12-28 Exercise 2: Prints a table showing how many time each digit appears

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Write a program that ask the user to input a serial character (max 1000). Prints a table showing how many time each digit appears in the number. You should see 'A' and 'a' as the same.

寫一個程式 求使用者輸入一字串(最大1000) 輸入字母出現的次數 (A跟a算一樣)

Example input

Write a program that ask the user to input a serial character. Prints a table showing how many time each digit appears in the number. You should see 'A' and 'a' as the same.

Example output

A 19
B 2
C 3
D 3
E 15
F 0
G 3
H 9
I 9
J 0
K 1
L 3
M 5
N 7
O 6
P 5
Q 0
R 10
S 10
T 13
U 5
V 0
W 3
X 0
Y 2
Z 0

 

[Exercise] Coding (C) - asked in Chapter 8: Arrays by (5.2k points)
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31 Answers

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#include <stdio.h>
#include <stdlib.h>
char string[1000];
int ii,jj;
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}
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#include <stdio.h>
#include <stdlib.h>
char string[1000];
int ii,jj;
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    return 0;
}
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Hidden content!
# include <stdio.h>
# include <string.h>

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#include <stdio.h>
#include <string.h>
int main(void)
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}
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# include <stdio.h>
# include <string.h>
# include <ctype.h>
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}
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}
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prog.c: In function 'main':
prog.c:7:2: warning: 'gets' is deprecated [-Wdeprecated-declarations]
  gets(word);
  ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccmUJkGw.o: In function `main':
prog.c:(.text+0x4f): warning: the `gets' function is dangerous and should not be used.
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#include <stdio.h>
#include <ctype.h>
#include <string.h>
int main()
{
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}
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prog.c: In function 'main':
prog.c:12:19: warning: implicit declaration of function 'tolower' [-Wimplicit-function-declaration]
                 x=tolower(string[c])-'a';
                   ^~~~~~~
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prog.c: In function 'main':
prog.c:9:16: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for (i=0;i<strlen(str);i++)
                ^~~~~~
prog.c:9:16: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:16: note: include '<string.h>' or provide a declaration of 'strlen'
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int main()
{
char a[1000];
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}
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#include<stdio.h>

int main()
{
 * ***  *   **   * *     * a[999];
*  ******  **   * **   * **** ** **** ** **  * *

   ** ****  ****** **** **  * * **  letter;
**** **  * *** *     * *  **  *** ***   *** **    **  *
    {
* *    ***  * * * * *  *   * * * * * ** * ****  **  i, lettercounter=0;
 **** *   ****  *   *****  * **    ***       *  * * **    * ***  **  
 *   **  *  *** *  *  * *   * ** ** * ***  * *  **
    ** **  **      **** *    ** * *  * * * *  **   * * *    * ** ***** *  ***  *  *** **  ***  || a[i]==letter+32)
 * ****** * ****  *   ** ***** ** **  *******   * ******  * * *  ******  *  ** *      ** ***    *  * *  *****   *
****  *   ***     **** *** ***  * **** * **   *  *   *
 * ** * * *  **** * *****  ****   *** * ** %d\n",letter,lettercounter);
    }

 ***  **   * ***** *  **    *** **
 **** ** **  *   **** *  **     * i, lettercounter=0;
 *****  ** ***** **    ** *  * ** * **  ****  *
 ***    * *  **** *  * ** ***
******  *  * * ** *    * *     * ******  **     *    *       *  ** ** * || a[i]==letter+32)
  *     **** ** *   *  *** * *** *   **     **  *   **      *  **   * *   * *  *
    }
  * * *    * *   *    ** * *  * *     %d",letter,lettercounter);


 *      ***   ****** *   ** 0;
}
answered by (-196 points)
0 0
Case 0: Correct output
Case 1: Correct output
commented by (4.3k points)
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