10-12 Exercise: A water supply company

Question

A water supply company charges the water consumption, as follows:

a) Fixed amount of 10$.
b) For the first 30 cubic meters 0.6$/meter.
c) For the next 20 cubic meters 0.8$/meter.  
d) For the next 10 cubic meters 1$/meter.  
e) For every additional meter 1.2$/meter.   

Write a program that reads the water consumption in cubic meters and displays the bill.
寫一個輸入水的用量 輸出水費的程式

Example Input:

25

Output:

Cost: 25.00

Example Input 2:

44

Output:

Cost: 39.20

Example Input 3:
 

75

Output:

Cost: 72.00

 

Answer 1

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Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output

---

-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output

Answer 2

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#include <stdio.h>
int main()
{
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Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

Answer 3

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Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output

---

-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output

Answer 4

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Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output

---

-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output

Answer 5

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#include <stdio.h>
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Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

Answer 6

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Comments

prog.c: In function 'main':
prog.c:6:5: error: implicit declaration of function 'scanf' [-Werror=implicit-function-declaration]
     scanf("%f",&x);
     ^~~~~
prog.c:6:5: error: incompatible implicit declaration of built-in function 'scanf' [-Werror]
prog.c:6:5: note: include '<stdio.h>' or provide a declaration of 'scanf'
prog.c:9:9: error: implicit declaration of function 'printf' [-Werror=implicit-function-declaration]
         printf("Cost: %.2f",x*0.6+10);
         ^~~~~~
prog.c:9:9: error: incompatible implicit declaration of built-in function 'printf' [-Werror]
prog.c:9:9: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:13:9: error: incompatible implicit declaration of built-in function 'printf' [-Werror]
         printf("Cost: %.2f",(x-30)*0.8+28);
         ^~~~~~
prog.c:13:9: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:17:9: error: incompatible implicit declaration of built-in function 'printf' [-Werror]
         printf("Cost: %.2f",(x-50)*1+44);
         ^~~~~~
prog.c:17:9: note: include '<stdio.h>' or provide a declaration of 'printf'
prog.c:21:9: error: incompatible implicit declaration of built-in function 'printf' [-Werror]
         printf("Cost: %.2f",(x-60)*1.2+54);
         ^~~~~~
prog.c:21:9: note: include '<stdio.h>' or provide a declaration of 'printf'
cc1: all warnings being treated as errors

Answer 7

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Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output

---

-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output

Answer 8

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}

Comments

Case 0: Correct output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

Answer 9

Hidden content!
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Comments

Case 0: Wrong output
Case 1: Wrong output
Case 2: Wrong output
Case 3: Wrong output
Case 4: Wrong output

Answer 10

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#include <stdio.h>

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Comments

Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output

---

-----------Re-judge-----------
Case 0: Correct output
Case 1: Correct output
Case 2: Correct output
Case 3: Correct output
Case 4: Correct output