   ****   ** *    * ***  **   *  *  *  *    * ** **  * ** *  
    *  ***   ** ***** *** **** ***** *** *  ** * *** * *  *   ** ******  ** 
   *     **   **  * * ***   **   *     * *  ** * **    *****  *   * ** *  **   **** ***
  **** *** ***** **** * **     *** *****   **  *** *** * *     ** *   **     
 ********* **        * * * ** *  ** * * *  * **   * **       ***  * *** ** ****  *
  **  ****   ** ****  *    *   **** * *  *        * ***    ** *    * *   *
**    ****    *  ** *    * *   *  * * ***       * * *    * ** * ***   *** *      *  
 * **   *   * **** ****** ****  * ***   * * ******  ***** **    * * * ** ***
  ****   *  ** ** ** *   * ** ** **  ** *  ** *  **  *   * ** **** **  * * ****  
  ****   *  * **    **   ***   *****    *   **   * *  ***  ****** **      **
*   *    **   *   *  **  * **** *  *  * *  **  * ** *        * **  * * * * * * *  *
***   *** * * *  *  *  ***** **    * ***   ****   **  **  *   **** **  *   * * 
      *** *  *****  ***  *    ***** **  * * *  *  **    *       ****    *    ** * *  *  *
*   *   ***   **  *  **  **  ** *  *  *  **   * * ***  *******   **   ** *   ** 
* *  * *    * **** *** *  *** *  * * *  *   * *   ***  **  ** ****      ** **  * * *
 *****   ****   * **   ****      *** ** *  **** *** * * **  **     *** ******   *   ** *
    **             ***** *  * * * *  **   *********     **   **    ** ** 
****  **** * * *  **  *** *   * * ** ***    * ***  *    *  ** ** **  * *** *
 ***** *     ****  *  ** ** ****     ** ** * *   * ****  * **    *   
* **   ** ***   **     *** ***  * * ** * *****   ** **     **  *** ** * ** ** *  *   **
  * **  ****** * **   * *    ***     ** * *    **** *      *  * *** *** **  

    }
    printf("A %d\n",a);
    printf("B %d\n",b);
****  ***** *  *   * * **   ***  **  *   * %d\n",c);
  ***  *     * **   *   ****   * * ***  %d\n",d);
*** ** ***  * ** * ****  *    * * *  %d\n",e);
*** *** ****  **      ***      *   **  %d\n",f);
*   ** **** ** **    *****    *  * %d\n",g);
* * *  ** *****    * * *  ****  *   * %d\n",h);
*    ** * * *       * * ***  ** *  ****** %d\n",i);
 * * **  *  ********  ***  ***        %d\n",j);
* **** **      *   ****    *  %d\n",k);
 * *  *           **   **   ******* ***  ***    %d\n",l);
 ***** *      *   *   ******  *  *** %d\n",m);
    *     ** *  ***  *  ****    **** %d\n",n);
* *   ** *** ***  *   ** *   *  %d\n",o);
* *  * ****   *   * * *  *    * **  %d\n",p);
  * ******  *******   ** **    *** ** ***** %d\n",q);
   *  **** ***  * * *   ** ** **  ****   %d\n",r);
   *  ** *  **     **  *   *** * *** * * *** %d\n",s);
 *  ******     *    * ***** * ** * * * * %d\n",t);
** *  **  * ******   *   *  ***** * * * *** %d\n",u);
** *  *    * *  * ** * ** **  ** ** %d\n",v);
    printf("W %d\n",w);
    printf("X %d\n",x);
    printf("Y %d\n",y);
 ** *  ****  * *  * * * *  ** **   %d",z);

    return 0;
}
answered by (-258 points)
0 0
Case 0: Correct output
Case 1: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
# include <stdio.h>
# include <string.h>

int main()
{
*  *  **  *     * * ** *   *    a[1000];

    **   * *  * * ** ***       * * *** **** *

  * * * * * * *  **  * *    letter;

