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Please write a program that receives an input number, then decreases the input by 1 until it reaches '0'. But instead of showing '0', it will output 'zero'.

Example(template)

#include <stdio.h>
#include <stdlib.h>

int main(int argc, char *argv[]) {
	int a;                             //can be changed

	printf("Enter your input:");       // DO NOT change
	scanf("%d",&a);

    // Your conditions start from here

	return 0;
}

 

Input

Enter your input:10

Output

Enter your input:10
10987654321zero

 

** No need to put a space between numbers

[Exercise] Coding (C) - asked in Chapter 3: Branching, Looping and Functions by (5.9k points)
ID: 30222 - Available when: Unlimited - Due to: Unlimited
| 4.7k views

20 Answers

0 like 0 dislike
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answered by (153 points)
0 0
Case 0: Wrong output
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answered by (153 points)
0 0
Case 0: Wrong output
0 like 0 dislike
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100/100 answered by (183 points)
0 0
prog.c: In function 'main':
prog.c:14:21: warning: too many arguments for format [-Wformat-extra-args]
             {printf("zero",i);}
                     ^~~~~~
0 like 0 dislike
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50/100 answered by (269 points)
0 0
prog.c: In function 'main':
prog.c:16:10: warning: too many arguments for format [-Wformat-extra-args]
   printf("zero", a);
          ^~~~~~
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Hidden content!
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100/100 answered by (273 points)
0 0
Case 0: Correct output
0 like 0 dislike
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//INPUT
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//OUTPUT
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100/100 answered by (290 points)
reshown by
0 0
Case 0: Wrong output
0 like 0 dislike
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100/100 answered by (271 points)
0 0
Case 0: Wrong output
0 like 0 dislike
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50/100 answered by (252 points)
0 0
Case 0: Wrong output
0 like 0 dislike
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100/100 answered by (268 points)
0 1
Case 0: Correct output
0 like 0 dislike
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answered by (5.9k points)
0 0
Case 0: Correct output
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