12-28 Exercise 2: Prints a table showing how many time each digit appears

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Write a program that ask the user to input a serial character (max 1000). Prints a table showing how many time each digit appears in the number. You should see 'A' and 'a' as the same.

寫一個程式 求使用者輸入一字串(最大1000) 輸入字母出現的次數 (A跟a算一樣)

Example input

Write a program that ask the user to input a serial character. Prints a table showing how many time each digit appears in the number. You should see 'A' and 'a' as the same.

Example output

A 19
B 2
C 3
D 3
E 15
F 0
G 3
H 9
I 9
J 0
K 1
L 3
M 5
N 7
O 6
P 5
Q 0
R 10
S 10
T 13
U 5
V 0
W 3
X 0
Y 2
Z 0

 

[Exercise] Coding (C) - asked in Chapter 8: Arrays by (5.2k points)
ID: 39985 - Available when: Unlimited - Due to: Unlimited
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31 Answers

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#include <stdio.h>
#include <stdlib.h>
char string[1000];
int ii,jj;
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    return 0;
}
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#include <stdio.h>
#include <stdlib.h>
char string[1000];
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    return 0;
}
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# include <stdio.h>
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# include <string.h>
# include <ctype.h>
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prog.c: In function 'main':
prog.c:7:2: warning: 'gets' is deprecated [-Wdeprecated-declarations]
  gets(word);
  ^~~~
In file included from prog.c:1:0:
/usr/include/stdio.h:640:14: note: declared here
 extern char *gets (char *__s) __wur __attribute_deprecated__;
              ^~~~
/tmp/ccmUJkGw.o: In function `main':
prog.c:(.text+0x4f): warning: the `gets' function is dangerous and should not be used.
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#include <stdio.h>
#include <ctype.h>
#include <string.h>
int main()
{
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}
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prog.c: In function 'main':
prog.c:12:19: warning: implicit declaration of function 'tolower' [-Wimplicit-function-declaration]
                 x=tolower(string[c])-'a';
                   ^~~~~~~
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prog.c: In function 'main':
prog.c:9:16: warning: implicit declaration of function 'strlen' [-Wimplicit-function-declaration]
     for (i=0;i<strlen(str);i++)
                ^~~~~~
prog.c:9:16: warning: incompatible implicit declaration of built-in function 'strlen'
prog.c:9:16: note: include '<string.h>' or provide a declaration of 'strlen'
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int main()
{
char a[1000];
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#include<stdio.h>

int main()
{
* * **   * * *** *  *  *  * ***** a[999];
*   *  * *  * ** * *    ** *  *  * *   *   ****** 

** ***  *   * *  ** **  * *  letter;
*  *** ***    *** *** * * *** ** **   * *    *    *    *  * 
    {
   * ** ** * **      **  **  *  * ** *  * *   * ***   *  i, lettercounter=0;
**      ***  * * **    *   * *    ***         ****** * * * ***  *    *    **
  ****  * ** *  *****   *** ***  * ** *******  ****  
       * *  *     ***      ***** * *** **  ** * * *** ** ***   * *  *   * * * **** *  *  ***   || a[i]==letter+32)
 *  * *** ***** *  *    ****  * *  **  * * *  *   ******  * *   *** ****  ** *  * ***** ** ****  *   *   ******** *** * 
*  ***        * * **  *     *    *** ***  **** *** *  **
  *****  ***** * ****    *** * * *** * *  * %d\n",letter,lettercounter);
    }

* **  *   ** ** ******  *** **** *
  *** *  **     *   **  **  i, lettercounter=0;
* * * * **** *   ***    *********
       *  *   **** * * * 
 *  * * *  ****** *   * *** * ** **   * **    * ** * * **  || a[i]==letter+32)
     *  ****  **  * **   ** ** **       ** * ****  ****     * ** *   *  ********  ***  **** 
    }
  *  * *    **  *  ** *  * ** * * * *   * * * * %d",letter,lettercounter);


 ** * ***** ********** *  * **   0;
}
answered by (-196 points)
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Case 1: Correct output
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