**** **     * * **        **  * *  **   ***   **    
    {
  ***   *    * * *     **   *  **  *  *  **   *  * **** * **  *   k,count=0;
    *   *   *     * * *    *  ***  * *   * *** ****    **     ** *  
  ** *  *     *** *   **  ** * *  * *********   ***   **
   ***    ***  *     ** **  ** ***  **  *   *  ** ** * ** *       * ***  * ****   *  *  **  ***    * *
  ** * ***  *** **    * *  ****  * * ***   **** *   * * **  **  *  * *  * ***** * **  **
   * ** * **    ** ****** * **   **** **  * **   ** **** *

***  ********  *  ****     **     ** *  * * * **  **** ** **    
 ** * **** * ** *  * ***** ***  * *    ***  * * * *****           * **   %d\n",letter,count);
   * *   ***   *  *    * *   *** * *  * * **  * ***   ** *
  *  ***  *  **** ***  *  ***        ****   **  ****** **** ** * %d",letter,count);
    }

 *    * *   **    *   *  *** **  0;
}
answered by (-16 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <string.h>
int main(void)
{
**  ** *** *********** *    *  alp[26]={0},i,k;
** *  * ** *  *      **** ***     *   ***   *** *  *** * * *  ** * ***    * *   * ***** *  ** **
*  **       *   * *       * * * ****        *   **    **  *    *  ***  ** **  * *    * ** * * ** **  ****
** *    * *  **   ** * *    * *  str[1000];
**** **** *   *  **** *** ** ***   * ***   * * *
  **       ** ** **   **  *   n= strlen(str);
  * * ** *  *  **  *  *** ** **  *   
    {
*  * *  **   **  *   * * *  **    *     ** *** * *** **  ** ****  * 
    * *** *   **     *  ***  * ** *    * *** * *      *
 ***  * * ***  **   **  * *  *  *  * ** ********  * *   **   ******    * ***  * * * **  (str[i]==cap[k] || str[i]==sm[k])
***   * * ***      ***  ** * *   *** * *  * *   ***  **** **  *      ** *   * * *     **   ** **  **** *    *****
 *  * ***  *  **** **           *   *  ** * **  
    }
 **  *       * ** ** **   *  **  * ***  *  * ******  
    {
   **     ** ***   *     *** **   * * * ** ** ** * *  * ** * *** %d",cap[i],alp[i]);
*   ** ***  *********  ** *   ** *** ****   **** ***  ** *   *      **      ***  *     * * * *  
* ** *       ****** **    *** * ** * * *  * *  ** *   *** **    **  * *** *    *  * ***** **  ***   **    *    * **   *   * *  *** **
    }
* ** * ***     ***   ** *   * **  0;
}
answered by (-304 points)
0 0
Case 0: Correct output
Case 1: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
** * * *  * **    **
 *  * * *  ** ***    
*** ** ** **  **** * *** **

int main()
{
char a[1000];
 **   *  *  
int len = *** ****
int e[26] = {0},i,j;
for(i = 0 ; i * *  len ; i++)
{
 **   ** **** *  *     ** *    = 0 ; j < 26 ;j++)
* * ***** * *  *** ***    
* ** *  ** *     **     * **   **   *  **  ***  ** ** **   *   == a[i] || 'A'+j == a[i])
*** ** *  * **   **    ***  * ***  *   **  ***   * *  *   * **  ***   *   * *  *
**  ** *   ** ****   *** * * 
}
for(j = 0 ; j *** ** 26 ; j++)
{
**   **  * ** *     **   *   * == 25)
 **** * **** ** ** *       * ***  ** ** * ****     *  **      *        *  *    * * **  **
 ** *  *   *  **  * * *      
* *  *  *    ** *  * *  *** * ** *    *  * ***    **   *     * *** *  *    ***
}
 *  * *   ***   * *** **  ** 0;
}
answered by (-127 points)
0 0
Case 0: Correct output
Case 1: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
# include <stdio.h>
# include <string.h>
# include <ctype.h>
int main(void)
{
*  *     * *  *** * * *** * ** str[1000];
*****  ****  **********    *  i,count[26]={0};
 * **    *  ***  ****     ***  *  * *     * 
*  * ** * ****    **** ** ****  **   *****  *  *** 
     **   * **** * *** * 
****     ***   **   **     * *** * **   ** **** *   *** *   *** ***  ** * * ***   ** *   * **
***    * *    * *   **  **    ** *    * * *       *  * **  *****    *    *   * ** *  * *****  *
***    **          * * *         ** *    * * * * **   if(str[i]>='a' && str[i]<='z')
  ***** * *      * * * * ** ** *  * * **   ***** ***    * *   **  * ******    * *** * *  *** ******  *   * ******  
  *** * ** * ** *  ***  *     *
*  **** ****   *       *** * * ** 
  *********    *  ** **     
   ** *   ****   *  *  **  ****      ** * *** * * *   *   **    ******   ** * %d",i+'A',count[i]);
* * *****    *  * **  ** *  * *** * ** *  *   **     **     ***  *
*** *** ***  *   *** ** **   **    * ** *** *    * * ** * *  * **  **  **  **     ****  ****  **    ** *
    }
***   ** * ** * *    ** *  ** 0;
}
answered by (-281 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
You have extra line at the end of ouput
commented by (5.2k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
-----------Re-judge-----------
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
   *     *  * *   * **
int *    
{
*  *  ** ****   char ** **
***    ****  int **   *  
*  *  *   * ** *       ****  * *
** * *     ** *** int i;
** *     *      *** **        ***  * *  *   ** **** **
**  *    {
*    *   * **  * * **  **  *    ****** *   *  **  *    ****  *  ||   **   *  ***     * ** ** ***   * ***  *  **** *  ')
 * * **         **** {
 * ** *     ** * * ***  *  *     ** * *** * * **   * * *     *
*   **  **  *** *  **  * **     ******* * *  * {
***  ** ****     ***   * ** * *  * * *      **        * *   **  *** **
  **         * *    }
** *           else
***      *   *  **   *    **  **    ** * {
   ***  ****   *  * * *   *    *    *** * ** ***   ***   **      ** 
  ** * ** *** * ** **     * *   ******  ***  **  }
 *** *  * **    *** *  *  **  * }
*   ***   * *   }
 ** *   * * ** int j;
  * **      *  * *   *** **  * *
* * * ** * ** {
 *  **         *   ** *** ** *** ***** *  ** **  * *** *** **
***  * ***      * ** *   * ** if(j!=25)
 ****  ****** * ***  **    * * *    ******* ** *    * 
******* * **** }
* ****  *    * return 0;
}
answered by (-249 points)
edited by
0 0
prog.c: In function 'main':
prog.c:7:2: warning: 'gets' is deprecated [-Wdeprecated-declarations]
  gets(word);
  ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccmUJkGw.o: In function `main':
prog.c:(.text+0x4f): warning: the `gets' function is dangerous and should not be used.
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include <stdio.h>
#include <ctype.h>
#include <string.h>
int main()
{
***  *   * * *    *  ** str[1000];
* **  * ************   **  * i,count[26]={0};
 *  *  *   *   *  * *  *     *** *****  * *
* * ****   ***  * *  ** * *     *****    **
 *** *  * ***   *      * *  
 ** *  * ** *** ***  **** ******     ******* *     **  * (toupper(str[i])>='A' && ***     * **   ***  
*** ****** ***  * *   **   * * * ***   * *    ** **  ** * ** *  *     * **  *** *** *  **    *  
  **    *  **   *   ** **
*    *    ** * *     *  *** (i=0;i<26;i++)
  * * ***    * **  *      **
   ****** * ** **     * ***   * *   ***    *   *** **     ** **  ** * *   ****  * * *  **
** ***   ***  **   ** *** ***** *****    **  *  **  **  *** *  (i<25)
**    **** *** **     ** * *      ****  *  *****  ***  *  * * * *   **       *   * *  *  *** ******** * *   
 *  **     * **   * * ***  
 **   ****  ***  **** ** ***** *  0;
}
answered by (-249 points)
edited by
0 0
prog.c: In function 'main':
prog.c:12:19: warning: implicit declaration of function 'tolower' [-Wimplicit-function-declaration]
                 x=tolower(string[c])-'a';
                   ^~~~~~~
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
commented by (4.3k points)
0 0
prog.c: In function 'main':
prog.c:9:16: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for (i=0;i<strlen(str);i++)
                ^~~~~~
prog.c:9:16: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:16: note: include '<string.h>' or provide a declaration of 'strlen'
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
****  *   *  ** *** *
**** *  ***   ** *****  
**      **  *   * **

int main()
{
char a[1000];
 * ****  *  * 
int len =  *****  
int e[26] = {0},i,j;
for(i = 0 ; i  * *  len ; i++)
{
  *   *  * *  ** *** *  * **** = 0 ; j < 26 ;j++)
     * * ** * *  * **   **** 
** ***** * **   * ***     ***    ***** * **  *   ******  * == a[i] || 'A'+j == a[i])
  **  * * * * ****** * * * * ****       ****** * * **** ****  ** ** ****   * * ** * * * **
*   **  *   * *   *** *  ** **
}
for(j = 0 ; j  ** *  26 ; j++)
{
**   *   **    * **** * * **    == 25)
   * **   *  * * *          * *  * *  *   ** *  **  **    **    ***** *    *  * 
*  **** * *  *  ******** ** 
**  ***** *  **     **  * ***    ******* * ** ** ** **    *   ** * ** **   **** **  * * 
}
 * * *  ** **   **   ***   * * 0;
}
answered by (-255 points)
edited by
0 0
Case 0: Wrong output
Case 1: Wrong output
commented by (4.3k points)
0 0
Case 0: Correct output
Case 1: Correct output
commented by (4.3k points)
0 like 0 dislike 
Hidden content!
#include<stdio.h>

int main()
{
 * *       ****       **  ** a[999];
*  **  ** ** ****  * *  *  *     **    *  ***     *

   * * ***    **    *   **  *  **** letter;
*   *  * *****    ***    *  ** * *  *** ** **** **** * *****
    {
**    **** * **   * ** ****   ***  **   *   * * *****  i, lettercounter=0;
  *  **  ****       *   * *     * ** ** * **   *  *  ** * ** 
  **  ** *  *  * *    ***   **  *********** **     **
 * ********* *  * **    ***      * * **** *  *  **** **  ** *    **  ** * *          || a[i]==letter+32)
* **     *    ***  * * * ***  * *   ** ***  *  *  **** * *     **  **  *  ** *   ** ** *     *     * *  ** *  ***    ** * * *
*   * *  *  ****   * *** *      *** ****  **  * ****  *  
  * * * *  *  **     *** ** ***   **    ***    %d\n",letter,lettercounter);
    }

* * ** *  **   ** *  * *** ***    **
 ** *  * * * *****  *** i, lettercounter=0;
*  *   **** * ** **** * ** *   ** *    *
*** ****    * * *** * *****   
*   * **     ** *    *****      ****   * ***      **    ** * **  || a[i]==letter+32)
 *** *    *****  * ****    **    **** * *** * * **   * *   * * * **** * ** **** *   * ** ** * *
    }
 *   ** *  *  *   ***       *  *  * %d",letter,lettercounter);


  ****** ****** ** *  *** *     * 0;
}
answered by (-196 points)
0 0
Case 0: Correct output
Case 1: Correct output
commented by (4.3k points)
Page:
Welcome to Peer-Interaction Programming Learning System (PIPLS) LTLab, National DongHwa University
English 中文 Tiếng Việt
IP:172.70.131.134
©2016-2025

Related questions

0 like 0 dislike
102 answers
12-28 Exercise 1: Pascal triangle
[Exercise] Coding (C) - asked Dec 28, 2017 in Chapter 8: Arrays by semicolon (5.2k points)
ID: 39984 - Available when: Unlimited - Due to: Unlimited | 10.2k views
0 like 0 dislike
56 answers
11-30 Exercise 2: Rotated Array
[Exercise] Coding (C) - asked Nov 29, 2017 in Chapter 8: Arrays by semicolon (5.2k points)
ID: 34913 - Available when: 2017-11-30 18:00 - Due to: Unlimited | 5.8k views
12,783 questions
183,443 answers
172,219 comments
4,824 users